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This section includes 657 Mcqs, each offering curated multiple-choice questions to sharpen your Testing Subject knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
The value of(3+22–√)−3+(3−22–√)−3=?The value of(3+22)−3+(3−22)−3=? |
| A. | 189 |
| B. | 180 |
| C. | 108 |
| D. | 198 |
| Answer» B. 180 | |
| 2. |
The value of(256)54 is = ?The value of(256)54 is = ? |
| A. | 512 |
| B. | 984 |
| C. | 1024 |
| D. | 1032 |
| Answer» B. 984 | |
| 3. |
The value of1(12−140−−−√)−−−−−−−−−−√−1(8−60−−√)−−−−−−−−−√−2(10+84−−√)−−−−−−−−−−√=is?The value of1(12−140)−1(8−60)−2(10+84)=is? |
| A. | 0 |
| B. | 1 |
| C. | 2 |
| D. | 3 |
| Answer» B. 1 | |
| 4. |
If 310 ÷ 272 = 92 × 3n then the value of n is = ? |
| A. | 10 |
| B. | 12 |
| C. | 15 |
| D. | 30 |
| Answer» B. 12 | |
| 5. |
(3)8 × (3)4 = ? |
| A. | (27)3 |
| B. | (27)5 |
| C. | (729)2 |
| D. | (729)3 |
| Answer» B. (27)5 | |
| 6. |
16×329×27×81=?16×329×27×81=? |
| A. | (2/3)9 |
| B. | (2/3)11 |
| C. | (2/3)2 |
| D. | (2/3)13 |
| Answer» B. (2/3)11 | |
| 7. |
Simplify:(1.5)3+(4.7)3+(3.8)3−3×1.5×4.7×3.8(1.5)2+(4.7)2+(3.8)2−1.5×4.7−4.7×3.8−3.8×1.5=?Simplify:(1.5)3+(4.7)3+(3.8)3−3×1.5×4.7×3.8(1.5)2+(4.7)2+(3.8)2−1.5×4.7−4.7×3.8−3.8×1.5=? |
| A. | 0 |
| B. | 1 |
| C. | 10 |
| D. | 30 |
| Answer» B. 1 | |
| 8. |
343×49216×16×81=?343×49216×16×81=? |
| A. | 75/67 |
| B. | 75/68 |
| C. | 76/67 |
| D. | 74/68 |
| Answer» B. 75/68 | |
| 9. |
The value of (12−−√−8–√)(3–√+2–√)5+24−−√−−−−−−−−−−−−−−−−−−−−√is = ?The value of (12−8)(3+2)5+24is = ? |
| A. | √6 - √2 |
| B. | √6 + √2 |
| C. | √6 - 2 |
| D. | 2 - √6 |
| Answer» B. √6 + √2 | |
| 10. |
(√8 - √4 - √2) Equals to = ? |
| A. | 2 - √2 |
| B. | √2 - 2 |
| C. | 2 |
| D. | -2 |
| Answer» B. √2 - 2 | |
| 11. |
Ifx=3+22–√,thenthevalueof(x−−√−1x−−√)is:Ifx=3+22,thenthevalueof(x−1x)is: |
| A. | 1 |
| B. | 2 |
| C. | 2√2 |
| D. | 3√3 |
| Answer» B. 2 | |
| 12. |
(64)−23×(14)−2is equal to ?(64)−23×(14)−2is equal to ? |
| A. | 1 |
| B. | 2 |
| C. | 1/2 |
| D. | 1/16 |
| Answer» B. 2 | |
| 13. |
[43×54]÷45=?[43×54]÷45=? |
| A. | 29.0825 |
| B. | 30.0925 |
| C. | 35.6015 |
| D. | 39.0625 |
| Answer» B. 30.0925 | |
| 14. |
(2+3–√2−3–√+2−3–√2+3–√+3–√−13–√+1)Simplifies to:(2+32−3+2−32+3+3−13+1)Simplifies to: |
| A. | 2 - √3 |
| B. | 2 + √3 |
| C. | 16 - √3 |
| D. | 40 - √3 |
| Answer» B. 2 + √3 | |
| 15. |
Simplify:⎛⎝32+3√−22−3√2−53–√⎞⎠=?Simplify:(32+3−22−32−53)=? |
| A. | 1/2 - 5√3 |
| B. | 2 - 5√3 |
| C. | 1 |
| D. | 0 |
| Answer» B. 2 - 5√3 | |
| 16. |
(243)n/5×32n+19n×3n−1=?(243)n/5×32n+19n×3n−1=? |
| A. | 1 |
| B. | 2 |
| C. | 9 |
| D. | 3n |
| Answer» B. 2 | |
| 17. |
If(ab)x−1=(ba)x−3,thenthevalueofxisIf(ab)x−1=(ba)x−3,thenthevalueofxis |
| A. | 1/2 |
| B. | 1 |
| C. | 2 |
| D. | 7/2 |
| Answer» B. 1 | |
| 18. |
11+a(n−m)+11+a(m−n)=?11+a(n−m)+11+a(m−n)=? |
| A. | 0 |
| B. | 1/2 |
| C. | 1 |
| D. | am + n |
| Answer» B. 1/2 | |
| 19. |
11+x(b−a)+x(c−a)+11+x(a−b)+x(c−b)+11+x(b−c)+x(a−c)=?11+x(b−a)+x(c−a)+11+x(a−b)+x(c−b)+11+x(b−c)+x(a−c)=? |
| A. | 0 |
| B. | 1 |
| C. | xa - b - c |
| D. | None of these |
| Answer» B. 1 | |
| 20. |
0.0169×?−−−−−−−−√=1.30.0169×?=1.3 |
| A. | 10 |
| B. | 100 |
| C. | 1000 |
| D. | None of these |
| Answer» B. 100 | |
| 21. |
(625−−−√11×1425−−√×11196−−−√)(62511×1425×11196) is equal to : |
| A. | 5 |
| B. | 6 |
| C. | 8 |
| D. | 11 |
| Answer» B. 6 | |
| 22. |
(3–√−13–√)2simplifiesto:(3−13)2simplifiesto: |
| A. | 34343434343434343434334434 |
| B. | 43–√4343–√4343–√43–√43–√43–√43–√43–√443–√3–√3–√3–√3–√333––√√43 |
| C. | 43434343434343434343443343 |
| D. | None of these |
| Answer» B. 43–√4343–√4343–√43–√43–√43–√43–√43–√443–√3–√3–√3–√3–√333––√√43 | |
| 23. |
If 5–√=2.236,5=2.236, then the value of 5–√252 −− 105–√105 ++ 125−−−√125 is equal to : |
| A. | 5.59 |
| B. | 7.826 |
| C. | 8.944 |
| D. | 10.062 |
| Answer» B. 7.826 | |
| 24. |
If 35–√+125−−−√35+125 = 17.88, then what will be the value of 80−−√+65–√?80+65? |
| A. | 13.41 |
| B. | 20.46 |
| C. | 21.66 |
| D. | 22.35 |
| Answer» B. 20.46 | |
| 25. |
If a = 0.1039, then the value of 4a2−4a+1−−−−−−−−−−√+3a4a2−4a+1+3a is: |
| A. | 0.1039 |
| B. | 0.2078 |
| C. | 1.1039 |
| D. | 2.1039 |
| Answer» B. 0.2078 | |
| 26. |
If x=3–√+13–√−1x=3+13−1 and y=3–√−13–√+1,y=3−13+1, then the value of (x2+y2)(x2+y2) is? |
| A. | 10 |
| B. | 13 |
| C. | 14 |
| D. | 15 |
| Answer» B. 13 | |
| 27. |
What should come in place of both x in the equation x128−−−√=162−−−√xx128=162x |
| A. | 12 |
| B. | 14 |
| C. | 144 |
| D. | 196 |
| Answer» B. 14 | |
| 28. |
67 × 119 + 17 - 27 ÷ 259 = ? |
| A. | -13 |
| B. | -3 |
| C. | 4 |
| D. | 7 |
| Answer» B. -3 | |
| 29. |
Solve 14 × 627 ÷ √(1089) = (?)3 + 141 |
| A. | 5√5 |
| B. | (125)2 |
| C. | 25 |
| D. | 5 |
| Answer» B. (125)2 | |
| 30. |
(0.73)3+(0.27)3(0.73)2+(0.27)2−0.73×0.27=?(0.73)3+(0.27)3(0.73)2+(0.27)2−0.73×0.27=? |
| A. | 0.27 |
| B. | 0.4087 |
| C. | 0.73 |
| D. | 1 |
| Answer» B. 0.4087 | |
| 31. |
Simplify : −2197−−−−−√3×−125−−−−√3÷27512−−−−√3=?−21973×−1253÷275123=? |
| A. | 4927492749274927492749274927492749274927492492492492774927 |
| B. | 5203520352035203520352035203520352035203520520520520335203 |
| C. | 5547554755475547554755475547554755475547554554554554775547 |
| D. | 5715571557155715571557155715571557155715571571571571555715 |
| Answer» B. 5203520352035203520352035203520352035203520520520520335203 | |
| 32. |
(a−b)2−(a+b)2−4a = xy(a−b)2−(a+b)2−4a = xy On simplifying the given equations, which of the following equations will be obtained ? |
| A. | xy = b |
| B. | bx = y |
| C. | ab = x |
| D. | yb = x |
| Answer» E. | |
| 33. |
If x + y = 2a, then the value ofnax−a+ay−ais = ?ax−a+ay−ais = ? |
| A. | 2 |
| B. | 0 |
| C. | -1 |
| D. | 1 |
| Answer» B. 0 | |
| 34. |
If x + y + z = 0, then x3 + y3 + z3 + 3xyz is equal to = ? |
| A. | 0 |
| B. | 6xyz |
| C. | 12xyz |
| D. | xyz |
| Answer» B. 6xyz | |
| 35. |
{(64−38)×4}÷3=?{(64−38)×4}÷3=? |
| A. | 4 |
| B. | 1 |
| C. | 8 |
| D. | 2 |
| Answer» B. 1 | |
| 36. |
Solve 145+20−280÷25=?145+20−280÷25=? |
| A. | 815815815815815815815815815151155815 |
| B. | 912912912912912912912912912121122912 |
| C. | 1112111211121112111211121112111211121211221112 |
| D. | 1035103510351035103510351035103510353533551035 |
| Answer» B. 912912912912912912912912912121122912 | |
| 37. |
14×627÷1089−−−−√=(?)3+14114×627÷1089=(?)3+141 |
| A. | 5√5 |
| B. | (125)2 |
| C. | 25 |
| D. | 4 |
| Answer» B. (125)2 | |
| 38. |
If x+1x−1 = abx+1x−1 = ab and 1−y1+y = ba,1−y1+y = ba, then the value of x−y1+xyx−y1+xy = ? |
| A. | 2aba2−b22aba2−b22aba2−b22aba2−b22aba2−b22aba2−b22aba2−b22aba2−b22aba2−b22aba2−b22ab2ab2ab2aba2−b2a2−b2a2−b2a2a2a2a2aa22−b2b2b2b2bb222aba2−b2 |
| B. | a2−b22aba2−b22aba2−b22aba2−b22aba2−b22aba2−b22aba2−b22aba2−b22aba2−b22aba2−b22aba2−b2a2−b2a2−b2a2a2a2a2aa22−b2b2b2b2bb222ab2ab2ab2aba2−b22ab |
| C. | a2+b22aba2+b22aba2+b22aba2+b22aba2+b22aba2+b22aba2+b22aba2+b22aba2+b22aba2+b22aba2+b2a2+b2a2+b2a2a2a2a2aa22+b2b2b2b2bb222ab2ab2ab2aba2+b22ab |
| D. | a2−b2aba2−b2aba2−b2aba2−b2aba2−b2aba2−b2aba2−b2aba2−b2aba2−b2aba2−b2aba2−b2a2−b2a2−b2a2a2a2a2aa22−b2b2b2b2bb22ababababa2−b2ab |
| Answer» B. a2−b22aba2−b22aba2−b22aba2−b22aba2−b22aba2−b22aba2−b22aba2−b22aba2−b22aba2−b22aba2−b2a2−b2a2−b2a2a2a2a2aa22−b2b2b2b2bb222ab2ab2ab2aba2−b22ab | |
| 39. |
20+8×0.520−? = 1220+8×0.520−? = 12 Find the value in place of (?) |
| A. | 2 |
| B. | 8 |
| C. | 18 |
| D. | None of these |
| Answer» B. 8 | |
| 40. |
If (x+1x) = 2,(x+1x) = 2, then (x−1x)(x−1x) is equal to = ? |
| A. | 0 |
| B. | 1 |
| C. | 2 |
| D. | 5 |
| Answer» B. 1 | |
| 41. |
If (x+1x) = 13−−√,(x+1x) = 13, then the value of (x3+1x3)(x3+1x3) is = ? |
| A. | 26 |
| B. | 27 |
| C. | 30 |
| D. | 36 |
| Answer» B. 27 | |
| 42. |
If (x−1x) = 21−−√,(x−1x) = 21, then the value of (x2+1x2)(x+1x)(x2+1x2)(x+1x) is = ? |
| A. | 42 |
| B. | 63 |
| C. | 115 |
| D. | 120 |
| Answer» B. 63 | |
| 43. |
If (4b2+1b2) = 2,(4b2+1b2) = 2, then (8b3+1b3)(8b3+1b3) = ? |
| A. | 0 |
| B. | 1 |
| C. | 2 |
| D. | 5 |
| Answer» B. 1 | |
| 44. |
On simplification the value ofn1−11+2–√ + 11−2–√is = ?1−11+2 + 11−2is = ? |
| A. | 22–√−122−122–√−122−122–√−122–√−122–√−122–√−122–√2–√222––√√−122−1 |
| B. | 1−22–√1−221−22–√1−221−22–√1−22–√1−22–√1−22–√1−22–√2–√222––√√1−22 |
| C. | 1−2–√1−21−2–√1−21−2–√1−2–√1−2–√1−2–√1−2–√2–√222––√√1−2 |
| D. | −22–√−22−22–√−22−22–√−22–√−22–√−22–√−22–√2–√222––√√−22 |
| Answer» B. 1−22–√1−221−22–√1−221−22–√1−22–√1−22–√1−22–√1−22–√2–√222––√√1−22 | |
| 45. |
The simplest value of (19–√−8–√−18–√−7–√+17–√−6–√−16–√−5–√)(19–√−8–√−18–√−7–√+17–√−6–√−16–√−5–√)=?(19−8−18−7+17−6−16−5)(19−8−18−7+17−6−16−5)=? |
| A. | 3−5–√3−53−5–√3−53−5–√3−5–√3−5–√3−5–√3−5–√5–√555––√√3−5 |
| B. | 3 |
| C. | 5–√55–√55–√5–√5–√5–√5–√5–√555––√√5 |
| D. | 5–√−35−35–√−35−35–√−35–√−35–√−35–√−35–√5–√555––√√−35−3 |
| Answer» B. 3 | |
| 46. |
If (a+1a)=6,(a+1a)=6, then (a4+1a4)(a4+1a4) = ? |
| A. | 1154 |
| B. | 1158 |
| C. | 1160 |
| D. | 1164 |
| Answer» E. | |
| 47. |
Let 0 u003c x u003c 1, then the correct inequality is = ? |
| A. | xu003cx−−√u003cx2xu003cxu003cx2xu003cx−−√u003cx2xu003cxu003cx2xu003cx−−√u003cx2xu003cx−−√u003cx2xu003cx−−√u003cx2xu003cx−−√u003cx2xu003cx−−√x−−√xxx−−−−−−√√u003cx2x2x2x2xx22xu003cxu003cx2 |
| B. | x−−√u003cxu003cx2xu003cxu003cx2x−−√u003cxu003cx2xu003cxu003cx2x−−√u003cxu003cx2x−−√u003cxu003cx2x−−√u003cxu003cx2x−−√u003cxu003cx2x−−√x−−√xxx−−−−−−√√u003cxu003cx2x2x2x2xx22xu003cxu003cx2 |
| C. | x2u003cxu003cx−−√x2u003cxu003cxx2u003cxu003cx−−√x2u003cxu003cxx2u003cxu003cx−−√x2u003cxu003cx−−√x2u003cxu003cx−−√x2u003cxu003cx−−√x2x2x2x2xx22u003cxu003cx−−√x−−√xxx−−−−−−√√x2u003cxu003cx |
| D. | x−−√u003cx2u003cxxu003cx2u003cxx−−√u003cx2u003cxxu003cx2u003cxx−−√u003cx2u003cxx−−√u003cx2u003cxx−−√u003cx2u003cxx−−√u003cx2u003cxx−−√x−−√xxx−−−−−−√√u003cx2x2x2x2xx22u003cxxu003cx2u003cx |
| Answer» B. x−−√u003cxu003cx2xu003cxu003cx2x−−√u003cxu003cx2xu003cxu003cx2x−−√u003cxu003cx2x−−√u003cxu003cx2x−−√u003cxu003cx2x−−√u003cxu003cx2x−−√x−−√xxx−−−−−−√√u003cxu003cx2x2x2x2xx22xu003cxu003cx2 | |
| 48. |
If x=3–√ + 2–√,x=3 + 2, then the value of x3−1x3x3−1x3 is? |
| A. | 102–√102102–√102102–√102–√102–√102–√102–√2–√222––√√102 |
| B. | 142–√142142–√142142–√142–√142–√142–√142–√2–√222––√√142 |
| C. | 222–√222222–√222222–√222–√222–√222–√222–√2–√222––√√222 |
| D. | 82–√8282–√8282–√82–√82–√82–√82–√2–√222––√√82 |
| Answer» B. 142–√142142–√142142–√142–√142–√142–√142–√2–√222––√√142 | |
| 49. |
(x+1x)(x−1x)(x2+1x2−1)(x2+1x2+1)(x+1x)(x−1x)(x2+1x2−1)(x2+1x2+1) is equal to ? |
| A. | x6−1x6x6−1x6x6−1x6x6−1x6x6−1x6x6−1x6x6−1x6x6−1x6x6x6x6x6xx66−1x61x611x6x6x6x6x6x6x6xx66x6−1x6 |
| B. | x8−1x8x8−1x8x8−1x8x8−1x8x8−1x8x8−1x8x8−1x8x8−1x8x8x8x8x8xx88−1x81x811x8x8x8x8x8x8x8xx88x8−1x8 |
| C. | x6+1x6x6+1x6x6+1x6x6+1x6x6+1x6x6+1x6x6+1x6x6+1x6x6x6x6x6xx66+1x61x611x6x6x6x6x6x6x6xx66x6+1x6 |
| D. | x8+1x8x8+1x8x8+1x8x8+1x8x8+1x8x8+1x8x8+1x8x8+1x8x8x8x8x8xx88+1x81x811x8x8x8x8x8x8x8xx88x8+1x8 |
| Answer» B. x8−1x8x8−1x8x8−1x8x8−1x8x8−1x8x8−1x8x8−1x8x8−1x8x8x8x8x8xx88−1x81x811x8x8x8x8x8x8x8xx88x8−1x8 | |
| 50. |
If pa+qb+rc=1pa+qb+rc=1 and ap+bq+cr=0ap+bq+cr=0 where a, b, c, p, q, r are non-zero real numbers, then p2a2+q2b2+r2c2p2a2+q2b2+r2c2 is equal to = ? |
| A. | 0 |
| B. | 1 |
| C. | 3 |
| D. | 9 |
| Answer» B. 1 | |