1.

If x+1x−1 = abx+1x−1 = ab and 1−y1+y = ba,1−y1+y = ba, then the value of x−y1+xyx−y1+xy = ?

A. 2aba2−b22aba2−b22aba2−b22aba2−b22aba2−b22aba2−b22aba2−b22aba2−b22aba2−b22aba2−b22ab2ab2ab2aba2−b2a2−b2a2−b2a2a2a2a2aa22−b2b2b2b2bb222aba2−b2
B. a2−b22aba2−b22aba2−b22aba2−b22aba2−b22aba2−b22aba2−b22aba2−b22aba2−b22aba2−b22aba2−b2a2−b2a2−b2a2a2a2a2aa22−b2b2b2b2bb222ab2ab2ab2aba2−b22ab
C. a2+b22aba2+b22aba2+b22aba2+b22aba2+b22aba2+b22aba2+b22aba2+b22aba2+b22aba2+b22aba2+b2a2+b2a2+b2a2a2a2a2aa22+b2b2b2b2bb222ab2ab2ab2aba2+b22ab
D. a2−b2aba2−b2aba2−b2aba2−b2aba2−b2aba2−b2aba2−b2aba2−b2aba2−b2aba2−b2aba2−b2a2−b2a2−b2a2a2a2a2aa22−b2b2b2b2bb22ababababa2−b2ab
Answer» B. a2−b22aba2−b22aba2−b22aba2−b22aba2−b22aba2−b22aba2−b22aba2−b22aba2−b22aba2−b22aba2−b2a2−b2a2−b2a2a2a2a2aa22−b2b2b2b2bb222ab2ab2ab2aba2−b22ab


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