On simplification the value ofn1−11+2–√ + 11−2–√is = ?1−11+2 + 11−2is = ?

Question

On simplification the value ofn1−11+2–√ + 11−2–√is = ?1−11+2 + 11−2is = ?

TuteeHUB · Accepted Answer

1−22–√1−221−22–√1−221−22–√1−22–√1−22–√1−22–√1−22–√2–√222––√√1−22

TuteeHUB · Answer

22–√−122−122–√−122−122–√−122–√−122–√−122–√−122–√2–√222––√√−122−1

TuteeHUB · Answer

1−2–√1−21−2–√1−21−2–√1−2–√1−2–√1−2–√1−2–√2–√222––√√1−2

TuteeHUB · Answer

−22–√−22−22–√−22−22–√−22–√−22–√−22–√−22–√2–√222––√√−22

1.	On simplification the value ofn1−11+2–√ + 11−2–√is = ?1−11+2 + 11−2is = ?
A.	22–√−122−122–√−122−122–√−122–√−122–√−122–√−122–√2–√222––√√−122−1
B.	1−22–√1−221−22–√1−221−22–√1−22–√1−22–√1−22–√1−22–√2–√222––√√1−22
C.	1−2–√1−21−2–√1−21−2–√1−2–√1−2–√1−2–√1−2–√2–√222––√√1−2
D.	−22–√−22−22–√−22−22–√−22–√−22–√−22–√−22–√2–√222––√√−22
Answer» B. 1−22–√1−221−22–√1−221−22–√1−22–√1−22–√1−22–√1−22–√2–√222––√√1−22

Discussion