1.

If pa+qb+rc=1pa+qb+rc=1 and ap+bq+cr=0ap+bq+cr=0 where a, b, c, p, q, r are non-zero real numbers, then p2a2+q2b2+r2c2p2a2+q2b2+r2c2 is equal to = ?

A. 0
B. 1
C. 3
D. 9
Answer» B. 1


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