Explore topic-wise MCQs in Embedded Systems.

This section includes 1267 Mcqs, each offering curated multiple-choice questions to sharpen your Embedded Systems knowledge and support exam preparation. Choose a topic below to get started.

351.

The most common cause of non relevant indications in MT is:

A. Over magnetisation
B. Low amperage
C. High flux density
D. Under magnetisation
Answer» B. Low amperage
352.

Lead screen are primarily used to:

A. Improve the quality of the radiography by increasing the effect of scatter radiation
B. Intensify the primary beam
C. Decrease film graininess
D. Reduce density of film
Answer» C. Decrease film graininess
353.

Retentivity:

A. Represents the ability to induce magnetism in a ferromagnetic body by an outside magnetising force
B. Represents the ability of a material to resist the establishment of magnetic flux within it
C. Represents the ability of a material to retain a portion of the magnetic field set up in it after the magnetising force has been removed
D. Is not a term used in magnetic particle testing
Answer» D. Is not a term used in magnetic particle testing
354.

Calculate the refracted shear wave angle in aluminium [VS = 0.31cm/microsec] for anincident longitudinal wave of 53 degrees in Plexiglas [VL = 0.267cm/microsec]

A. 53 degrees
B. 61 degrees
C. 42 degrees
D. 68 degrees
Answer» E.
355.

A material with a wider hysteresis loop has:

A. Lower reluctance
B. Lower residual magnetism
C. Higher residual magnetism
D. Higher permeability
Answer» D. Higher permeability
356.

Diffusion of a lipophilic emulsifier penetrant into the test piece surface is stopped by:

A. The conclusion of the emulsifier dwell time
B. The penetrant
C. Application of developer
D. The water rinse step
Answer» E.
357.

The standard dose rate of a radioactive isotope is expressed in:

A. Roentgens per hour per curie at any standardised distance not exceeding 75 feet
B. Roentgens per hour per curie per foot
C. Roentgens per hour at a distance of one foot
D. Curies per hour
Answer» D. Curies per hour
358.

Which of the following is the most effective method for the detection of extremelydeep-lying defects:

A. Dry residual method using DC surge
B. Wet continuous method using half wave rectified current
C. Wet residual method
D. Dry continuous method using half wave rectified current with prods
Answer» E.
359.

As ultrasonic frequency increases:

A. Wavelength increases
B. Wavelength decreases
C. Sound velocity increases
D. Sound velocity decreases
Answer» C. Sound velocity increases
360.

The average energy of a Ir-192 source is approximately:

A. 60-80 keV
B. 660 keV
C. 400 keV
D. 1.2 MeV
Answer» E.
361.

Which of the following penetrant has a built-in emulsifier

A. Water washable
B. Solvent removable
C. Post emulsified
D. All of the listed above
Answer» B. Solvent removable
362.

Magnetic lines of force enter and leave a magnet at:

A. Saturation
B. L/D ratios of greater than 4 to 1
C. Flux concentration points
D. Poles
Answer» E.
363.

Which of the following is a disadvantage of contact testing?

A. Ability to maintain uniform coupling on rough surface
B. Ease of field use
C. Greater penetrating power than immersion testing
D. Less penetrating power than immersion testing
Answer» B. Ease of field use
364.

The temperature above which steels become nonmagnetic is called the:

A. Zero retentivity
B. Curie point
C. Demagnetisation temperature
D. Random polar point
Answer» C. Demagnetisation temperature
365.

Which penetrant process is the most sensitive to detect fine discontinuities?

A. Solvent removable
B. Water washable
C. Post emulsifiable fluorescent
D. Water washable fluorescent
Answer» D. Water washable fluorescent
366.

The field in a section of pipe being magnetised by means of a central conductor isstronger at:

A. The ends of the pipe
B. The outer surface of the pipe
C. The inside surface of the pipe
D. The middle of the pipe wall
Answer» D. The middle of the pipe wall
367.

According to ASMT E709-95 alternating current electromagnetic yokes should give alifting force of at least:

A. 1.5 kg
B. 2.5 kg
C. 3.5 kg
D. 4.5 kg
Answer» E.
368.

Acoustic impedance is a material's:

A. (Density)/(velocity)
B. (Density) × (velocity)
C. Refractive index
D. (Density)/(refractive index)
Answer» C. Refractive index
369.

Typical ranges of emulsifier dwell times are:

A. 5 to 10 minutes
B. 30 seconds to 1 minute
C. 1 to 3 minutes
D. 5 to 10 minutes
Answer» D. 5 to 10 minutes
370.

According to ASTM E709-95 when fluorescent particles are used, the UV lightintensity shall be above:

A. 700 µW/cm2
B. 800 µW/cm2
C. 900 µW/cm2
D. 1000 µW/cm2
Answer» E.
371.

A penetrant which requires a separate emulsification step prior to removal from the surface of the test piece is called?

A. Solvent removable
B. Water washable
C. Post emulsifiable
D. Solvent suspended
Answer» D. Solvent suspended
372.

A continuous linear indication along the edge of a new fillet weld would most likelybe a:

A. Crater crack
B. Fatigue crack
C. Stress corrosion crack
D. Heat affected zone hydrogen crack
Answer» E.
373.

An advantage of a double versus a single emulsion film is:

A. It is higher speed
B. It is finer grained
C. It is lower speed
D. None of the above
Answer» B. It is finer grained
374.

A metal that is difficult to magnetise is said to have:

A. High permeability
B. Low permeability
C. High reluctance
D. Low retentivity
Answer» C. High reluctance
375.

Sound waves of a frequency beyond the hearing range of the human ear are referred toas ultrasonic waves or vibrations, and the term embraces all vibrational waves of frequency greater than approximately:

A. 20 kHz
B. 2 MHz
C. 2 kHz
D. 200 kHz
Answer» B. 2 MHz
376.

A possible result of failing to use a stop bath during manual development is:

A. Streaking of the film
B. Underdevelopment of the film
C. Contamination of the developer solution
D. Developer solution drag-out
Answer» B. Underdevelopment of the film
377.

A penetrant testing method in which an emulsifier, separate from the penetrant, is usedis called:

A. Solvent removable
B. Water washable
C. Post emulsifying
D. Self emulsifying
Answer» D. Self emulsifying
378.

In longitudinal magnetisation the proper term for calculating magnetising force is:

A. Amperes
B. Ampere-turns
C. Watts
D. Ohms
Answer» C. Watts
379.

Acceptable methods of penetrant application are:

A. Spraying
B. Dipping
C. Brushing
D. All of the above
Answer» E.
380.

When conducting an immersion test, the water path distance must be controlled sothat:

A. Spurious signals are not created by surface waves on the test piece
B. The (water path distance)/(diameter) ratio does not result in asymmetric standing waves
C. The test piece discontinuity indications appear between the first front and first back surface echos
D. The second front surface echo does not appear on the CRT screen between the first front and first back surface echos
Answer» D. The second front surface echo does not appear on the CRT screen between the first front and first back surface echos
381.

When a magnetic field cuts across a crack:

A. Electrons begin jumping back and forth across the crack
B. The crack begins to heat up
C. Magnetic poles form at the edges of the crack
D. All of the above
Answer» D. All of the above
382.

A straight, dark line in the centre of a weld bead image on film would be suspected ofbeing:

A. Lack of fusion
B. A crack
C. Incomplete penetration
D. Root concavity
Answer» D. Root concavity
383.

‘Undercut’ or ‘burned out’ edges of the test piece film image are caused by:

A. Geometric unsharpness
B. Scattered radiation
C. Inadequate source to film distance
D. Old film
Answer» C. Inadequate source to film distance
384.

Why is the need for a dry surface prior to developer application more of a disadvantage with a dry developer than with a non-aqueous wet developer?

A. Because the dry developer only forms a thin film on the surface of the test piece
B. Because the solvent in a non-aqueous wet developer penetrates deeper into discontinuities to contact entrapped penetrant and draw it back out
C. Because the warm test piece causes evaporation of the solvent in the nonaqueous developer
D. All of the above
Answer» B. Because the solvent in a non-aqueous wet developer penetrates deeper into discontinuities to contact entrapped penetrant and draw it back out
385.

How can parts be tested to determine if they have been adequately demagnetized?

A. By bringing a suspended paper clip near the middle of the part
B. By using a small horseshoe permanent magnet
C. By using a small magnetometer held at a corner of the part
D. By sprinkling some magnetic particles on the part
Answer» D. By sprinkling some magnetic particles on the part
386.

According to ASTM E709-95 the UV light shall be centred on (1 Å = 10-10m):

A. 3000Å
B. 3250 Å
C. 3400Å
D. 3650 Å
Answer» E.
387.

If the radiation intensity is 1 Gy/h (100 R/h) at a distance of 152.4 cm (5 feet) from asource, what is the intensity at 610 cm (20 feet)?

A. 0.0625 Gy/h (6.25 R/h)
B. 0.25 Gy/h (25 R/h)
C. 16 Gy/h (1600 R/h)
D. 4 Gy/h (400 R/h)
Answer» B. 0.25 Gy/h (25 R/h)
388.

An ultrasonic testing technique in which the transducer element is not parallel to thetest surface is called:

A. Angle beam testing
B. Immersion testing
C. Contact testing
D. Through-transmission testing
Answer» B. Immersion testing
389.

Sound velocity is described by which of the following relationships?

A. Wavelength times frequency
B. Wavelength divided by frequency
C. Wavelength divided acoustic impedance
D. Acoustic impedance divided by density
Answer» B. Wavelength divided by frequency
390.

In ultrasonic testing, a liquid coupling medium between the crystal surface and the part surface is necessary because :

A. Lubricant is required to minimize wear on the crystal surface
B. An air interface between the crystal surface and the part surface would almost completely reflect the ultrasonic vibrations
C. The crystal will not vibrate if placed directly in contact with the surface of the part being inspected
D. The liquid is necessary to complete the electrical circuit in the search unit
Answer» C. The crystal will not vibrate if placed directly in contact with the surface of the part being inspected
391.

A change in which of the following parameters would necessitate the construction of anew X ray exposure chart?

A. X ray machine used
B. Film type
C. Focal spot to film distance
D. Any of the above
Answer» B. Film type
392.

Abnormally large grain size in the test material may be indicated by:

A. High levels of baseline noise, or hash
B. High amplitude reflections between front and back surface echoes
C. High amplitude, spurious echoes which are not repeatable
D. Abnormally high back surface echo
Answer» B. High amplitude reflections between front and back surface echoes
393.

A dark, jagged, linear indication appears on a radiograph of a casting. The area is a transition area between a thick and a thin section. This indication should be interpreted as:

A. A hot tear
B. A gas hole
C. An unfused chaplet
D. A spongy shrink
Answer» B. A gas hole
394.

The tube current in milliamps multiplied by the time in seconds or minutes equals:

A. Density
B. Intensity
C. Exposure
D. Kilovoltage
Answer» D. Kilovoltage
395.

Static marks are most often caused by:

A. Film bent when inserted in a cassette or holder
B. Foreign material or dirt imbedded in screens
C. Scratches on lead foil screens
D. Improper film handling techniques
Answer» E.
396.

An advantage of a dual crystal search unit is that:

A. There is no ‘dead zone’
B. There is no near surface resolution
C. There is no near field
D. All of the above are true
Answer» B. There is no near surface resolution
397.

For direct contact magnetising methods, the magnetic field is oriented in whatdirection relative to the current direction?

A. Parallel
B. At 45o
C. At 90o
D. At 180o
Answer» D. At 180o
398.

A seam would be classified as what type of discontinuity?

A. Inherent
B. Processing
C. Service
D. None of the above
Answer» C. Service
399.

An important consideration when using a direct contact method is:

A. Lifting power of the yoke
B. Coil diameter
C. Preventing arc burns
D. Field strength adjacent to the coil inside diameter
Answer» D. Field strength adjacent to the coil inside diameter
400.

According to ASTME 709-95 and API, in order to eliminate all contaminants, an appropriate cleaning shall be performed on all the surfaces to be examined and on a minimum of adjacent material:

A. 25.4 mm (1 inch)
B. 31.7 mm (5/4 inches)
C. 38.1 mm (1.5 inches)
D. 44.5 mm (7/4 inches)
Answer» B. 31.7 mm (5/4 inches)