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This section includes 9294 Mcqs, each offering curated multiple-choice questions to sharpen your Engineering knowledge and support exam preparation. Choose a topic below to get started.
| 4651. |
The number of product terms in the minimized sum of product expression obtained through the following K-map, where d, don't care. |
| A. | 2 |
| B. | 3 |
| C. | 4 |
| D. | 5 |
| Answer» B. 3 | |
| 4652. |
BCD equivalent of - 810 is |
| A. | 00110 |
| B. | 10110 |
| C. | 11000 |
| D. | 01000 |
| Answer» D. 01000 | |
| 4653. |
The number of inputs and outputs in a full adder are |
| A. | 2 and 1 |
| B. | 2 and 2 |
| C. | 3 and 3 |
| D. | 3 and 2 |
| Answer» E. | |
| 4654. |
A 6 bit ladder A/D converter has input 101001. The output is (assume 0 = 0 V and 1 = 10 V) |
| A. | 4.23 |
| B. | 6.41 |
| C. | 5.52 |
| D. | 9.23 |
| Answer» C. 5.52 | |
| 4655. |
A ripple counter has 4 bits and uses flip flops with propagation delay time of 25 ns. The maximum possible time for change of state will be |
| A. | 25 ns |
| B. | 50 ns |
| C. | 75 ns |
| D. | 100 ns |
| Answer» E. | |
| 4656. |
A counter has a modulus of 10. The number of flip flops is |
| A. | 10 |
| B. | 5 |
| C. | 4 |
| D. | 3 |
| Answer» D. 3 | |
| 4657. |
A pulse train with a 1 MHz frequency is counted using a 1024 modulus ripple counter using JK flip flops. The maximum propagation delay for each flip-flop should be |
| A. | 1 s |
| B. | 0.5 s |
| C. | 0.2 s |
| D. | 0.1 s |
| Answer» E. | |
| 4658. |
What will be maximum input that can be converted for a 6 bit dual slope A/D converter uses a reference of -6v and a 1 MHz clock. It uses a fixed count of 40 (101000). |
| A. | 9 V |
| B. | 9.45 |
| C. | 10 V |
| D. | 8 V |
| Answer» C. 10 V | |
| 4659. |
In the given figure shows a logic circuit. The minimum Boolean expression for this circuit is |
| A. | A + B |
| B. | A + B + C |
| C. | AB + C |
| D. | AB + AC + BC |
| Answer» C. AB + C | |
| 4660. |
If number of information bits is 11, the number of parity bits in Hamming code is |
| A. | 5 |
| B. | 4 |
| C. | 3 |
| D. | 2 |
| Answer» C. 3 | |
| 4661. |
The number of digit 1 present in the binary representation of 3 x 512 + 7 x 64 + 5 x 8 + 3 is |
| A. | 8 |
| B. | 9 |
| C. | 10 |
| D. | 12 |
| Answer» C. 10 | |
| 4662. |
A + A . B = |
| A. | B |
| B. | A . B |
| C. | A |
| D. | A or B |
| Answer» D. A or B | |
| 4663. |
The device 'one shot' has |
| A. | two stable states |
| B. | one stable state |
| C. | either 1 or 2 stable states |
| D. | no stable state |
| Answer» C. either 1 or 2 stable states | |
| 4664. |
A full adder adds |
| A. | 2 bits |
| B. | 3 bits |
| C. | 4 bits |
| D. | any number of bits |
| Answer» C. 4 bits | |
| 4665. |
A certain JK FF has tpd = 12 n sec the largest MOD counter that can be constructed from these FF and still operate up to 10 MHz is |
| A. | any |
| B. | 8 |
| C. | 256 |
| D. | 10 |
| Answer» D. 10 | |
| 4666. |
For a Mod 64 parallel counter we need |
| A. | 6 flip flops |
| B. | 6 flip flops and 2 AND gates |
| C. | 6 flip flops and 4 AND gates |
| D. | none of the above |
| Answer» D. none of the above | |
| 4667. |
If number of information bits is 4, the parity bits in Hamming code are located at bit positions __________ from the LSB. |
| A. | 1, 2, 5 |
| B. | 1, 2, 4 |
| C. | 1, 2, 3 |
| D. | 1, 2 |
| Answer» C. 1, 2, 3 | |
| 4668. |
If the inputs to a 2 input XOR gate are high then, the output is high. |
| A. | True |
| B. | False |
| Answer» C. | |
| 4669. |
The number of select lines in a 16 : 1 multiplexer are |
| A. | 4 |
| B. | 3 |
| C. | 2 |
| D. | 1 |
| Answer» B. 3 | |
| 4670. |
Out of SR and JK flip flops, which is susceptible to race condition? |
| A. | SR |
| B. | JK |
| C. | Both SR and JK |
| D. | None of the above |
| Answer» B. JK | |
| 4671. |
The number of memory locations in which 14 address bits can access is |
| A. | 1024 |
| B. | 2048 |
| C. | 4096 |
| D. | 16384 |
| Answer» E. | |
| 4672. |
A 6 bit R-2R ladder D/A converter has a reference voltage of 6.5 V. It meets standard linearity then resolution in percent and volts. |
| A. | 3% 7 V |
| B. | 6.4 V, 2% |
| C. | 0.1%, 1.57 V |
| D. | 1.57%, 0.1 V |
| Answer» E. | |
| 4673. |
When a binary adder is used as BCD adder, the sum is |
| A. | correct when it is < 9 |
| B. | correct when it is > 9 |
| C. | correct when it is < 16 |
| D. | none of these |
| Answer» B. correct when it is > 9 | |
| 4674. |
The circuit of the given figure gives the output Y = |
| A. | AB |
| B. | A + B |
| C. | A B |
| D. | <span style="text-decoration:overline;">A + B</span> |
| Answer» E. | |
| 4675. |
If interrupt service request have been received from all of the following interrupts, then which one will be serviced last? |
| A. | RST 5.5 |
| B. | RST 6.5 |
| C. | RST 7.5 |
| D. | None of these |
| Answer» B. RST 6.5 | |
| 4676. |
A gate in which shift register is connected as shown in the figure below. How many clock pulse (after reset to '0') the contents of the shift register are '000' again? |
| A. | 3 |
| B. | 6 |
| C. | 16 |
| D. | 8 |
| Answer» C. 16 | |
| 4677. |
Which liquid crystal is used for LCD display? |
| A. | Mercury |
| B. | Pneumatic fluid |
| C. | Aqua regia |
| D. | Liquid boron |
| Answer» C. Aqua regia | |
| 4678. |
Assuming accumulator contain A 64 and the carry is set (1). What will register A and carry (CY) contain after ORA A? |
| A. | A 6 H, 1 |
| B. | A 6 H, 0 |
| C. | 00 H, 0 |
| D. | 00 H, 1 |
| Answer» C. 00 H, 0 | |
| 4679. |
2's complement of a given 3 or more bit number of non-zero magnitude is the same as the original number if all bits except |
| A. | MSB are zero |
| B. | LSB are zero |
| C. | MSB are 1 |
| D. | LSB are 1 |
| Answer» B. LSB are zero | |
| 4680. |
To have the multiprocessing capabilities of the 8086 microprocessor, the pin connected to the ground is |
| A. | <span style="text-decoration:overline;">DEN</span> |
| B. | ALE |
| C. | INTER |
| D. | <img src="/_files/images/electronics-and-communication-engineering/digital-electronics/42-618.png"> |
| Answer» E. | |
| 4681. |
An index register in digital computer is a register to be used for |
| A. | performing arithmetic and logic operations |
| B. | temporary storage of result |
| C. | counting number of times a program is executed |
| D. | address modification purpose |
| Answer» E. | |
| 4682. |
If noise margin is high, there is lesser chance of false operation. |
| A. | True |
| B. | False |
| Answer» B. False | |
| 4683. |
Decimal 1932 when converted into 10's complement will become |
| A. | 8868 |
| B. | 8068 |
| C. | 8608 |
| D. | 8806 |
| Answer» C. 8608 | |
| 4684. |
In 8085 microprocessor, what is the length of status Word? |
| A. | 6 bits |
| B. | 8 bits |
| C. | 12 bits |
| D. | 16 bits |
| Answer» E. | |
| 4685. |
While obtaining minimal SOP expression |
| A. | all do not care terms are ignored |
| B. | all do not care terms are treated as 1 |
| C. | all do not care terms are treated as 0 |
| D. | only such do not care terms which aid minimization are treated as 1 |
| Answer» E. | |
| 4686. |
In 8085 microprocessor, how many interrupt control lines are there? |
| A. | 6 |
| B. | 8 |
| C. | 12 |
| D. | 16 |
| Answer» C. 12 | |
| 4687. |
In 8085 microprocessor, what are the contents of register SP, after the interrupt has been started? |
| A. | 0210 H |
| B. | 0211 H |
| C. | 054 CH |
| D. | 054 EH |
| Answer» D. 054 EH | |
| 4688. |
Assertion (A): The resolution of a DAC depends on the number of bits Reason (R): Low resolution leads to fine control. |
| A. | Both A and R are correct and R is correct explanation of A |
| B. | Both A and R are correct but R is not correct explanation of A |
| C. | A is true, R is false |
| D. | A is false, R is true |
| Answer» C. A is true, R is false | |
| 4689. |
(62)10 in binary system is |
| A. | 110000 |
| B. | 111100 |
| C. | 111110 |
| D. | 111111 |
| Answer» D. 111111 | |
| 4690. |
In 2's complement addition, the carry generated in the last stage is |
| A. | added to LSB |
| B. | neglected |
| C. | added to bit next to MSB |
| D. | added to the bit next to LSB |
| Answer» C. added to bit next to MSB | |
| 4691. |
A is even or B is true. Negation of above statement is |
| A. | A is odd or B is false |
| B. | A is odd and B is false |
| C. | A is even or B is false |
| D. | A is even and B is false |
| Answer» C. A is even or B is false | |
| 4692. |
In a 4 bit counter the output of 3 JK FFs from MSB downward are connected to the NAND gate whose O/P is connected to CLR |
| A. | it is a MOD-14 counter |
| B. | it is MOD-13 counter |
| C. | it is divided by 13 counter |
| D. | it is divide by 10 counter |
| Answer» B. it is MOD-13 counter | |
| 4693. |
Among the digital IC families - ECL, TTL, and CMOS |
| A. | ECL has the least propagation delay |
| B. | TTL has largest fan out |
| C. | CMOS has the lowest noise margin |
| D. | TTL has the lowest power consumption |
| Answer» B. TTL has largest fan out | |
| 4694. |
In ASCII, letter B is coded as |
| A. | 1000001 |
| B. | 1000010 |
| C. | 100100 |
| D. | 1001000 |
| Answer» C. 100100 | |
| 4695. |
The power dissipated per gate |
| A. | is constant at all frequencies |
| B. | increases with frequency |
| C. | decreases with frequency |
| D. | may increase or decrease with frequency |
| Answer» C. decreases with frequency | |
| 4696. |
For checking the parity of a digital word, it is preferable to use |
| A. | AND gates |
| B. | NAND gates |
| C. | EX-OR gates |
| D. | NOR gates |
| Answer» D. NOR gates | |
| 4697. |
In 8085 microprocessor, what is the memory word addressing capability? |
| A. | 32 K |
| B. | 64 K |
| C. | 256 K |
| D. | 512 K |
| Answer» C. 256 K | |
| 4698. |
Gray code is used in devices which convert analog quantities to digital signal because it is |
| A. | more error free |
| B. | much simpler than binary code |
| C. | superior to Excess-3 code |
| D. | absolutely error free |
| Answer» B. much simpler than binary code | |
| 4699. |
A TTL circuit with totem pole output has |
| A. | high output impedance |
| B. | low output impedance |
| C. | very high output impedance |
| D. | none of the above |
| Answer» C. very high output impedance | |
| 4700. |
A NOR gate has 3 inputs A, B, C. For which combination of inputs is output HIGH |
| A. | A = B = C = 0 |
| B. | A = B = C = 1 |
| C. | A = B = 1 and C = 0 |
| D. | A = C = 1 and B = 0 |
| Answer» B. A = B = C = 1 | |