MCQOPTIONS
Saved Bookmarks
This section includes 1365 Mcqs, each offering curated multiple-choice questions to sharpen your Arithmetic Ability knowledge and support exam preparation. Choose a topic below to get started.
| 401. |
Solve the following :_x005F_x000D_ 38 - (60 ÷ 5 x 16 - 8 ÷ 2 ÷ 3) =?_x005F_x000D_ |
| A. | 22 |
| B. | 29 |
| C. | 30 |
| D. | 37 |
| Answer» B. 29 | |
| 402. |
Solve the following:_x005F_x000D_ 22 - (1/4){-5 - (-48) ÷ (-16)}_x005F_x000D_ |
| A. | 0 |
| B. | 24 |
| C. | 22 |
| D. | 21 |
| Answer» C. 22 | |
| 403. |
Solve the following :_x005F_x000D_ (sin 27°cos 63°) - (cos 27°sin 63°)2_x005F_x000D_ |
| A. | 2 |
| B. | |
| C. | -1 |
| D. | 1 |
| Answer» C. -1 | |
| 404. |
Solve : Sinθ1 + Cosθ + 1 + CosθSinθ_x005F_x000D_ |
| A. | tan θ |
| B. | cot θ |
| C. | 2sin θ |
| D. | 2cosθ |
| Answer» D. 2cosθ | |
| 405. |
Solve : 1213 × 28596 ÷ 171169 = ?_x005F_x000D_ |
| A. | 323 |
| B. | 21724 |
| C. | 78 |
| D. | 1124 |
| Answer» C. 78 | |
| 406. |
Solve: 109 x 102 ÷ 103_x005F_x000D_ |
| A. | 108 |
| B. | 106 |
| C. | 102 |
| D. | 105 |
| Answer» B. 106 | |
| 407. |
Solve 1+tan2θ = ?_x005F_x000D_ |
| A. | cos2θ |
| B. | sec2θ |
| C. | tan2θ |
| D. | 2 |
| Answer» C. tan2θ | |
| 408. |
Solve : 2x + 4 = x - 3_x005F_x000D_ |
| A. | 7 |
| B. | -7 |
| C. | -1 |
| D. | 1 |
| Answer» C. -1 | |
| 409. |
Solve : 12 - [26 - {2 + 5 x (6 - 3)}] |
| A. | 2 |
| B. | 3 |
| C. | 7 |
| D. | 8 |
| Answer» C. 7 | |
| 410. |
Solve : 1000x - 5 = -6 |
| A. | 1/1000 |
| B. | -0.001 |
| C. | -0.011 |
| D. | 11/1000 |
| Answer» C. -0.011 | |
| 411. |
Smaller diagonal of a rhombus is equal to length of its sides. If length of each side is 4 cm, then what is the area (in cm2) of an equilateral triangle with side equal to the bigger diagonal of the rhombus? |
| A. | 6 |
| B. | 9√3 |
| C. | 12 |
| D. | 12√3 |
| Answer» E. | |
| 412. |
Slope of the line AB is -2/3. Co-ordinates of points A and B are (x , -3) and (5 , 2) respectively. What is the value of x? |
| A. | 4 |
| B. | -14 |
| C. | 12.5 |
| D. | -4 |
| Answer» D. -4 | |
| 413. |
Slope of the line AB is -4/3. Co-ordinates of points A and B are (x, -5) and (-5, 3) respectively. What is the value of x? |
| A. | -1 |
| B. | 2 |
| C. | -2 |
| D. | 1 |
| Answer» E. | |
| 414. |
sin(A+B) -Â sin(A-ÂB) is equal to |
| A. | 2sinAcosB |
| B. | 2cosAcosB |
| C. | 2cosAsinB |
| D. | 2sinAsinB |
| Answer» D. 2sinAsinB | |
| 415. |
[sinA/(1 + cosA)] + [(1 + cosA)/sinA] is equal to |
| A. | 2secA |
| B. | 2cosecA |
| C. | 2tanA |
| D. | 2cotA |
| Answer» C. 2tanA | |
| 416. |
sinA/(1 + cos A) is equal to |
| A. | (cosecA -Â cotA) |
| B. | (cosecA + cotA) |
| C. | √[(cosecA Â- cotA)] |
| D. | √[(cosecA + cotA)] |
| Answer» B. (cosecA + cotA) | |
| 417. |
sin 30°1 + cos30° + 1 + cos30°sin30° = ?_x005F_x000D_  _x005F_x000D_ |
| A. | 4 |
| B. | 3 |
| C. | 1 |
| D. | 2 |
| Answer» B. 3 | |
| 418. |
Sinθ Cos(90 - θ) + Cosθ Sin(90 - θ) = _x005F_x000D_ |
| A. | 1 |
| B. | 2 |
| C. | -1 |
| D. | 0 |
| Answer» B. 2 | |
| 419. |
Simplify the fraction?_x005F_x000D_ 5 (2/7) - 3 (1/14) - 2 (1/14) - 1 (1/7) = ? + 3 (1/17) |
| A. | -4 (1/17) |
| B. | 5 (2/17) |
| C. | -2 (1/17) |
| D. | 3 (3/17) |
| Answer» B. 5 (2/17) | |
| 420. |
Simplify the following equation_x005F_x000D_ [K-L2-K+L2]4KÂ = a/b |
| A. | K = b /a |
| B. | bL = -a |
| C. | KL = 1 |
| D. | aK = -b |
| Answer» C. KL = 1 | |
| 421. |
Simplify the following equation_x005F_x000D_ 55.55 + 155 + 15.55 + 0.5 + 0.05 = ? |
| A. | 226.65 |
| B. | 196.55 |
| C. | 202.35 |
| D. | 216.66 |
| Answer» B. 196.55 | |
| 422. |
Simplify the following equation ?_x005F_x000D_ 2003 x 2004 - 2001 x 2002 = ? |
| A. | 8010 |
| B. | 8020 |
| C. | 8030 |
| D. | 8040 |
| Answer» B. 8020 | |
| 423. |
Simplify the following equation._x005F_x000D_ 1943Â +Â 12Â +Â 13Â +Â 11Â +Â 14 |
| A. | 43/19 |
| B. | 1 |
| C. | 38/19 |
| D. | None of these |
| Answer» E. | |
| 424. |
Simplify the following and find the value of ?_x005F_x000D_  _x005F_x000D_ 13 of ? + 47 of 114 of 539 = 31% of 2000 |
| A. | 1134 |
| B. | 1237 |
| C. | 1187 |
| D. | 1249 |
| Answer» B. 1237 | |
| 425. |
Simplify the following :_x005F_x000D_ 4 15 × 3 13 + ? = 20% of 120 |
| A. | 10 |
| B. | 24 |
| C. | 36 |
| D. | 40 |
| Answer» B. 24 | |
| 426. |
Simplify the following :_x005F_x000D_ 373+353+283-3x37x35x28372+352+282-37x35-35x28-37x28Â ? |
| A. | 100 |
| B. | 1 |
| C. | 4 |
| D. | 0 |
| Answer» B. 1 | |
| 427. |
Simplify (533bxaz)/(41ab) |
| A. | 17xzb |
| B. | 19xz |
| C. | 13xz |
| D. | 31ab |
| Answer» D. 31ab | |
| 428. |
Simplify  _x005F_x000D_ 1.53 + 4.73 + 3.83 - 3 x 1.5 x 4.7 x 3.81.52 + 4.72 + 3.82 - 1.5 x 4.7 - 4.7 x 3.8 - 1.5 x 3.8 |
| A. | 6 |
| B. | 8 |
| C. | 10 |
| D. | 12 |
| Answer» D. 12 | |
| 429. |
Simplify : 913 ÷ 1826 ÷ 9052_x005F_x000D_ |
| A. | 45/26 |
| B. | 13/45 |
| C. | 26/45 |
| D. | 45/13 |
| Answer» D. 45/13 | |
| 430. |
Simplify : 528 ÷ 2835 ÷ 20112_x005F_x000D_ |
| A. | 44320 |
| B. | 44291 |
| C. | 44381 |
| D. | 44293 |
| Answer» C. 44381 | |
| 431. |
Simplify :Â (27)-23_x005F_x000D_ |
| A. | 43101 |
| B. | 9 |
| C. | 44440 |
| D. | 18 |
| Answer» D. 18 | |
| 432. |
Simplify :Â (25)32_x005F_x000D_ |
| A. | 625 |
| B. | 15625 |
| C. | 125 |
| D. | √125 |
| Answer» D. √125 | |
| 433. |
Simplify 2392-21+8-72=?2_x005F_x000D_ |
| A. | 4 |
| B. | 5 |
| C. | 6 |
| D. | 9 |
| Answer» D. 9 | |
| 434. |
Simplify and find '?'_x005F_x000D_ 48?+32? = 320 |
| A. | 4 |
| B. | 8 |
| C. | 16 |
| D. | 32 |
| Answer» D. 32 | |
| 435. |
Simplify: b-[b-(a+b)-{b-(b-a-b)}+2a] |
| A. | 2b |
| B. | 1 |
| C. | 0 |
| D. | 3b |
| Answer» D. 3b | |
| 436. |
Simplify 5x(x + 2) + 4x_x005F_x000D_ Â _x005F_x000D_ |
| A. | 5x2Â +Â 10 |
| B. | 9x + 10 |
| C. | 5x2Â -Â 14x |
| D. | 5x2Â +Â 14x |
| Answer» E. | |
| 437. |
Simplify : 5x - 2x(x-1)_x005F_x000D_ |
| A. | 3x-2 |
| B. | 3x+2 |
| C. | 7x+2x2 |
| D. | 7x-2x2 |
| Answer» E. | |
| 438. |
Simplify 4(x-1) -3x |
| A. | 7x - 4 |
| B. | 7x + 4 |
| C. | x + 4 |
| D. | x - 4 |
| Answer» E. | |
| 439. |
Simplify : (-4.6)x(-4.6)/(-4.6+0.6) |
| A. | -5.29 |
| B. | -0.529 |
| C. | -4.06 |
| D. | 5.01 |
| Answer» B. -0.529 | |
| 440. |
Simplify 437bxaz / 23ab. |
| A. | 17xzb |
| B. | 9xz |
| C. | 19xz |
| D. | 19ab |
| Answer» D. 19ab | |
| 441. |
Simplify: (213 x 213 + 187 x 187) |
| A. | 80338 |
| B. | 80438 |
| C. | 60338 |
| D. | 60438 |
| Answer» B. 80438 | |
| 442. |
Simplify (2/7 + 3/5) / (2/5 + 2/7) |
| A. | 31/24 |
| B. | 24/31 |
| C. | 26/25 |
| D. | 41609 |
| Answer» B. 24/31 | |
| 443. |
Simplify: (157 x 157 + 143 x 143)_x005F_x000D_ |
| A. | 45098 |
| B. | 46098 |
| C. | 90196_x005F_x000D_ |
| D. | 91196 |
| Answer» B. 46098 | |
| 444. |
Simplify_x005F_x000D_ 39.96% of 649.85 ÷13.07 = 45.14 - ? |
| A. | 25 |
| B. | 26 |
| C. | 27 |
| D. | 28 |
| Answer» B. 26 | |
| 445. |
Shaan got a total of Rs. 912 in the denomination of equal numbers of Rs. 1, Rs. 5 and Rs. 10 coins. How many coins do Shaan posses? |
| A. | 16 |
| B. | 57 |
| C. | 171 |
| D. | 323 |
| Answer» D. 323 | |
| 446. |
Select the option that can replace the question mark (?) in the following equation._x005F_x000D_  _x005F_x000D_ 2 + 5 ÷ [5 + 8 ÷ 1 + 13 - 1] = ?_x005F_x000D_ |
| A. | 44228 |
| B. | 44232 |
| C. | 44230 |
| D. | 2 |
| Answer» C. 44230 | |
| 447. |
Select the option that can replace the '?' symbol in the following equation._x005F_x000D_  _x005F_x000D_ 122 + 345 - 1 x 1011 ÷ 337 = ?_x005F_x000D_ |
| A. | 446 |
| B. | 644 |
| C. | 460 |
| D. | 464 |
| Answer» E. | |
| 448. |
Select the option that can replace the question mark (?) in the following equation._x005F_x000D_ Â _x005F_x000D_ 0.23Â -Â 0.130.2Â +Â 0.12_x005F_x000D_ |
| A. | 43101 |
| B. | 14671 |
| C. | -0.077777777777778 |
| D. | 33055 |
| Answer» E. | |
| 449. |
Select the appropriate combination of symbols that when sequentially placed in place of the question marks (?) in the given equation will correctly complete the equation._x005F_x000D_  _x005F_x000D_ ((20?100)?4)?10 = −10_x005F_x000D_ |
| A. | −, ×, ÷ |
| B. | −, ÷, + |
| C. | +, ÷, ÷ |
| D. | +, ×, × |
| Answer» C. +, ÷, ÷ | |
| 450. |
(secA Â- tanA)/(cosecA + cotA) is equal to |
| A. | (secA -Â cot'/ (cosecA + tanA) |
| B. | (secA -Â cosA) / (cosecA + sinA) |
| C. | (cosecA -Â cotA) / (secA + tanA) |
| D. | (secA + cosA) / (cosecA -Â sinA) |
| Answer» D. (secA + cosA) / (cosecA -Â sinA) | |