Explore topic-wise MCQs in Arithmetic Ability.

This section includes 1365 Mcqs, each offering curated multiple-choice questions to sharpen your Arithmetic Ability knowledge and support exam preparation. Choose a topic below to get started.

401.

Solve the following :_x005F_x000D_ 38 - (60 ÷ 5 x 16 - 8 ÷ 2 ÷ 3) =?_x005F_x000D_

A. 22
B. 29
C. 30
D. 37
Answer» B. 29
402.

Solve the following:_x005F_x000D_ 22 - (1/4){-5 - (-48) ÷ (-16)}_x005F_x000D_

A. 0
B. 24
C. 22
D. 21
Answer» C. 22
403.

Solve the following :_x005F_x000D_ (sin 27°cos 63°) - (cos 27°sin 63°)2_x005F_x000D_

A. 2
B.
C. -1
D. 1
Answer» C. -1
404.

Solve : Sinθ1 + Cosθ + 1 + CosθSinθ_x005F_x000D_

A. tan θ
B. cot θ
C. 2sin θ
D. 2cosθ
Answer» D. 2cosθ
405.

Solve : 1213 × 28596 ÷ 171169 = ?_x005F_x000D_

A. 323
B. 21724
C. 78
D. 1124
Answer» C. 78
406.

Solve: 109 x 102 ÷ 103_x005F_x000D_

A. 108
B. 106
C. 102
D. 105
Answer» B. 106
407.

Solve 1+tan2θ = ?_x005F_x000D_

A. cos2θ
B. sec2θ
C. tan2θ
D. 2
Answer» C. tan2θ
408.

Solve : 2x + 4 = x - 3_x005F_x000D_

A. 7
B. -7
C. -1
D. 1
Answer» C. -1
409.

Solve : 12 - [26 - {2 + 5 x (6 - 3)}]

A. 2
B. 3
C. 7
D. 8
Answer» C. 7
410.

Solve : 1000x - 5 = -6

A. 1/1000
B. -0.001
C. -0.011
D. 11/1000
Answer» C. -0.011
411.

Smaller diagonal of a rhombus is equal to length of its sides. If length of each side is 4 cm, then what is the area (in cm2) of an equilateral triangle with side equal to the bigger diagonal of the rhombus?

A. 6
B. 9√3
C. 12
D. 12√3
Answer» E.
412.

Slope of the line AB is -2/3. Co-ordinates of points A and B are (x , -3) and (5 , 2) respectively. What is the value of x?

A. 4
B. -14
C. 12.5
D. -4
Answer» D. -4
413.

Slope of the line AB is -4/3. Co-ordinates of points A and B are (x, -5) and (-5, 3) respectively. What is the value of x?

A. -1
B. 2
C. -2
D. 1
Answer» E.
414.

sin(A+B) -­ sin(A-­B) is equal to

A. 2sinAcosB
B. 2cosAcosB
C. 2cosAsinB
D. 2sinAsinB
Answer» D. 2sinAsinB
415.

[sinA/(1 + cosA)] + [(1 + cosA)/sinA] is equal to

A. 2secA
B. 2cosecA
C. 2tanA
D. 2cotA
Answer» C. 2tanA
416.

sinA/(1 + cos A) is equal to

A. (cosecA -­ cotA)
B. (cosecA + cotA)
C. √[(cosecA ­- cotA)]
D. √[(cosecA + cotA)]
Answer» B. (cosecA + cotA)
417.

sin 30°1 + cos30° + 1 + cos30°sin30° = ?_x005F_x000D_  _x005F_x000D_

A. 4
B. 3
C. 1
D. 2
Answer» B. 3
418.

Sinθ Cos(90 - θ) + Cosθ Sin(90 - θ) = _x005F_x000D_

A. 1
B. 2
C. -1
D. 0
Answer» B. 2
419.

Simplify the fraction?_x005F_x000D_ 5 (2/7) - 3 (1/14) - 2 (1/14) - 1 (1/7) = ? + 3 (1/17)

A. -4 (1/17)
B. 5 (2/17)
C. -2 (1/17)
D. 3 (3/17)
Answer» B. 5 (2/17)
420.

Simplify the following equation_x005F_x000D_ [K-L2-K+L2]4K = a/b

A. K = b /a
B. bL = -a
C. KL = 1
D. aK = -b
Answer» C. KL = 1
421.

Simplify the following equation_x005F_x000D_ 55.55 + 155 + 15.55 + 0.5 + 0.05 = ?

A. 226.65
B. 196.55
C. 202.35
D. 216.66
Answer» B. 196.55
422.

Simplify the following equation ?_x005F_x000D_ 2003 x 2004 - 2001 x 2002 = ?

A. 8010
B. 8020
C. 8030
D. 8040
Answer» B. 8020
423.

Simplify the following equation._x005F_x000D_ 1943 + 12 + 13 + 11 + 14

A. 43/19
B. 1
C. 38/19
D. None of these
Answer» E.
424.

Simplify the following and find the value of ?_x005F_x000D_  _x005F_x000D_ 13 of ? + 47 of 114 of 539 = 31% of 2000

A. 1134
B. 1237
C. 1187
D. 1249
Answer» B. 1237
425.

Simplify the following :_x005F_x000D_ 4 15 × 3 13 + ? = 20% of 120

A. 10
B. 24
C. 36
D. 40
Answer» B. 24
426.

Simplify the following :_x005F_x000D_ 373+353+283-3x37x35x28372+352+282-37x35-35x28-37x28 ?

A. 100
B. 1
C. 4
D. 0
Answer» B. 1
427.

Simplify (533bxaz)/(41ab)

A. 17xzb
B. 19xz
C. 13xz
D. 31ab
Answer» D. 31ab
428.

Simplify  _x005F_x000D_ 1.53 + 4.73 + 3.83 - 3 x 1.5 x 4.7 x 3.81.52 + 4.72 + 3.82 - 1.5 x 4.7 - 4.7 x 3.8 - 1.5 x 3.8

A. 6
B. 8
C. 10
D. 12
Answer» D. 12
429.

Simplify : 913 ÷ 1826 ÷ 9052_x005F_x000D_

A. 45/26
B. 13/45
C. 26/45
D. 45/13
Answer» D. 45/13
430.

Simplify : 528 ÷ 2835 ÷ 20112_x005F_x000D_

A. 44320
B. 44291
C. 44381
D. 44293
Answer» C. 44381
431.

Simplify : (27)-23_x005F_x000D_

A. 43101
B. 9
C. 44440
D. 18
Answer» D. 18
432.

Simplify : (25)32_x005F_x000D_

A. 625
B. 15625
C. 125
D. √125
Answer» D. √125
433.

Simplify 2392-21+8-72=?2_x005F_x000D_

A. 4
B. 5
C. 6
D. 9
Answer» D. 9
434.

Simplify and find '?'_x005F_x000D_ 48?+32? = 320

A. 4
B. 8
C. 16
D. 32
Answer» D. 32
435.

Simplify: b-[b-(a+b)-{b-(b-a-b)}+2a]

A. 2b
B. 1
C. 0
D. 3b
Answer» D. 3b
436.

Simplify 5x(x + 2) + 4x_x005F_x000D_  _x005F_x000D_

A. 5x2 + 10
B. 9x + 10
C. 5x2 - 14x
D. 5x2 + 14x
Answer» E.
437.

Simplify : 5x - 2x(x-1)_x005F_x000D_

A. 3x-2
B. 3x+2
C. 7x+2x2
D. 7x-2x2
Answer» E.
438.

Simplify 4(x-1) -3x

A. 7x - 4
B. 7x + 4
C. x + 4
D. x - 4
Answer» E.
439.

Simplify : (-4.6)x(-4.6)/(-4.6+0.6)

A. -5.29
B. -0.529
C. -4.06
D. 5.01
Answer» B. -0.529
440.

Simplify 437bxaz / 23ab.

A. 17xzb
B. 9xz
C. 19xz
D. 19ab
Answer» D. 19ab
441.

Simplify: (213 x 213 + 187 x 187)

A. 80338
B. 80438
C. 60338
D. 60438
Answer» B. 80438
442.

Simplify (2/7 + 3/5) / (2/5 + 2/7)

A. 31/24
B. 24/31
C. 26/25
D. 41609
Answer» B. 24/31
443.

Simplify: (157 x 157 + 143 x 143)_x005F_x000D_

A. 45098
B. 46098
C. 90196_x005F_x000D_
D. 91196
Answer» B. 46098
444.

Simplify_x005F_x000D_ 39.96% of 649.85 ÷13.07 = 45.14 - ?

A. 25
B. 26
C. 27
D. 28
Answer» B. 26
445.

Shaan got a total of Rs. 912 in the denomination of equal numbers of Rs. 1, Rs. 5 and Rs. 10 coins. How many coins do Shaan posses?

A. 16
B. 57
C. 171
D. 323
Answer» D. 323
446.

Select the option that can replace the question mark (?) in the following equation._x005F_x000D_  _x005F_x000D_ 2 + 5 ÷ [5 + 8 ÷ 1 + 13 - 1] = ?_x005F_x000D_

A. 44228
B. 44232
C. 44230
D. 2
Answer» C. 44230
447.

Select the option that can replace the '?' symbol in the following equation._x005F_x000D_  _x005F_x000D_ 122 + 345 - 1 x 1011 ÷ 337 = ?_x005F_x000D_

A. 446
B. 644
C. 460
D. 464
Answer» E.
448.

Select the option that can replace the question mark (?) in the following equation._x005F_x000D_  _x005F_x000D_ 0.23 - 0.130.2 + 0.12_x005F_x000D_

A. 43101
B. 14671
C. -0.077777777777778
D. 33055
Answer» E.
449.

Select the appropriate combination of symbols that when sequentially placed in place of the question marks (?) in the given equation will correctly complete the equation._x005F_x000D_  _x005F_x000D_ ((20?100)?4)?10 = −10_x005F_x000D_

A. −, ×, ÷
B. −, ÷, +
C. +, ÷, ÷
D. +, ×, ×
Answer» C. +, ÷, ÷
450.

(secA ­- tanA)/(cosecA + cotA) is equal to

A. (secA -­ cot'/ (cosecA + tanA)
B. (secA -­ cosA) / (cosecA + sinA)
C. (cosecA -­ cotA) / (secA + tanA)
D. (secA + cosA) / (cosecA -­ sinA)
Answer» D. (secA + cosA) / (cosecA -­ sinA)