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This section includes 1365 Mcqs, each offering curated multiple-choice questions to sharpen your Arithmetic Ability knowledge and support exam preparation. Choose a topic below to get started.
| 351. |
The co-ordinates of the centroid of a triangle ABC are (3,-2). What are the co-ordinates of vertex C if co-ordinates of A and B are (-2,5) and (6,-2)Â respectively? |
| A. | (-5,-9) |
| B. | (5,-9) |
| C. | (5,9) |
| D. | (-5,9) |
| Answer» C. (5,9) | |
| 352. |
The average revenues of 13 consecutive years of a company is Rs 70 lakhs. If the average of first 7 years is Rs 65 lakhs and that of last 7 years is Rs 77Â lakhs, find the revenue for the 7th year. |
| A. | Rs 86 lakhs |
| B. | Rs 84 lakhs |
| C. | Rs 82 lakhs |
| D. | Rs 80 lakhs |
| Answer» C. Rs 82 lakhs | |
| 353. |
The average weight of Sudesh, Jyothi and Ritu is 89 kg. If the average weight of Sudesh and Jyothi be 98 kg and that of Jyothi and Ritu be 83 kg, then the weight of Jyothi is |
| A. | 58 |
| B. | 56 |
| C. | 95 |
| D. | 66 |
| Answer» D. 66 | |
| 354. |
The average of 100 observations was calculated as 35.It was found later, that one of the observation was misread as 83 instead of 53. The correct average is : |
| A. | 32.7 |
| B. | 34.7 |
| C. | 35.7 |
| D. | 36.7 |
| Answer» C. 35.7 | |
| 355. |
The angle of elevation of the top of a tower, vertically erected in the middle of a paddy field, from two points on a horizontal line through the foot of the tower are given to be α and β (α>β). The height of the tower is h unit. A possible distance (in the same unit) between the points is |
| A. | h(cotβ-cotα)cos(α+β) |
| B. | h(cotα - cotβ) |
| C. | h(tanβ - tanα)tanα tanβ |
| D. | h(cotα+cotβ) |
| Answer» E. | |
| 356. |
The area of the circle with radius Y is W. The difference between the areas of the bigger circle (with radius Y) and that of the smaller circle (with radius X) is W'. So x/y is equal to_x005F_x000D_ |
| A. | 1 |
| B. | 2 |
| C. | 3 |
| D. | 4 |
| Answer» B. 2 | |
| 357. |
The areas of two similar triangles ΔABC and ΔPQR are 121 sq cms and 64 sq cms respectively. If PQ = 12 cm, what is the length (in cm) of AB? |
| A. | 7.25 |
| B. | 6.25 |
| C. | 16.5 |
| D. | 5.25 |
| Answer» D. 5.25 | |
| 358. |
The angle of elevation of the top of a tower from two horizontal points (in opposite sides) at distances of 25 meter and 64 meter from the base of tower are x and 90° - x respectively . The height of the tower will be |
| A. | 39 m |
| B. | 89 m |
| C. | 1.6 m |
| D. | 40 m |
| Answer» E. | |
| 359. |
The average number of visitors of a library in the first 4 days of a week was 58. The average for the 2nd, 3rd, 4th and 5th days was 60.If the number of visitors on the 1st and 5th days were in the ratio 8 : 9. Then what is the number of visitors on the 5th day of the library ? |
| A. | 54 |
| B. | 64 |
| C. | 68 |
| D. | 72 |
| Answer» E. | |
| 360. |
The angle of elevation of the top of a tower from a point A on the ground is 30°. On moving a distance of 20 metres towards the foot of the tower to a point B, the angle of elevation increases to 60°. The height of the tower in meters is |
| A. | √3 |
| B. | 5√3 |
| C. | 10√3 |
| D. | 20√3 |
| Answer» D. 20√3 | |
| 361. |
The 3rd and 8th term of an arithmetic progression are -13 and 2 respectively. What is the 14th term? |
| A. | 23 |
| B. | 17 |
| C. | 20 |
| D. | 26 |
| Answer» D. 26 | |
| 362. |
The value of315+314+1921+3135-2330 is:_x005F_x000D_ |
| A. | 25 |
| B. | 13 |
| C. | 1235 |
| D. | 821 |
| Answer» D. 821 | |
| 363. |
tan(A/2) is equal to |
| A. | tanA/(1 + secA) |
| B. | 1/(cosecA + cotA) |
| C. | tanA/(1 + cosecA) |
| D. | 1/(secA + cotA) |
| Answer» B. 1/(cosecA + cotA) | |
| 364. |
Tan 45° + Cosec 60° = |
| A. | (1 + 2√2)/2 |
| B. | (√3 + 2)/√6 |
| C. | 5/√3 |
| D. | (3 + 2√3)/3 |
| Answer» E. | |
| 365. |
Take away 0.15 from 2.4 and add the result to 7.5. What do you get?_x005F_x000D_ |
| A. | 8.75 |
| B. | 7.8.75 |
| C. | 9.75 |
| D. | 6 |
| Answer» D. 6 | |
| 366. |
Suppose 0 < θ < 90, then for every θ 4 sin2 θ + 1 is greater than or equal to ?_x005F_x000D_ |
| A. | 2 |
| B. | 4 sin θ |
| C. | 4 cos θ |
| D. | 4 tan θ |
| Answer» C. 4 cos θ | |
| 367. |
Sum of twice a fraction and its reciprocal is 17/6. What is the fraction? |
| A. | 44259 |
| B. | 44291 |
| C. | 44289 |
| D. | 44320 |
| Answer» D. 44320 | |
| 368. |
Sumit and Amit undertook a work for Rs 7200. Sumit alone can do the work in 5 days and Amit alone can do the work in 4 days. If they work together,then what will be the difference (in Rs.) in the amount they receive? |
| A. | 800 |
| B. | 1600 |
| C. | 1200 |
| D. | 1400 |
| Answer» B. 1600 | |
| 369. |
Sum of a fraction and thrice of its reciprocal is 73/20. What is the fraction? |
| A. | 44320 |
| B. | 44295 |
| C. | 44443 |
| D. | 44291 |
| Answer» E. | |
| 370. |
Square root of 0.9 is equal to |
| A. | 0.03 |
| B. | 0.3 |
| C. | 0.9487 |
| D. | 0.9463 |
| Answer» D. 0.9463 | |
| 371. |
Square of (3x – 5xy) is |
| A. | 9x2 - 30x2y + 25x2y2 |
| B. | 9x2 - 15x2y + 25x2y2 |
| C. | 25x2 - 15x2y + 9x2y2 |
| D. | 25x2 - 30x2y + 9x2y2 |
| Answer» B. 9x2 - 15x2y + 25x2y2 | |
| 372. |
Square of (7 Â- 4x) is |
| A. | 16x2 - 28x + 49 |
| B. | 49 - 28x Â- 16x2 |
| C. | 49 - Â 56x - 16x2 |
| D. | 16x2 - 56x + 49 |
| Answer» E. | |
| 373. |
Solve : x - 3 = 3x + 7_x005F_x000D_ Â _x005F_x000D_ |
| A. | 5 |
| B. | -5 |
| C. | 1 |
| D. | 44296 |
| Answer» C. 1 | |
| 374. |
Solve : (x + 2y) (2x - y) |
| A. | 2x2 + 5xy + 2y2 |
| B. | 2x2 + 3xy - 2y2 |
| C. | x2 + 4xy + y2 |
| D. | x2+ 4xy - y2 |
| Answer» C. x2 + 4xy + y2 | |
| 375. |
Solve this inequality 3b - 7 < 32? |
| A. | b = 13 |
| B. | b < 13 |
| C. | b > = 13 |
| D. | b < = 13 |
| Answer» C. b > = 13 | |
| 376. |
Solve the following : 80÷[48−56−(60−36÷12×4)]=?_x005F_x000D_ |
| A. | 5 |
| B. | 8 |
| C. | 4 |
| D. | 2 |
| Answer» E. | |
| 377. |
Solve this inequality 3p - 16 < 20? |
| A. | p >= 12 |
| B. | p <= 11/3 |
| C. | p < 12 |
| D. | p > 11/3 |
| Answer» D. p > 11/3 | |
| 378. |
Solve the following: (−18)[36÷7−(−2)]÷{}(−4)19−(−3)×(−5)={}? |
| A. | -4.5 |
| B. | 4.5 |
| C. | -2.5 |
| D. | 2.5 |
| Answer» C. -2.5 | |
| 379. |
Solve the following expression._x005F_x000D_ Â _x005F_x000D_ 5.6 - [2 + 0.6 of (2.1 - 2.6 x 1.12)]_x005F_x000D_ |
| A. | 7.7112 |
| B. | 7.7113 |
| C. | 4.0871 |
| D. | 4.0872 |
| Answer» E. | |
| 380. |
Solve the following expression._x005F_x000D_ 11 + 11 × 11 − 11 ÷ 11_x005F_x000D_  _x005F_x000D_ |
| A. | 131 |
| B. | 22 |
| C. | 11 |
| D. | 121 |
| Answer» B. 22 | |
| 381. |
Solve the following : 3/4+{3/4 + 3/4 ÷ (3/4 + 3/4)} = ? |
| A. | 0 |
| B. | 44289 |
| C. | 1 |
| D. | 2 |
| Answer» E. | |
| 382. |
Solve the following : 27 - [38 - {46 - (15 - 13 - 2)}] |
| A. | 31 |
| B. | 35 |
| C. | 30 |
| D. | 29 |
| Answer» C. 30 | |
| 383. |
Solve the following 7 x {4 + (-2) x (-3)} = ? |
| A. | 14 |
| B. | -42 |
| C. | -14 |
| D. | 70 |
| Answer» E. | |
| 384. |
Solve the following :_x005F_x000D_  _x005F_x000D_  _x005F_x000D_ 24 - [25 - 26 - 27 - 28 - 29¯] = ?_x005F_x000D_  _x005F_x000D_ |
| A. | -1 |
| B. | 1 |
| C. | -3 |
| D. | -2 |
| Answer» D. -2 | |
| 385. |
Solve the following : -1/4 { -45 - (-96) / (-32)} = ? |
| A. | 12 |
| B. | 10.5 |
| C. | -12 |
| D. | -10.5 |
| Answer» B. 10.5 | |
| 386. |
Solve the following :_x005F_x000D_ Â _x005F_x000D_ (-8) [36 / {7 - (-2)}] / (-4){19 - (-3) x (-5)} = ? |
| A. | 4 |
| B. | -4 |
| C. | -2 |
| D. | 2 |
| Answer» E. | |
| 387. |
Solve the following :_x005F_x000D_  _x005F_x000D_ 72 ÷ 12{15 + 12 - 9 + 6 - 5 + 7¯} = ?_x005F_x000D_ |
| A. | 6 |
| B. | 9 |
| C. | 12 |
| D. | 8 |
| Answer» B. 9 | |
| 388. |
Solve the following :_x005F_x000D_  _x005F_x000D_ (-6)[40 ÷ 7 - -3] = ?_x005F_x000D_  _x005F_x000D_ |
| A. | -24 |
| B. | -60 |
| C. | 60 |
| D. | 24 |
| Answer» B. -60 | |
| 389. |
Solve the following._x005F_x000D_ Â _x005F_x000D_ -4 - (-7 - 12 / 4) = ? |
| A. | -2 |
| B. | 6 |
| C. | 0.75 |
| D. | -14 |
| Answer» C. 0.75 | |
| 390. |
Solve the following :_x005F_x000D_ Â _x005F_x000D_ (-4){19 - (-2) x (-8)} = ? |
| A. | 12 |
| B. | -140 |
| C. | 140 |
| D. | -12 |
| Answer» E. | |
| 391. |
Solve the following_x005F_x000D_ Â _x005F_x000D_ 36- [18 - {14 - (15 - 4 / 2 x 2)}]_x005F_x000D_ Â _x005F_x000D_ |
| A. | 23 |
| B. | 21 |
| C. | 20 |
| D. | 22 |
| Answer» C. 20 | |
| 392. |
Solve the following_x005F_x000D_ Â _x005F_x000D_ 24/(19 - 9 / 3 x 9) = ? |
| A. | -3 |
| B. | -4 |
| C. | 3 |
| D. | 6 |
| Answer» B. -4 | |
| 393. |
Solve the following_x005F_x000D_ Â _x005F_x000D_ 24 / (20 - 12 / 3 x 8) = ? |
| A. | -2 |
| B. | -3 |
| C. | 6 |
| D. | 3 |
| Answer» B. -3 | |
| 394. |
Solve the following :_x005F_x000D_  _x005F_x000D_ 2sin22°cos68° - 2cot75°5tan15° - 8tan45°tan20°tan40°5tan50°tan70°_x005F_x000D_ |
| A. | 3 |
| B. | 1 |
| C. | 2 |
| D. | 0 |
| Answer» E. | |
| 395. |
Solve the following_x005F_x000D_ Â _x005F_x000D_ 23 - [23 - {23 - (23 - 23 + 23)}]_x005F_x000D_ |
| A. | -1 |
| B. | 23 |
| C. | 1 |
| D. | 0 |
| Answer» E. | |
| 396. |
Solve the following :_x005F_x000D_ Â _x005F_x000D_ 123 + 12.3 + 1.23 + 0.123 + 0.0123 = ? |
| A. | 136.7659 |
| B. | 136.653 |
| C. | 136.6653 |
| D. | 136.776 |
| Answer» D. 136.776 | |
| 397. |
Solve the following:_x005F_x000D_  _x005F_x000D_ 11 + sinθ + 11 - sinθ = ?_x005F_x000D_ |
| A. | 2cos2θ |
| B. | 1 |
| C. | 0 |
| D. | 2sec2θ |
| Answer» E. | |
| 398. |
Solve the following :_x005F_x000D_ Â _x005F_x000D_ 196 - 19.6 - 1.96 - 0.196 = ?_x005F_x000D_ |
| A. | 173.254 |
| B. | 173.234 |
| C. | 174.234 |
| D. | 174.244 |
| Answer» E. | |
| 399. |
Solve the following_x005F_x000D_ 78 ÷[-4 + -3 of 27 ÷ -18 ÷ -2] |
| A. | -6 |
| B. | 13 |
| C. | 6 |
| D. | 15.6 |
| Answer» B. 13 | |
| 400. |
Solve the following :_x005F_x000D_ 60 ÷ 5 × 16 - 8 ÷ 2 ÷ 3 = ? |
| A. | 3 |
| B. | 48 |
| C. | 1 |
| D. | 44256 |
| Answer» C. 1 | |