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MCQOPTIONS
This section includes 2318 Mcqs, each offering curated multiple-choice questions to sharpen your 8th Class knowledge and support exam preparation. Choose a topic below to get started.
| 1151. |
Simplify; \[\begin{align} & {{\left( \frac{{{x}^{a}}}{{{x}^{b}}} \right)}^{({{a}^{2}}+{{b}^{2}}+ab)}}\times {{\left( \frac{{{x}^{b}}}{{{x}^{c}}} \right)}^{({{b}^{2}}+{{c}^{2}}+cb)}}\times {{\left( \frac{{{x}^{c}}}{{{x}^{a}}} \right)}^{({{c}^{2}}+{{a}^{2}}+ca)}} \\ & \\ \end{align}\] |
| A. | 1 |
| B. | \[{{(a+b+c)}^{3}}\] |
| C. | \[{{\text{a}}^{\text{2}}}\text{+}{{\text{b}}^{\text{2}}}\text{+}{{\text{c}}^{\text{2}}}\] |
| D. | 0 |
| Answer» B. \[{{(a+b+c)}^{3}}\] | |
| 1152. |
Evaluate: \[{{\left( \frac{16}{81} \right)}^{\frac{3}{4}}}\] |
| A. | \[\frac{9}{2}\] |
| B. | \[\frac{2}{9}\] |
| C. | \[\frac{8}{27}\] |
| D. | \[\frac{27}{8}\] |
| Answer» D. \[\frac{27}{8}\] | |
| 1153. |
Evaluate the product \[{{5}^{1/4}}\times {{(125)}^{0.25}}\]. |
| A. | \[\sqrt{5}\] |
| B. | \[5\] |
| C. | \[5\sqrt{5}\] |
| D. | \[25\] |
| Answer» C. \[5\sqrt{5}\] | |
| 1154. |
How much is \[\left[ {{10}^{150}}\div {{10}^{146}} \right]\]? |
| A. | \[1000\] |
| B. | \[10000\] |
| C. | \[100000\] |
| D. | \[{{10}^{6}}\] |
| Answer» C. \[100000\] | |
| 1155. |
What is the value of \[{{\left( \frac{-1}{216} \right)}^{-2/3}}\]? |
| A. | \[36\] |
| B. | \[-36\] |
| C. | \[\frac{1}{36}\] |
| D. | \[\frac{-1}{36}\] |
| Answer» B. \[-36\] | |
| 1156. |
The value of x so that \[{{\left( \frac{2}{7} \right)}^{4}}.{{\left( \frac{2}{7} \right)}^{3}}={{\left( \frac{2}{7} \right)}^{4x-1}}\] is |
| A. | 1 |
| B. | 2 |
| C. | 3 |
| D. | 4 |
| Answer» C. 3 | |
| 1157. |
The size of a red blood cell is\[0.000007\text{ }m\] . The size of a plant cell is\[0.00001275\text{ }m\]. Compare them. |
| A. | \[\frac{1}{2}\] |
| B. | \[\frac{1}{4}\] |
| C. | \[\frac{1}{5}\] |
| D. | \[-\frac{1}{5}\] |
| Answer» B. \[\frac{1}{4}\] | |
| 1158. |
A box has 5 books, each 20 mm thick and 5 cards each 0.016 mm thick. What is the total thickness? |
| A. | \[1.0008\times {{10}^{4}}mm\] |
| B. | \[1.008\times {{10}^{3}}mm\] |
| C. | \[1.0008\times {{10}^{2}}mm\] |
| D. | \[1.0008\times {{10}^{5}}mm\] |
| Answer» D. \[1.0008\times {{10}^{5}}mm\] | |
| 1159. |
Which of the following has the same value of \[{{\mathbf{3}}^{6}}\times {{\left( {{\mathbf{3}}^{-\mathbf{2}}} \right)}^{2}}\times {{\left( {{\mathbf{2}}^{\mathbf{3}}} \right)}^{2}}\times {{\left( {{\mathbf{2}}^{-\mathbf{2}}} \right)}^{\mathbf{3}}}\] |
| A. | \[{{9}^{{}^\circ }}\] |
| B. | 9 |
| C. | \[{{9}^{2}}\] |
| D. | \[{{9}^{3}}\] |
| Answer» C. \[{{9}^{2}}\] | |
| 1160. |
Find the value of n if \[\frac{{{2}^{n}}\times {{2}^{6}}}{{{2}^{-3}}}={{2}^{18}}\] |
| A. | 7 |
| B. | 8 |
| C. | 9 |
| D. | 10 |
| Answer» D. 10 | |
| 1161. |
The size of a plant cell is\[0.00001275\text{ }m\]. Express this size in standard form. |
| A. | \[1.25\times {{10}^{8}}m\] |
| B. | \[1.275\times {{10}^{5}}m\] |
| C. | \[1.275\times {{10}^{-8}}m\] |
| D. | \[1.275\times {{10}^{-5}}m\] |
| Answer» E. | |
| 1162. |
Find the value of m in the expression \[\frac{{{\left( 16 \right)}^{2m+1}}{{\left( 64 \right)}^{5}}}{{{\left( 256 \right)}^{2}}\times 4}={{\left( 256 \right)}^{3m}}\] |
| A. | 1 |
| B. | 0 |
| C. | 4 |
| D. | 5 |
| Answer» B. 0 | |
| 1163. |
The value of \[x+x({{x}^{x}})\] at \[x=2\] is __. |
| A. | 10 |
| B. | 16 |
| C. | 18 |
| D. | 36 |
| Answer» B. 16 | |
| 1164. |
What is the usual form of\[1.0001\times {{10}^{9}}\]? |
| A. | \[100010000\] |
| B. | \[1000100000\] |
| C. | \[10001000000000\] |
| D. | \[10001000000\] |
| Answer» C. \[10001000000000\] | |
| 1165. |
\[{{\left[ {{\left( \frac{2}{13} \right)}^{-6}}\div {{\left( \frac{2}{13} \right)}^{3}} \right]}^{3}}\times {{\left( \frac{2}{13} \right)}^{-9}}\] |
| A. | \[{{\left( \frac{2}{13} \right)}^{36}}\] |
| B. | \[{{\left( \frac{2}{13} \right)}^{-36}}\] |
| C. | \[{{\left( \frac{2}{13} \right)}^{-36}}\] |
| D. | \[{{\left( \frac{2}{13} \right)}^{-36}}\] |
| Answer» E. | |
| 1166. |
For any two non-zero rational numbers x and \[y,{{x}^{4}}\div {{y}^{4}}\]is equal to |
| A. | \[{{(x\div y)}^{0}}\] |
| B. | \[{{(x\div y)}^{1}}\] |
| C. | \[{{(x\div y)}^{4}}\] |
| D. | \[{{(x\div y)}^{8}}\] |
| Answer» D. \[{{(x\div y)}^{8}}\] | |
| 1167. |
What is the value of \[({{6}^{-1}}-{{8}^{-1}})+{{({{2}^{-1}}-{{3}^{-1}})}^{-1}}\]? |
| A. | \[25\] |
| B. | \[30\] |
| C. | \[35\] |
| D. | \[40\] |
| Answer» C. \[35\] | |
| 1168. |
\[{{\left( -9 \right)}^{3}}\div {{\left( -9 \right)}^{8}}\] is equal to |
| A. | (9)5 |
| B. | \[{{\left( 9 \right)}^{-5}}\] |
| C. | \[{{\left( -9 \right)}^{5}}\] |
| D. | \[{{\left( -9 \right)}^{-5}}\] |
| Answer» E. | |
| 1169. |
What is the number to be multiplied by \[{{(-7)}^{-1}}\] so as to get \[{{10}^{-1}}\] as the product? |
| A. | \[\frac{-7}{10}\] |
| B. | \[\frac{7}{10}\] |
| C. | \[\frac{9}{10}\] |
| D. | \[\frac{-3}{10}\] |
| Answer» B. \[\frac{7}{10}\] | |
| 1170. |
If \[{{2}^{2x-y}}=32\] and \[{{2}^{x+y}}=16\] then find \[{{\mathbf{x}}^{\mathbf{2}}}+{{\mathbf{y}}^{\mathbf{2}}}\]is equal to |
| A. | 9 |
| B. | 10 |
| C. | 11 |
| D. | 13 |
| Answer» C. 11 | |
| 1171. |
If \[a=({{2}^{-2}}-{{2}^{-3}})\], \[b=({{2}^{-3}}-{{2}^{-4}})\] and\[c=({{2}^{-4}}-{{2}^{-2}})\] then find : (i) \[{{a}^{3}}+{{b}^{3}}+{{c}^{3}}\] (ii) \[10\text{ abc}\] |
| A. | (i) (ii) 9/2048 7/2048 |
| B. | (i) (ii) 3/1024 5/2048 |
| C. | (i) (ii) -3/1024 -10/2048 |
| D. | (i) (ii) -9/2048 -15/1024 |
| Answer» E. | |
| 1172. |
Find the value of\[\frac{1}{1+{{x}^{a-b}}}+\frac{1}{1+{{x}^{b-a}}}\] |
| A. | 0 |
| B. | \[-\]1 |
| C. | 1 |
| D. | \[{{x}^{a+b}}\] |
| Answer» D. \[{{x}^{a+b}}\] | |
| 1173. |
Match the following. Column - I Column - II (P) \[{{\left( {{6}^{-1}}+{{\left( \frac{3}{2} \right)}^{-1}} \right)}^{-1}}\] (i) \[-\frac{4}{13}\] (Q) \[{{\left\{ {{\left( \frac{4}{3} \right)}^{-1}}{{\left( \frac{1}{4} \right)}^{-1}} \right\}}^{-1}}\] (ii) \[\frac{9}{32}\] (R) \[\left[ {{\left( \frac{1}{3} \right)}^{-3}}-{{\left( \frac{1}{2} \right)}^{-3}} \right]\div {{\left( \frac{1}{4} \right)}^{-3}}\] (iii) \[\frac{6}{5}\] (S) \[({{3}^{-1}}\times {{4}^{-1}})\times {{\left( \frac{2}{3} \right)}^{-3}}\] (iv) \[\frac{19}{64}\] |
| A. | (P)\[\to \](iii); (Q)\[\to \](i); (R)\[\to \](iv); (S)\[\to \](ii) |
| B. | (P)\[\to \](iv): (Q)\[\to \](i); (R)\[\to \](ii); (S)\[\to \](iii) |
| C. | (P)\[\to \](ii); (Q)\[\to \](iii); (R)\[\to \](iv); (S)\[\to \](i) |
| D. | (P)\[\to \](iii); (Q)\[\to \](i); (R)\[\to \](ii); (S)\[\to \](iv) |
| Answer» B. (P)\[\to \](iv): (Q)\[\to \](i); (R)\[\to \](ii); (S)\[\to \](iii) | |
| 1174. |
Find \[{{(0.000064)}^{5/4}}\times {{(0.04)}^{5/4}}\]. |
| A. | \[{{2}^{10}}{{.10}^{10}}\] |
| B. | \[{{2}^{10}}{{.10}^{-10}}\] |
| C. | \[{{2}^{-10}}{{.10}^{10}}\] |
| D. | \[{{2}^{-10}}{{.10}^{-10}}\] |
| Answer» C. \[{{2}^{-10}}{{.10}^{10}}\] | |
| 1175. |
If \[{{\mathbf{2}}^{\mathbf{2}n-}}^{\mathbf{3}}=\mathbf{2048}\], then \[\left( 4n+3{{n}^{2}} \right)=\]________ |
| A. | 175 |
| B. | 25 |
| C. | 125 |
| D. | 75 |
| Answer» B. 25 | |
| 1176. |
Fill in the blanks. (i) If \[{{m}^{2}}={{27}^{2/3}}\times {{16}^{-3/2}}\]then m = P . (ii) If \[ab=1\]then \[\frac{1}{1+{{a}^{-1}}}+\frac{1}{1+{{b}^{-1}}}=\] Q . (iii) If x = \[({{8}^{2/3}}\cdot {{32}^{-2/5}})\]then \[{{x}^{-5}}=\] R |
| A. | P Q R 5/4 0 10/7 |
| B. | P Q R 1 1 5/16 |
| C. | P Q R 3/8 1 1 |
| D. | P Q R 7/8 0 7/8 |
| Answer» D. P Q R 7/8 0 7/8 | |
| 1177. |
If xyz = 0, then find the value of \[{{({{a}^{x}})}^{zy}}+{{({{a}^{y}})}^{zx}}+{{({{a}^{z}})}^{xy}}\] |
| A. | 3 |
| B. | 2 |
| C. | 1 |
| D. | 0 |
| Answer» B. 2 | |
| 1178. |
Solve for y, if \[\frac{{{\left( \frac{1}{9} \right)}^{2y-1}}{{(.0081)}^{1/3}}}{\sqrt{243}}={{\left( \frac{1}{3} \right)}^{2y-5}}\sqrt[3]{\frac{{{27}^{y-1}}}{10000}}\] |
| A. | \[\frac{1}{2}\] |
| B. | \[-\frac{19}{18}\] |
| C. | \[\frac{3}{10}\] |
| D. | \[\frac{12}{17}\] |
| Answer» C. \[\frac{3}{10}\] | |
| 1179. |
If \[{{3}^{n}}=729,\] find the value of \[{{3}^{3n+1}}\]. |
| A. | \[{{3}^{21}}\] |
| B. | \[{{3}^{10}}\] |
| C. | \[{{3}^{19}}\] |
| D. | \[{{3}^{15}}\] |
| Answer» D. \[{{3}^{15}}\] | |
| 1180. |
If \[{{\left( \mathbf{x}+\mathbf{y} \right)}^{\mathbf{3}}}=\mathbf{1331}\] and\[{{\left( \mathbf{x}-\mathbf{y} \right)}^{\mathbf{5}}}=\mathbf{243}\], then find \[{{\mathbf{x}}^{\mathbf{2}}}-{{\mathbf{y}}^{\mathbf{2}}}.\] |
| A. | 33 |
| B. | 22 |
| C. | 11 |
| D. | 44 |
| Answer» B. 22 | |
| 1181. |
Simplify: \[\frac{{{\left[ \frac{2}{3} \right]}^{3}}\times {{\left[ \frac{2}{3} \right]}^{-2}}\times {{\left[ {{\left( \frac{1}{2} \right)}^{2}} \right]}^{-2}}\times \frac{1}{24}}{{{\left( \frac{2}{3} \right)}^{-5}}\times {{\left( \frac{3}{2} \right)}^{-12}}}\] |
| A. | \[{{\left( \frac{2}{3} \right)}^{-4}}\] |
| B. | \[\frac{32}{3}\] |
| C. | \[\frac{243}{16}\] |
| D. | \[\frac{243}{32}\] |
| Answer» E. | |
| 1182. |
What is the simplified form of \[\frac{{{\left( {{x}^{a+b}} \right)}^{3}}.{{\left( {{x}^{b+c}} \right)}^{3}}.{{\left( {{x}^{c+a}} \right)}^{3}}}{{{\left( {{x}^{a}}.{{x}^{b}}.{{x}^{c}} \right)}^{6}}}\]? |
| A. | \[0\] |
| B. | \[1\] |
| C. | \[{{x}^{a+b+c}}\] |
| D. | \[x\] |
| Answer» C. \[{{x}^{a+b+c}}\] | |
| 1183. |
\[{{\left( \frac{a}{b} \right)}^{x+y+z}}\div \left[ {{\left( \sqrt{\frac{a}{b}} \right)}^{-x}}\times {{\left( \sqrt{\frac{a}{b}} \right)}^{-y}}\times {{\left( \sqrt{\frac{a}{b}} \right)}^{-z}} \right]=\]______ |
| A. | \[{{\left[ {{a}^{3}}/{{b}^{3}} \right]}^{x+y+z}}\] |
| B. | \[{{\left[ {{a}^{2}}/{{b}^{2}} \right]}^{x+y+z}}\] |
| C. | \[{{\left[ a/b \right]}^{\left( x+y+z \right)/2}}\] |
| D. | \[{{\left[ a/b \right]}^{3\left( x+y+z \right)/2}}\] |
| Answer» E. | |
| 1184. |
Weight of moon is \[(7.346\times {{10}^{22}})kg\] and weight of Earth is \[\text{5,9724}\times \text{1}{{\text{0}}^{\text{24}}}\text{ 7 kg}\]. What is the total weight of both in standard form? |
| A. | \[\text{6}\text{.04}\times \text{1}{{\text{0}}^{\text{24}}}\text{kg}\] |
| B. | \[\text{7}\text{.08}\times \text{1}{{\text{0}}^{\text{22}}}\text{kg}\] |
| C. | \[\text{5}\text{.98}\times \text{1}{{\text{0}}^{24}}\text{kg}\] |
| D. | \[\text{6}\text{.44}\times \text{1}{{\text{0}}^{\text{24}}}\text{ kg}\] |
| Answer» B. \[\text{7}\text{.08}\times \text{1}{{\text{0}}^{\text{22}}}\text{kg}\] | |
| 1185. |
The value of the expression \[\frac{{{4}^{-5}}\times {{10}^{6}}\times 625}{{{4}^{-8}}\times {{4}^{2}}}\] is given by |
| A. | \[2.5\times {{10}^{9}}\] |
| B. | \[3.5\times {{10}^{5}}\] |
| C. | \[4.5\times {{10}^{5}}\] |
| D. | \[5.5\times {{10}^{5}}\] |
| Answer» B. \[3.5\times {{10}^{5}}\] | |
| 1186. |
What is the solution of \[{{3}^{3x-5}}=\frac{1}{{{9}^{x}}}\]? |
| A. | \[\frac{5}{2}\] |
| B. | \[5\] |
| C. | \[1\] |
| D. | \[\frac{7}{3}\] |
| Answer» D. \[\frac{7}{3}\] | |
| 1187. |
\[{{\left( \frac{{{a}^{x}}}{{{a}^{y}}} \right)}^{z}}\times {{\left( \frac{{{a}^{y}}}{{{a}^{z}}} \right)}^{x}}\times {{\left( \frac{{{a}^{z}}}{{{a}^{x}}} \right)}^{y}}=\]__________. \[\left( a\ne 0\,\mathbf{and}\,\mathbf{a}\ne 1 \right)\]) |
| A. | 1 |
| B. | 0 |
| C. | \[{{a}^{xyz}}\] |
| D. | \[{{a}^{xy+yz+zx}}\] |
| Answer» B. 0 | |
| 1188. |
At the end of the 20th century, the world's population was approximately\[6.125\times {{10}^{9}}\]. Express this population in usual form. |
| A. | \[6.125\times {{10}^{10}}\] |
| B. | 6125000000 |
| C. | \[6125\times {{10}^{5}}\] |
| D. | 612500000 |
| Answer» C. \[6125\times {{10}^{5}}\] | |
| 1189. |
Give the simplified form of \[\frac{{{3}^{a}}{{4}^{a-2}}{{25}^{a+1}}}{{{9}^{a-1}}{{2}^{a+1}}{{5}^{a-2}}}\]. |
| A. | \[{{3}^{a-2}}{{.2}^{a-5}}{{.5}^{a+4}}\] |
| B. | \[{{2}^{a-5}}{{.3}^{a+2}}{{.5}^{a+4}}\] |
| C. | \[{{2}^{a+5}}{{.3}^{a+2}}{{.5}^{a+4}}\] |
| D. | \[{{2}^{a-5}}{{.3}^{-a22}}{{.5}^{a+4}}\] |
| Answer» C. \[{{2}^{a+5}}{{.3}^{a+2}}{{.5}^{a+4}}\] | |
| 1190. |
If \[{{\mathbf{3}}^{-\mathbf{x}}}=\mathbf{3000},\] then find \[\mathbf{1}{{\mathbf{0}}^{\mathbf{3}}}\times {{3}^{\left( 2x+3 \right)}}\] |
| A. | \[3\times {{10}^{-3}}\] |
| B. | \[27\times {{10}^{-3}}\] |
| C. | \[9\times {{10}^{-3}}\] |
| D. | 3000 |
| Answer» B. \[27\times {{10}^{-3}}\] | |
| 1191. |
The cell of bacteria doubles itself after every 1 hour. How many cells will there be after 8 hours? |
| A. | 200 times of the original |
| B. | \[{{\text{2}}^{\text{10}}}\] times of the original |
| C. | \[{{\text{2}}^{\text{8}}}\] times of the original |
| D. | \[{{\text{2}}^{\text{6}}}\] times of the original |
| Answer» D. \[{{\text{2}}^{\text{6}}}\] times of the original | |
| 1192. |
Find the value of \[\frac{1}{1+{{x}^{-m}}}+\frac{1}{1+{{x}^{m}}}.\] |
| A. | \[0\] |
| B. | \[{{x}^{m}}\] |
| C. | \[1\] |
| D. | \[{{x}^{-m}}\] |
| Answer» D. \[{{x}^{-m}}\] | |
| 1193. |
The product of \[\sqrt[3]{2}\times \sqrt[4]{3}\] is given |
| A. | \[\sqrt{10}\] |
| B. | 1 |
| C. | \[\sqrt[12]{432}\] |
| D. | \[\sqrt{201}\] |
| Answer» D. \[\sqrt{201}\] | |
| 1194. |
Pluto is 5913000000 km away from the Sun. Express this distance in standard form. |
| A. | \[5.913\times {{10}^{-11}}\] |
| B. | \[5.913~\times {{10}^{-9}}\] |
| C. | \[\text{5}\text{.913}\times \text{1}{{\text{0}}^{\text{6}}}\] |
| D. | \[\text{5}\text{.913}\times \text{1}{{\text{0}}^{9}}\] |
| Answer» E. | |
| 1195. |
Compute \[\frac{{{(64)}^{-1/6}}\times {{(216)}^{-1/3}}\times {{(81)}^{1/4}}}{{{(512)}^{-1/3}}\times {{(16)}^{1/4}}\times {{(9)}^{-1/2}}}\] |
| A. | \[3\] |
| B. | \[6\] |
| C. | \[1\] |
| D. | \[-6\] |
| Answer» B. \[6\] | |
| 1196. |
Find \[x\], if \[{{\left( \frac{5}{11} \right)}^{-3}}\times {{\left( \frac{5}{11} \right)}^{5}}={{\left( \frac{5}{11} \right)}^{x}}\] |
| A. | 3 |
| B. | 4 |
| C. | 8 |
| D. | 2 |
| Answer» E. | |
| 1197. |
If \[{{(25)}^{{}}}={{(125)}^{y}},\]find \[x:y\]. |
| A. | \[1:1\] |
| B. | \[2:3\] |
| C. | \[3:2\] |
| D. | \[1:3\] |
| Answer» D. \[1:3\] | |
| 1198. |
Find x so that \[{{\left( \frac{5}{3} \right)}^{-5}}\times {{\left( \frac{5}{3} \right)}^{-11}}={{\left( \frac{5}{3} \right)}^{8x}}\] |
| A. | \[-\,4\] |
| B. | \[-\,2\] |
| C. | \[-\,6\] |
| D. | \[-\,8\] |
| Answer» C. \[-\,6\] | |
| 1199. |
Number of prime factors in \[{{(216)}^{\frac{3}{5}}}\times {{(2500)}^{\frac{2}{5}}}\times {{(300)}^{\frac{1}{5}}}\] is _______. |
| A. | 6 |
| B. | 9 |
| C. | 8 |
| D. | None of these |
| Answer» E. | |
| 1200. |
Evaluate \[\frac{{{(-1)}^{13}}}{{{2}^{3}}}+\frac{{{2}^{3}}-{{1}^{10}}+{{3}^{2}}}{{{3}^{2}}-{{2}^{2}}}+{{\left( \frac{7}{11} \right)}^{3}}\div \frac{98}{121}\]. |
| A. | \[3\frac{173}{440}\] |
| B. | \[3\frac{17}{44}\] |
| C. | \[3\frac{137}{440}\] |
| D. | \[3\frac{21}{440}\] |
| Answer» B. \[3\frac{17}{44}\] | |