Solve for y, if \[\frac{{{\left( \frac{1}{9} \right)}^{2y-1}}{{(.0081)}^{1/3}}}{\sqrt{243}}={{\left( \frac{1}{3} \right)}^{2y-5}}\sqrt[3]{\frac{{{27}^{y-1}}}{10000}}\]

• A.  \[\frac{1}{2}\]                                   
• B.  \[-\frac{19}{18}\]     
• C.  \[\frac{3}{10}\]                     
• D.         \[\frac{12}{17}\]