MCQOPTIONS
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MCQOPTIONS
This section includes 843 Mcqs, each offering curated multiple-choice questions to sharpen your Materials Science and Manufacturing Engineering knowledge and support exam preparation. Choose a topic below to get started.
| 751. |
For the CNC part programming, match Group A with Group B: |
| A. | P-II, Q-III, R-I, S-IV |
| B. | p -I, Q-III, R-II, S-IV |
| C. | P-I, Q-IV, R-II, S-III |
| D. | p-II, Q-I, R-III, S-IV |
| Answer» B. p -I, Q-III, R-II, S-IV | |
| 752. |
Solidification time of a metallic alloy casting is |
| A. | Directly proportional to its surface area |
| B. | Inversely proportional to the specific heat of the cast material |
| C. | Inversely proportional to the thermal diffusivity of the mould material |
| D. | Inversely proportional to the pouring temp |
| Answer» E. | |
| 753. |
In sand casting of hollow part of lead, a cylindrical core of diameter 120 mm and height 180 mm is placed inside the mould cavity. The densities of core material and lead are 1600 kg/m and 11300 kg/m respectively. The net force (in N) that tends to lift the core during pouring of molten metal will be |
| A. | 19.7 |
| B. | 64.5 |
| C. | 193.7 |
| D. | 257.6 |
| Answer» D. 257.6 | |
| 754. |
The mould filling time is seconds is |
| A. | 2.8 |
| B. | 5.78 |
| C. | 7.54 |
| D. | 8.41 |
| Answer» C. 7.54 | |
| 755. |
A cast Steel slab of dimension 30 20 5 cm is poured horizontally using a side riser. The riser is cylindrical in shape with diameter and height, both equal to D. The freezing ratio of the mould is |
| A. | 8D/75 |
| B. | 4D/75 |
| C. | 75/8D |
| D. | 75/4D |
| Answer» B. 4D/75 | |
| 756. |
The shape factor for a casting in the form of an annular cylinder of outside diameter 30 cm, inside diameter 20 cm and height 30 cm (correction factor k = 1.0) will be |
| A. | 21.77 |
| B. | 6.28 |
| C. | 9.42 |
| D. | 12.28 |
| Answer» B. 6.28 | |
| 757. |
The flow stress (in MPa) of a material is given by = 500 0.1 |
| A. | 98.157mm |
| B. | 85.157mm |
| C. | 95.157mm |
| D. | 95mm |
| Answer» D. 95mm | |
| 758. |
Match the correct combination for following metal working processes. Processes |
| A. | P-2, Q-1, R-3, S-4 |
| B. | P-3, Q-4, R-1, S-5 |
| C. | P-5, Q-3, R-3, S-1 |
| D. | P-3, Q-1, R-2, S-4 |
| Answer» E. | |
| 759. |
Increase in water content in moulding sand causes |
| A. | flowability to go through a maxima |
| B. | permeability to go through a maxima |
| C. | compressive strength to go through a maxima |
| D. | strength to go through a maxima |
| Answer» C. compressive strength to go through a maxima | |
| 760. |
A 25 mm hole is pierced in at = 2.5 mm thick steel sheet having shear strength = 350 MPa. If the diametral clearance is given by the expression c = 0.0064 |
| A. | 25.0, 25.3, 171.8 |
| B. | 25.0, 24.7, 68.75 |
| C. | 24.7, 25.0, 171.8 |
| D. | 25.3, 25.0, 68.75 |
| Answer» E. | |
| 761. |
The current in Amperes used in resistance spot welding of plain carbon steel sheets (1 to 3 mm thick) lies within the range |
| A. | 10-50 |
| B. | 50-500 |
| C. | 500-5000 |
| D. | 5000-5000 |
| Answer» E. | |
| 762. |
A disc of 200 mm diameter is blanked from a strip of an aluminum alloy of thickness 3.2 mm. The material shear strength to fracture is 150 MPa. The blanking force (in kN) is |
| A. | 291 |
| B. | 301 |
| C. | 311 |
| D. | 421 |
| Answer» C. 311 | |
| 763. |
The maximum drawing force is |
| A. | 0.047 MN |
| B. | 0.082 MN |
| C. | 0.83 MN |
| D. | 9.69 MN |
| Answer» C. 0.83 MN | |
| 764. |
Consider the following statements : The size of the heat affected zone (HAZ) will increase with |
| A. | 1, 2 and 3 |
| B. | 1 and 3 |
| C. | 1 and 4 |
| D. | 2 and 3 |
| Answer» C. 1 and 4 | |
| 765. |
It is require to punch a hole of diameter 10 mm on a sheet of thickness 3 mm. The shear strength of the work material is 420 MPa. The required punch force is |
| A. | 19.78 kN |
| B. | 39.58 kN |
| C. | 98.9 kN |
| D. | 395.6 kN |
| Answer» C. 98.9 kN | |
| 766. |
Resistance spot welding is performed on two plates of 1.5 mm thickness with 6 mm diameter electrode, using 15000 A current for a time duration of 0.25 sec. Assuming the interface resistance to be 0.0001 ohms. The heat generated to form the weld is |
| A. | 5625 W-sec |
| B. | 8437 W-sec |
| C. | 22500 W-sec |
| D. | 33750 W-sec |
| Answer» B. 8437 W-sec | |
| 767. |
Which of the following welding process results in the smallest heat affected zone? |
| A. | Shielded metal arc welding |
| B. | Gas welding |
| C. | Laser beam welding |
| D. | Thermit welding |
| Answer» D. Thermit welding | |
| 768. |
During a steady gas metal arc welding with direct current electrode positive polarity, the welding current, voltage and weld speed are 150 A, 30 V and 6 m/min respectively. A metallic wire electrode of diameter 1.2 mm is being fed at a constant rate of 12 m/min. The density, specific heat and melting temp of the wire electrode are 7000 kg/m3, 500 J/kg and 1530 C respectively. Assume the ambient temp to be 30 C and neglect the latent heat of melting. Further consider that 2/3rd of the total electrical power is available for melting of the wire electrode. The melting efficiency (in percentage) of the wire electrode is |
| A. | 39.58 |
| B. | 45.25 |
| C. | 49.38 |
| D. | 54.98 |
| Answer» B. 45.25 | |
| 769. |
A 31.8 MM HSS drill is used to drill a hole in cast iron block 100 mm thick at cutting speed of 20 m/min and feed 0.3 mm/rev. If the over travel of drill is 4 mm and approach 9 mm, the time required to drill the hole is |
| A. | 1 min 40 s |
| B. | 1 min 44 s |
| C. | 1 min 49 s |
| D. | 1 min 53 s |
| Answer» E. | |
| 770. |
The velocity (in m/min) with which the chip flows on the tool face is |
| A. | 32 |
| B. | 63 |
| C. | 22 |
| D. | 27.5 |
| Answer» E. | |
| 771. |
During the above operation, the drill wears out after producing 200 holes.Taylor's tool life equation is of the form VT |
| A. | 15 |
| B. | 72 |
| C. | 93 |
| D. | 490 |
| Answer» C. 93 | |
| 772. |
The number of tool changes required to machine the whole batch is |
| A. | 138 |
| B. | 270 |
| C. | 62 |
| D. | 61 |
| Answer» C. 62 | |
| 773. |
Applying Taylor's equation VT |
| A. | 20.36 |
| B. | 22.43 |
| C. | 674 |
| D. | 28.20 |
| Answer» D. 28.20 | |
| 774. |
The rake angle of a cutting tool is 15 , shear angle 45 and cutting velocity 35 m/min. What is the velocity of chip along the tool face? |
| A. | 28.5 m/min |
| B. | 27.3 m/min |
| C. | 25.3 m/min |
| D. | 23.5 m/min |
| Answer» B. 27.3 m/min | |
| 775. |
A cylinder of 25 mm diameter and 100 mm length is turned with a tool, for which the relation VT |
| A. | 12 |
| B. | 22 |
| C. | 43 |
| D. | 85 |
| Answer» E. | |
| 776. |
The shear angle (in degrees) is |
| A. | 26.8 |
| B. | 27.8 |
| C. | 28.8 |
| D. | 29.8 |
| Answer» D. 29.8 | |
| 777. |
Machining time (in min) per hole will be |
| A. | 0.08 |
| B. | 0.31 |
| C. | 0.44 |
| D. | 0.86 |
| Answer» D. 0.86 | |
| 778. |
Friction angle during machining will be |
| A. | 22.6 |
| B. | 32.6 |
| C. | 57.1 |
| D. | 67.4 |
| Answer» B. 32.6 | |
| 779. |
If the friction angle at the tool chip interface is 58 10' and the cutting force components measured by a dynamometer are 600 N and 200 N, the power loss due to friction (in kNm/ min) is approximately |
| A. | 20 |
| B. | 18 |
| C. | 16 |
| D. | 350 |
| Answer» E. | |
| 780. |
For cutting double start screw threads of pitch 1.0 mm on a lathe, the thread cutting tool should have a feed rate of |
| A. | 0.5 mm/rev |
| B. | 1.0 mm/rev |
| C. | 2.0 mm/rev |
| D. | 4.0 mm/rev |
| Answer» D. 4.0 mm/rev | |
| 781. |
The ideal cutting fluid for low speed machining of metals should be one which |
| A. | removes the heat faster from the cutting zone |
| B. | forms a coating on the cutting tools by Chemical reaction |
| C. | forms a low shear strength film of work material at the tool chip interface |
| D. | serves as a dielectric, minimizing thereby reactions due to EMF at the interface |
| Answer» B. forms a coating on the cutting tools by Chemical reaction | |
| 782. |
In a shaping process, the number of double strokes per minute is 30 and the quick return ratio is 0.6. If the length of the stroke is 250 mm, the average cutting velocity in mm/min. |
| A. | 3.0 |
| B. | 4.5 |
| C. | 7.5 |
| D. | 12.0 |
| Answer» E. | |
| 783. |
The ultimate shear stress (in N/mm ) of the work material is |
| A. | 235 |
| B. | 139 |
| C. | 564 |
| D. | 380 |
| Answer» E. | |
| 784. |
The chip velocity (in m/min) is |
| A. | 8 |
| B. | 10 |
| C. | 12 |
| D. | 14 |
| Answer» C. 12 | |
| 785. |
Observation of a slip gauge on flatness interferometer produced fringe counts numbering 10 and 14 for two readings.The second reading is taken by rotating the setup by 180 . Assume that both faces of the slip gauge are flat and the wavelength of the radiation is 0.5086 m. The parallelism error (in m) between the two faces of the slip gauge is |
| A. | 0.2543 |
| B. | 1.172 |
| C. | 0.5086 |
| D. | 0.800 |
| Answer» D. 0.800 | |
| 786. |
To measure the effective diameter of an external metric thread (included angle is 60 ) of 3.5 mm pitch, a cylindrical standard of 30.5 mm diameter and two wires of 2 mm diameter each are used. The micrometer reading over the standard and over the wires are 16.532 mm and 15.398 mm respectively. The effective diameter (in mm) of the thread is |
| A. | 33.336 |
| B. | 30.397 |
| C. | 29.366 |
| D. | 26.397 |
| Answer» C. 29.366 | |
| 787. |
A small bore is designated 25H7. The lower (minimum) and upper (maximum) limits of the . bore are 25.000 mm and 25.021 respectively. When the bore is designated as 25H8, then the upper limit is 25.033 mm. When the bore is designated as 25H6, then the upper limit of the bore in mm is |
| A. | 25.001 |
| B. | 25.005 |
| C. | 25.009 |
| D. | 25.013 |
| Answer» E. | |
| 788. |
The following data are given for calculating limits of dimension and tolerances for a hole: Tolerance unit i (microns) = 0.45 (D |
| A. | 24.984 and 24.967 |
| B. | 25.017 and 24.984 |
| C. | 25.033 and 25.00 |
| D. | 25.00, 24.967 |
| Answer» D. 25.00, 24.967 | |
| 789. |
Among the conventional machining processes, maximum specific energy is consumed in |
| A. | Turning |
| B. | Drilling |
| C. | Planning |
| D. | Grinding |
| Answer» E. | |
| 790. |
Cutting power consumption in turning can be significantly reduced by |
| A. | Increasing rake angle of the tool |
| B. | Increasing cutting angle of the tool |
| C. | Widening the nose radius of the tool |
| D. | Increasing the clearance angle |
| Answer» B. Increasing cutting angle of the tool | |
| 791. |
A grinding wheel A 27 K 7 V is specified for finish grinding of a HSS cutting tool. What do you understand about the wheel from the above code. Is this an appropriate choice? |
| A. | yes |
| B. | no, because abrasive is not correct |
| C. | no, grain size is not correct |
| D. | no, because grade is not correct choice |
| Answer» D. no, because grade is not correct choice | |
| 792. |
A milling cutter having 8 teeth is rotating at 150 rpm. If the feed per tooth is 0.1 mm, the speed in mm per minute is |
| A. | 120 |
| B. | 187 |
| C. | 125 |
| D. | 70 |
| Answer» B. 187 | |
| 793. |
In a single pass turning operation the cutting speed is the only variable based on the cutting time cost and the cutting edge cost. The tool life for minimum cost given that cost of 1 cutting edge is Rs. 5, operator wages including the machine tool cost is Rs. 75/hour and tool life equation is VT0.1 is 100 |
| A. | 10 |
| B. | 17 |
| C. | 29 |
| D. | 36 |
| Answer» E. | |
| 794. |
A workpiece of 2000 mm length and 300 mm width was machined by a planning operation with the feed set at 0.3 mm/stroke. If the machine tool executes 10 double strokes/min, the planning time for a single pass will be |
| A. | 50 min |
| B. | 100 min |
| C. | 200 min |
| D. | 220 min |
| Answer» C. 200 min | |
| 795. |
In a cutting test with 0.3 mm flank wear as tool failure criterion, a tool life of 10 min was obtained at a cutting velocity of 20 m/min. Taking tool life exponent as 0.25, the tool life in minutes at 40 m/min of cutting velocity will be |
| A. | 0.506 |
| B. | 0.625 |
| C. | 3.140 |
| D. | 5.002 |
| Answer» C. 3.140 | |
| 796. |
For spot welding of two steel sheets (base metal) each of 3 mm thickness, welding current of 10000 A is applied for 0.2 s. The heat dissipated to the base metal is 1000 J. Assuming that the heat required for melting 1 mm volume of steel is 20 J and interfacial contact resistance between sheets is 0.0002 ohms, the volume (in mm ) of weld nugget is. |
| A. | 180mm |
| B. | 50mm |
| C. | 150mm |
| D. | 60mm |
| Answer» D. 60mm | |
| 797. |
Determine the load required to punch a 20 mm diameter hole in 2 mm thick sheet. The properties of the material of the sheet are: Tensile strength 580 MPa |
| A. | 31.40 |
| B. | 43.98 |
| C. | 64.40 |
| D. | 91.10 |
| Answer» C. 64.40 | |
| 798. |
A hole of 40 mm diameter is pierced in a steel sheet of 4 mm thickness without shear on the tool. Shear strength of steel is 400 N/mm and penetration is 25%. What is the expected percentage load reduction if a shear of 1 mm is provided on the punch? |
| A. | 25.00 |
| B. | 33.33 |
| C. | 50.00 |
| D. | 66.67 |
| Answer» D. 66.67 | |
| 799. |
A 10 mm deep cylindrical cup with diameter of 15 mm is drawn from a circular blank. Neglecting the variation in the sheet thickness, the diameter (upto 2 decimal points accuracy) of the blank is mm. |
| A. | 24.72 mm |
| B. | 48.79 mm |
| C. | 28.72 mm |
| D. | 38.76 mm |
| Answer» D. 38.76 mm | |
| 800. |
For machining a rectangular island represented by coordinates P(0,0), Q(100,0), fl( 100,50) and S(0,50) on a casting using CNC milling machine, an end mill with a diameter of 16 mm is used. The trajectory of the cutter centre to machine the island PQRS is |
| A. | (- 8, - 8), (108, - 8), (108,58), (- 8,58), (- 8, -8) |
| B. | (8,8), (94,8), (94,44), (8,44), (8,8) |
| C. | (- 8,8), (94,0), (94,44), (8,44), (- 8,8) |
| D. | (0,0), (100,0), (100,50), (50,0), (0,0) |
| Answer» B. (8,8), (94,8), (94,44), (8,44), (8,8) | |