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This section includes 9294 Mcqs, each offering curated multiple-choice questions to sharpen your Engineering knowledge and support exam preparation. Choose a topic below to get started.
| 3851. |
Consider the following features: negative operands cannot be usedwhen immediate operand changes, the program should be reassembledthe program is difficult to readthe size of operand is restricted by word length of the computer Disadvantages of immediate addressing include |
| A. | 1 and 2 |
| B. | 2 and 4 |
| C. | 2 and 3 |
| D. | 1 and 4 |
| Answer» C. 2 and 3 | |
| 3852. |
In magnetic film memory, the memory element consits of |
| A. | plated wires |
| B. | superconductive material |
| C. | nickel iron alloy |
| D. | doped aluminium |
| Answer» D. doped aluminium | |
| 3853. |
Which device changes serial data to parallel data? |
| A. | Counter |
| B. | Multiplexer |
| C. | Demultiplexer |
| D. | Flip flop |
| Answer» D. Flip flop | |
| 3854. |
Which binary addition is incorrect? |
| A. | 1101.1 + 1011.1 = 11001.0 |
| B. | 101101 + 1101101 + 1100011 |
| C. | 0.0011 + 0.1110 + 1.0001 |
| D. | 1100.001 + 1011.011 = 10111.100 |
| Answer» E. | |
| 3855. |
CD4010 is a |
| A. | inverting buffer |
| B. | non-inverting hex buffer |
| C. | NOR IC |
| D. | NAND IC |
| Answer» C. NOR IC | |
| 3856. |
What is the terminal count in decimal form? |
| A. | 1579 |
| B. | 1681 |
| C. | 1881 |
| D. | 2014 |
| Answer» B. 1681 | |
| 3857. |
In the generic microprocessor |
| A. | instruction cycle time period is shorter than machine cycle time period |
| B. | machine cycle time period is shorter than instruction cycle time period |
| C. | instruction cycle time period is exactly half of machine cycle time period |
| D. | instruction cycle time period is exactly equal to machine cycle time period |
| Answer» C. instruction cycle time period is exactly half of machine cycle time period | |
| 3858. |
In floating point representation, mantissa is expressed in |
| A. | excess 3 notation |
| B. | gray code |
| C. | excess 32 notation |
| D. | 2's complement |
| Answer» D. 2's complement | |
| 3859. |
Which of the circuits in the given figure that converts JK flip flop to T flip flop? |
| A. | <img src="/_files/images/electronics-and-communication-engineering/digital-electronics/29-391-1.png"> |
| B. | <img src="/_files/images/electronics-and-communication-engineering/digital-electronics/29-391-2.png"> |
| C. | <img src="/_files/images/electronics-and-communication-engineering/digital-electronics/29-391-3.png"> |
| D. | <img src="/_files/images/electronics-and-communication-engineering/digital-electronics/29-391-4.png"> |
| Answer» B. <img src="/_files/images/electronics-and-communication-engineering/digital-electronics/29-391-2.png"> | |
| 3860. |
Consider the following registers: A accumulator and B registerB and C registersD and E registersH and L registers Which of these 8-bit registers of 8085 P can be paired together to make a 16-bit register? |
| A. | 1, 3 and 4 |
| B. | 2, 3 and 4 |
| C. | 1 and 2 |
| D. | 1, 2 and 3 |
| Answer» C. 1 and 2 | |
| 3861. |
Access time of a storage is the time required |
| A. | to write one word into the memory |
| B. | to read one word from the memory |
| C. | to write one word into and to read one word from the memory |
| D. | either to write one word or to read one word |
| Answer» E. | |
| 3862. |
For a D/A converter, inputs and outputs are given. The output corresponding to digital input 01000 |
| A. | 2.0 V |
| B. | 2.5 V |
| C. | 3.0 V |
| D. | 4.0 V |
| Answer» B. 2.5 V | |
| 3863. |
The fetching, decoding and executing of an instruction is broken down into several time intervals. Each of these intervals, involving one or more clock periods, is called a |
| A. | instruction cycle |
| B. | machine cycle |
| C. | process cycle |
| D. | none of the above |
| Answer» C. process cycle | |
| 3864. |
By placing an inverter between both inputs of an S-R flip-flop, the resulting flip-flop becomes |
| A. | J-K flip-flop |
| B. | D-flip-flop |
| C. | T-flip-flop |
| D. | Master salve JK flip-flop |
| Answer» C. T-flip-flop | |
| 3865. |
The output of the circuit shown below will be of the frequency |
| A. | 125 Hz |
| B. | 250 Hz |
| C. | 500 Hz |
| D. | 750 Hz |
| Answer» C. 500 Hz | |
| 3866. |
In the given figure Y = |
| A. | A |
| B. | B |
| C. | A + B + C |
| D. | ABC |
| Answer» C. A + B + C | |
| 3867. |
Assertion (A): An encoder converts key dips to binary code.Reason (R): An encoder has more inputs than output. |
| A. | Both A and R are correct and R is correct explanation of A |
| B. | Both A and R are correct but R is not correct explanation of A |
| C. | A is true, R is false |
| D. | A is false, R is true |
| Answer» C. A is true, R is false | |
| 3868. |
If a RAM has 34 bits in its MAR and 16 bits in its MDR, then its capacity will be |
| A. | 32 GB |
| B. | 16 GB |
| C. | 32 MB |
| D. | 16 MB |
| Answer» B. 16 GB | |
| 3869. |
In 8085 microprocessor, how many I/O ports can be accessed by direct method? |
| A. | 8 |
| B. | 256 |
| C. | 32 K |
| D. | 64 K |
| Answer» C. 32 K | |
| 3870. |
If the mantissa of a digital computer is 37 bit long then the accuracy of the digital computer will be of |
| A. | 37 decimal places |
| B. | 23 decimal places |
| C. | 11 decimal places |
| D. | accuracy is independent of the length to mantissa |
| Answer» D. accuracy is independent of the length to mantissa | |
| 3871. |
Bipolar IC memories are fabricated using |
| A. | high density versions of the bipolar transistor flip-flop |
| B. | low density versions of the unipolar transistor flip-flop |
| C. | high density versions of the MOSFET |
| D. | low density versions of the MOSFET |
| Answer» B. low density versions of the unipolar transistor flip-flop | |
| 3872. |
A D-flip-flop is |
| A. | dial type flip-flop |
| B. | delay flip-flop |
| C. | differential flip-flop |
| D. | digital flip-flop |
| Answer» C. differential flip-flop | |
| 3873. |
Which of the following flip-flop do not have race problem? |
| A. | T flip-flop |
| B. | D flip-flop |
| C. | JK flip-flop |
| D. | Master-slave flip-flop |
| Answer» E. | |
| 3874. |
It is desired to route data from many registers to one register. The device needed is |
| A. | decoder |
| B. | multiplexer |
| C. | demultiplexer |
| D. | counter |
| Answer» C. demultiplexer | |
| 3875. |
Advanced low power Schottky is a part of |
| A. | ECL family |
| B. | CMOS family |
| C. | TTL family |
| D. | none of the above |
| Answer» D. none of the above | |
| 3876. |
A device that converts from decimal to binary numbered is called |
| A. | decoder |
| B. | encoder |
| C. | CPU |
| D. | converter |
| Answer» C. CPU | |
| 3877. |
It is desired to clean up ragged looking pulsed that have been distorted during transmission from one place to another, which of the following device will be appropriate? |
| A. | Multiplexer |
| B. | D/A converter |
| C. | JK flip-flop |
| D. | Schmitt trigger |
| Answer» E. | |
| 3878. |
Decimal number 9 in gray code = |
| A. | 1100 |
| B. | 1101 |
| C. | 110 |
| D. | 1111 |
| Answer» C. 110 | |
| 3879. |
Binary number 11011.01 when converted to its 2's complement will become |
| A. | 0101.110 |
| B. | 01111.10 |
| C. | 01100.10 |
| D. | 00100.11 |
| Answer» E. | |
| 3880. |
Decimal 45.15 when converted into 9's complement will become |
| A. | 54.84 |
| B. | 45.48 |
| C. | 48.54 |
| D. | 45.84 |
| Answer» B. 45.48 | |
| 3881. |
A five bit binary adder is used to add 01001 and 00111. The adders from LSB position are numbered as FA0, FA1, FA2 and FA3. The outputs of FA2 are |
| A. | SUM = 0 |
| B. | SUM = 0, CARRY = 1 |
| C. | SUM = 1, CARRY = 0 |
| D. | SUM = 1, CARRY = 1 |
| Answer» B. SUM = 0, CARRY = 1 | |
| 3882. |
figure shows a NAND latch used as a switch debouncer. With the switch in STOP position. Q will be equal to |
| A. | 0 |
| B. | 1 |
| C. | CLK |
| D. | none of these |
| Answer» B. 1 | |
| 3883. |
As compared to MOS memories, bipolar memories have |
| A. | slower access time but are cheaper |
| B. | slower access time and are costly |
| C. | faster access time and are cheaper |
| D. | faster access time and are costly |
| Answer» E. | |
| 3884. |
The hexadecimal number BBC7 is equivalent to decimal number |
| A. | 49761 |
| B. | 46791 |
| C. | 47691 |
| D. | 49761 |
| Answer» C. 47691 | |
| 3885. |
In 8085, out of interrupts given below, one particular interrupts is quite different from others, This interrupt is |
| A. | RST 5.5 |
| B. | RST 6.5 |
| C. | RST 7.5 |
| D. | none of these |
| Answer» D. none of these | |
| 3886. |
An A/D converter uses for reference purposes |
| A. | DC voltage |
| B. | a saw tooth generator |
| C. | set of keys |
| D. | a flip-flop |
| Answer» C. set of keys | |
| 3887. |
A seven bit (even parity) code 0010001 may have error. The correct code is |
| A. | 0010001 |
| B. | 1110001 |
| C. | 0011001 |
| D. | 1111110 |
| Answer» D. 1111110 | |
| 3888. |
Which of the following represents the decimal form of binary 0.0111? |
| A. | 0.1600 |
| B. | 0.22728 |
| C. | 0.9375 |
| D. | 0.7964 |
| Answer» D. 0.7964 | |
| 3889. |
Which one of the following is loaded in the main memory by the bootstrap loader? |
| A. | System data |
| B. | User program |
| C. | BIOS |
| D. | Part of DOS |
| Answer» E. | |
| 3890. |
Microprocessors find applications in |
| A. | pocket calculators |
| B. | scientific instruments |
| C. | medical equipments |
| D. | all of the above |
| Answer» E. | |
| 3891. |
If we need a device to shut off a few ampere current in a few nano seconds, the proper devices is |
| A. | VMOS |
| B. | CMOS |
| C. | BJT |
| D. | UJT |
| Answer» B. CMOS | |
| 3892. |
A semiconductor Read-only-Memory basically is |
| A. | a combinational logic circuit |
| B. | a set of flip-flop memory elements |
| C. | a sequential circuit with flip-flops and gates |
| D. | none of the above |
| Answer» B. a set of flip-flop memory elements | |
| 3893. |
Assertion (A): A binary number is a string of zeros and ones only Reason (R): The base in a binary system is 2 |
| A. | Both A and R are correct and R is correct explanation of A |
| B. | Both A and R are correct but R is not correct explanation of A |
| C. | A is true, R is false |
| D. | A is false, R is true |
| Answer» B. Both A and R are correct but R is not correct explanation of A | |
| 3894. |
Symbol in the given figure is IEEE symbol for |
| A. | AND |
| B. | OR |
| C. | NAND |
| D. | NOR |
| Answer» C. NAND | |
| 3895. |
For a level input sequential circuit |
| A. | output in a level only |
| B. | output is in the pulse form |
| C. | output may be a pulse or a level form |
| D. | none of these |
| Answer» B. output is in the pulse form | |
| 3896. |
In a digital system, the maximum clock frequency that can be used with Master/Slave Clocked flip-flops having total propagation delay of 200 sec is |
| A. | 20 MHz |
| B. | 50 MHz |
| C. | 100 MHz |
| D. | 200 MHz |
| Answer» C. 100 MHz | |
| 3897. |
Which of them contains an organic fluid? |
| A. | LED |
| B. | LCD |
| C. | Both LED and LCD |
| D. | Neither LED nor LCD |
| Answer» C. Both LED and LCD | |
| 3898. |
A buffer is |
| A. | always non-inverting |
| B. | always inverting |
| C. | inverting or non-inverting |
| D. | none of the above |
| Answer» D. none of the above | |
| 3899. |
The circuit realizes the function |
| A. | (A + B) E + CD |
| B. | (A + B) (E + CD) |
| C. | (A + B) (E + C + D) |
| D. | (AB + E). CD |
| Answer» B. (A + B) (E + CD) | |
| 3900. |
A voltage DAC is generally slower than current DAC |
| A. | because of more accuracy |
| B. | because of higher resolution |
| C. | because of response time of op-amp current to voltage converter |
| D. | none of the above |
| Answer» D. none of the above | |