MCQOPTIONS
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MCQOPTIONS
This section includes 1271 Mcqs, each offering curated multiple-choice questions to sharpen your Electronics & Communication Engineering knowledge and support exam preparation. Choose a topic below to get started.
| 1051. |
The range of signed decimal number that can be represented by 6 bit in complement number is |
| A. | -31 to +31 |
| B. | -63 to +64 |
| C. | -64 to +63 |
| D. | -32 to +31 |
| Answer» B. -63 to +64 | |
| 1052. |
In an R-S latch, to set the output to high |
| A. | R is low and S is high |
| B. | R and S are high |
| C. | R and S are low |
| D. | R is high and S is low |
| Answer» B. R and S are high | |
| 1053. |
In 8085 microprocessor, even after a Reset operation which of the following interrupts remains enabled? |
| A. | INTR |
| B. | RST 5.5 |
| C. | RST 7.5 |
| D. | TRAP |
| Answer» E. | |
| 1054. |
If an analog voltage is expressed in binary using 4 bits, each successive binary count would represent |
| A. | of total voltage |
| B. | of total voltage |
| C. | of total voltage |
| D. | of total voltage |
| Answer» D. of total voltage | |
| 1055. |
The Truth Table shown is for a |
| A. | CMO |
| B. | counter |
| C. | flip-flop |
| D. | half adder |
| Answer» E. | |
| 1056. |
In the full adder, denoting Sum by S and carry by C |
| A. | S = 1 when two or more inputs are unity |
| B. | C = 1 when two or more inputs are unity |
| C. | C = 1 when all the inputs are unity |
| D. | S = 1 when all the inputs are unity |
| Answer» C. C = 1 when all the inputs are unity | |
| 1057. |
The hexadecimal number (3E8)16 is equal to decimal number |
| A. | 1000 |
| B. | 982 |
| C. | 768 |
| D. | 323 |
| Answer» B. 982 | |
| 1058. |
Out of 5 M x 8, 1 M x 16, 2 M x 16 and 3M x 8 memories, which memory can store more bits? |
| A. | 5 M x 8 |
| B. | 2 M x 16 |
| C. | 3 M x 8 |
| D. | 1 M x 16 |
| Answer» B. 2 M x 16 | |
| 1059. |
Which binary subtraction is incorrect? |
| A. | 100101 - 100011 = 000000 |
| B. | 10000000 - 01000000 = 1000000 |
| C. | 10111110.1 - 101011.11 = 110010.11 |
| D. | 11111111 - 1111111 = 10000000 |
| Answer» B. 10000000 - 01000000 = 1000000 | |
| 1060. |
The logic realized by the circuit shown in figure |
| A. | F = A ‚äô C |
| B. | F = A ‚äï C |
| C. | F = B ‚äô C |
| D. | F = B ‚äï C |
| Answer» C. F = B ‚äô C | |
| 1061. |
A JK flip flop has tpd= 12 ns. The largest modulus of a ripple counter using these flip flops and operating at 10 MHz is |
| A. | 16 |
| B. | 64 |
| C. | 128 |
| D. | 256 |
| Answer» E. | |
| 1062. |
State transition table and state transition diagram form part of design steps for |
| A. | combinational circuits |
| B. | sequential circuits |
| C. | delay circuits |
| D. | all of the above |
| Answer» C. delay circuits | |
| 1063. |
Multiplexer can be used as logic function generator. |
| A. | 1 |
| B. | |
| C. | NAND IC |
| D. | interface between TTL and CMOS |
| Answer» B. | |
| 1064. |
With four Boolean variables, how many Boolean expressions can be performed? |
| A. | 16 |
| B. | 256 |
| C. | 1024 (1 K) |
| D. | 64K (64 x 1024) |
| Answer» E. | |
| 1065. |
2's complement representation of a 16 bit number (one sign bit and 15 magnitude bits) is FFFF. Its magnitude in decimal representation is |
| A. | 0 |
| B. | 1 |
| C. | 32, 767 |
| D. | 65, 535 |
| Answer» C. 32, 767 | |
| 1066. |
The 8085 microprocessor is interrupted while executing MOV instruction at location 0210 H. What is the location at which contents of register E are stored. |
| A. | 054 CH |
| B. | 054 DH |
| C. | 054 EH |
| D. | 054 FH |
| Answer» D. 054 FH | |
| 1067. |
The function of interface circuit is |
| A. | to match output conditions of driver with input conditions of load device |
| B. | to match output conditions of load device with input conditions of driver |
| C. | both (a) and (b) |
| D. | neither (a) nor (b) |
| Answer» B. to match output conditions of load device with input conditions of driver | |
| 1068. |
A microcomputer has a 64 K memory. What is the hexadecimal notation for the first memory location? |
| A. | 0 |
| B. | FFFF |
| C. | 0FFF |
| D. | 3FFF |
| Answer» B. FFFF | |
| 1069. |
A 10 bit ADC with a full scale output voltage of 10.24 V is to be designed to have ± LSB/2 accuracy. If ADC is calibrated at 25°C, the maximum net temperature coefficient of ADC should not exceed |
| A. | ± 200 μV/°C |
| B. | ± 400 μV/°C |
| C. | ± 600 μV/°C |
| D. | ± 800 μV/°C |
| Answer» B. ¬± 400 ŒºV/¬∞C | |
| 1070. |
Flash ADC is |
| A. | serial ADC |
| B. | parallel ADC |
| C. | series-parallel ADC |
| D. | successive approximation ADC |
| Answer» C. series-parallel ADC | |
| 1071. |
1's complement of 11100110 is |
| A. | 11001 |
| B. | 10000001 |
| C. | 11010 |
| D. | 0 |
| Answer» B. 10000001 | |
| 1072. |
A 4 input AND gate is equivalent to |
| A. | 4 switches in parallel |
| B. | 2 switches in series and 2 in parallel |
| C. | three switches in parallel and one in series |
| D. | 4 switches in series |
| Answer» E. | |
| 1073. |
A mod-2 counter followed by a mod 5 is same as |
| A. | mod-7 counter |
| B. | A decade counter |
| C. | mod-3 counter |
| D. | none |
| Answer» C. mod-3 counter | |
| 1074. |
Decimal 43 in hexadecimal and BCD number system is respectively. |
| A. | B2, 01000011 |
| B. | 2B, 01000011 |
| C. | 2B, 00110100 |
| D. | B2, 01000100 |
| Answer» C. 2B, 00110100 | |
| 1075. |
As compared to MOS memories, bipolar memories have |
| A. | slower access time but are cheaper |
| B. | slower access time and are costly |
| C. | faster access time and are cheaper |
| D. | faster access time and are costly |
| Answer» E. | |
| 1076. |
Assertion (A): The output of an 8 bit ADC is 80 H if input is 2.5 V Reason (R): ADC has an output range of 00 to FF H if input range is - 5 to + 5 V |
| A. | Both A and R are correct and R is correct explanation of A |
| B. | Both A and R are correct but R is not correct explanation of A |
| C. | A is true, R is false |
| D. | A is false, R is true |
| Answer» D. A is false, R is true | |
| 1077. |
In standard TTL the totem pole stage refers to |
| A. | multiemitter input stage |
| B. | phase splitter |
| C. | output buffer |
| D. | open collector output stage |
| Answer» D. open collector output stage | |
| 1078. |
The gate width of a monostable multivibrator is given by |
| A. | T = 1.1 RC |
| B. | T = 0.693 RC |
| C. | 0.963 RC |
| D. | T = 0.369 RC |
| Answer» C. 0.963 RC | |
| 1079. |
A 4 bit synchronous counter uses flip flops with a delay time of 15 ns each. The time required for change of state is |
| A. | 15 ns |
| B. | 30 ns |
| C. | 45 ns |
| D. | 60 ns |
| Answer» B. 30 ns | |
| 1080. |
For the minterm designation Y = ‚àë m (1, 3, 5, 7) the complete expression is |
| A. | Y = A BC + A B C |
| B. | Y = A B C + A B C + ABC + A BC |
| C. | Y = A B C + A B C + ABC + A BC |
| D. | Y = A B C + ABC + A BC + A BC |
| Answer» C. Y = A B C + A B C + ABC + A BC | |
| 1081. |
39.1210 = __________ 10 |
| A. | 10111.00011 |
| B. | 100011.0001 |
| C. | 100001.0001 |
| D. | 1111.000111 |
| Answer» B. 100011.0001 | |
| 1082. |
A microprocessor with a 16-bit address bus is used in a linear memory selection configuration (i.e., Address bus lines are directly used as chip selects of memory chips) with 4 memory chips. The maximum addressable memory space is |
| A. | 64 K |
| B. | 16 K |
| C. | 8 K |
| D. | 4 K |
| Answer» B. 16 K | |
| 1083. |
Semiconductor ROM's are sometimes preferred to semiconductor RAM's because |
| A. | ROM's are cheaper than RAMs |
| B. | ROMs are faster |
| C. | ROMs do not require power supply for their operations |
| D. | Programs stored in ROMs cannot be altered either by the power failure or by the user |
| Answer» E. | |
| 1084. |
For the ring oscillator shown in the figure, the propagation delay of each inverter is 100 pico sec. What is the fundamental frequency of the oscillator output __________ |
| A. | 10 MHz |
| B. | 100 MHz |
| C. | 1 GHz |
| D. | 2 GHz |
| Answer» E. | |
| 1085. |
In a 4 bit ripple counter using flip flops with tpd = 40 ns, the maximum frequency can be |
| A. | 1.25 MHz |
| B. | 3.25 MHz |
| C. | 6.25 MHz |
| D. | 12.5 MHz |
| Answer» D. 12.5 MHz | |
| 1086. |
The decimal equivalent of the hexadecimal number E 5 is |
| A. | 279 |
| B. | 229 |
| C. | 327 |
| D. | 0 |
| Answer» C. 327 | |
| 1087. |
The basic circuit configuration for TTL resembles that of a |
| A. | AND gate |
| B. | NAND gate |
| C. | NOR gate |
| D. | OR gate |
| Answer» C. NOR gate | |
| 1088. |
A counter type A/D converter contains a 4 bit binary ladder and a counter driven by a 2 MHz clock. Then conversion time |
| A. | 8 μ sec |
| B. | 10 μ sec |
| C. | 2 μ sec |
| D. | 5 μ sec |
| Answer» B. 10 Œº sec | |
| 1089. |
Some of MOS families are PMOS, NMOS, CMOS. The family dominating the LSI field where low power consumption is necessary is |
| A. | NMOS |
| B. | CMOS |
| C. | PMOS |
| D. | both NMOS and CMOS |
| Answer» C. PMOS | |
| 1090. |
In 2's complement representation the number 11100101 represents the decimal number |
| A. | 37 |
| B. | -31 |
| C. | 27 |
| D. | -27 |
| Answer» E. | |
| 1091. |
Zero suppression is not used in actual practice. |
| A. | 1 |
| B. | |
| Answer» C. | |
| 1092. |
Which one of the following is used to change data from spatial code to temporal code? |
| A. | Shift register |
| B. | Counter |
| C. | A/D converters |
| D. | Combinational circuits |
| Answer» B. Counter | |
| 1093. |
The no. of FF required and the maximum decimal no. of a MOD-12 counter is |
| A. | 12, 12 |
| B. | 4, 11 |
| C. | 3, 6 |
| D. | 4, 10 |
| Answer» C. 3, 6 | |
| 1094. |
In 8085 microprocessor, how many I/O ports can be accessed by direct method? |
| A. | 8 |
| B. | 256 |
| C. | 32 K |
| D. | 64 K |
| Answer» C. 32 K | |
| 1095. |
A ripple counter has propagation delay. |
| A. | 1 |
| B. | |
| C. | 1 |
| D. | |
| Answer» B. | |
| 1096. |
The hexadecimal number 5 F is equal to binary number |
| A. | 1010011 |
| B. | 1011001 |
| C. | 1010101 |
| D. | 1011111 |
| Answer» E. | |
| 1097. |
The sum of 11101012 and 110112 in decimal form will be |
| A. | 65 |
| B. | 75 |
| C. | 85 |
| D. | 95 |
| Answer» D. 95 | |
| 1098. |
Schmitt trigger can be used as a |
| A. | comparator |
| B. | square-wave generator |
| C. | flip-flop |
| D. | all of these |
| Answer» E. | |
| 1099. |
In the given figure, Y = |
| A. | (A + B)C + DE |
| B. | AB + C(D + E) |
| C. | (A + B)C + D + E |
| D. | none of the above |
| Answer» B. AB + C(D + E) | |
| 1100. |
BCD input 1000 is fed to a 7 segment display through a BCD to 7 segment decoder/driver. The segments which will lit up are |
| A. | a, b, d |
| B. | a, b, c |
| C. | all |
| D. | a, b, g, c, d |
| Answer» D. a, b, g, c, d | |