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This section includes 10 Mcqs, each offering curated multiple-choice questions to sharpen your Computational Fluid Dynamics knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
The central differencing scheme gives good results when _____________ |
| A. | the grid is coarse |
| B. | the grid is very fine |
| C. | the grid is Cartesian and uniform |
| D. | the gird is on-Cartesian |
| Answer» C. the grid is Cartesian and uniform | |
| 2. |
The order of accuracy of the central differencing scheme is _____________ |
| A. | fourth-order |
| B. | third-order |
| C. | second-order |
| D. | first-order |
| Answer» D. first-order | |
| 3. |
The central difference scheme gives unphysical results when the problem is _____________ |
| A. | depends on the boundary conditions |
| B. | equally dominated by diffusion and convection |
| C. | diffusive dominant |
| D. | convective dominant |
| Answer» E. | |
| 4. |
The central differencing scheme becomes inconsistent when the Peclet number _____________ |
| A. | is higher than 2 |
| B. | is less than 2 |
| C. | is higher than 5 |
| D. | is less than 5 |
| Answer» B. is less than 2 | |
| 5. |
Which of these is correct about the central differencing scheme? |
| A. | The importance of upwind and downwind nodes depends on the problem |
| B. | It gives more importance to the downwind nodes |
| C. | It gives equal importance to upwind and downwind nodes |
| D. | It gives more importance to the upwind nodes |
| Answer» D. It gives more importance to the upwind nodes | |
| 6. |
The central difference approximation goes wrong when _____________ |
| A. | Peclet number is negative |
| B. | Peclet number is positive |
| C. | Peclet number is low |
| D. | Peclet number is high |
| Answer» E. | |
| 7. |
What is the relationship between \(\frac{\phi_c-\phi_w}{\phi_E-\phi_w}\) and the Peclet number (Pe) when the grid is uniform? |
| A. | \(\frac{\phi_c-\phi_w}{\phi_E-\phi_w} = \frac{1}{2}(1-\frac{Pe}{2}) \) |
| B. | \(\frac{\phi_c-\phi_w}{\phi_E-\phi_w} = \frac{1}{2}(1+\frac{Pe}{2}) \) |
| C. | \(\frac{\phi_c-\phi_w}{\phi_E-\phi_w} = \frac{1}{2}(\frac{Pe}{2}-1) \) |
| D. | \(\frac{\phi_c-\phi_w}{\phi_E-\phi_w} = (\frac{Pe}{4}) \) |
| E. | when the grid is uniform?a) \(\frac{\phi_c-\phi_w}{\phi_E-\phi_w} = \frac{1}{2}(1-\frac{Pe}{2}) \) b) \(\frac{\phi_c-\phi_w}{\phi_E-\phi_w} = \frac{1}{2}(1+\frac{Pe}{2}) \) c) \(\frac{\phi_c-\phi_w}{\phi_E-\phi_w} = \frac{1}{2}(\frac{Pe}{2}-1) \) d) \(\frac{\phi_c-\phi_w}{\phi_E-\phi_w} = (\frac{Pe}{4}) \) |
| Answer» B. \(\frac{\phi_c-\phi_w}{\phi_E-\phi_w} = \frac{1}{2}(1+\frac{Pe}{2}) \) | |
| 8. |
What is the central differencing scheme similar to? |
| A. | Interpolation profile |
| B. | Linear interpolation profile |
| C. | Weighted average method |
| D. | Geometric mean |
| Answer» C. Weighted average method | |
| 9. |
Consider the following stencil.Assume that the grid is a uniform Cartesian grid. What is φw as given by the central difference scheme?(Note: Φ represents the flow variable). |
| A. | Φc |
| B. | \(\frac{\phi_c+\phi_w}{2}\) |
| C. | \(\frac{\phi_c-\phi_w}{2}\) |
| D. | \(\frac{\phi_w-\phi_c}{2}\) |
| E. | .a) Φcb) \(\frac{\phi_c+\phi_w}{2}\) c) \(\frac{\phi_c-\phi_w}{2}\) d) \(\frac{\phi_w-\phi_c}{2}\) |
| Answer» C. \(\frac{\phi_c-\phi_w}{2}\) | |
| 10. |
Consider the following stencil. What is Φe as given by the central difference scheme?(Note: Φ represents the flow variable). |
| A. | \(\phi_E = \phi_c-\frac{(\phi_E+\phi_c)}{(x_E-x_C)}(x_e-x_C)\) |
| B. | \(\phi_E = \phi_c+\frac{(\phi_E+\phi_c)}{(x_E-x_C)}(x_e-x_C)\) c) \(\phi_E = \phi_c+\frac{(\phi_E-\phi_c)}{(x_E-x_C)}(x_e-x_C)\) d) \(\phi_E = \phi_c-\frac{(\phi_E-\phi_ |
| C. | }{(x_E-x_C)}(x_e-x_C)\) b) \(\phi_E = \phi_c+\frac{(\phi_E+\phi_c)}{(x_E-x_C)}(x_e-x_C)\) c) \(\phi_E = \phi_c+\frac{(\phi_E-\phi_c)}{(x_E-x_C)}(x_e-x_C)\) |
| D. | \(\phi_E = \phi_c-\frac{(\phi_E-\phi_c)}{(x_E-x_C)}(x_e-x_C)\) |
| E. | .a) \(\phi_E = \phi_c-\frac{(\phi_E+\phi_c)}{(x_E-x_C)}(x_e-x_C)\) b) \(\phi_E = \phi_c+\frac{(\phi_E+\phi_c)}{(x_E-x_C)}(x_e-x_C)\) c) \(\phi_E = \phi_c+\frac{(\phi_E-\phi_c)}{(x_E-x_C)}(x_e-x_C)\) d) \(\phi_E = \phi_c-\frac{(\phi_E-\phi_c)}{(x_E-x_C)}(x_e-x_C)\) |
| Answer» D. \(\phi_E = \phi_c-\frac{(\phi_E-\phi_c)}{(x_E-x_C)}(x_e-x_C)\) | |