MCQOPTIONS
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MCQOPTIONS
This section includes 15 Mcqs, each offering curated multiple-choice questions to sharpen your Soil Mechanics knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
The Rowe cell apparatus also measures the pore pressure. |
| A. | False |
| B. | True |
| Answer» C. | |
| 2. |
From the calculations consideration of a consolidation test data, the change in thickness can be both positive and negative. |
| A. | True |
| B. | False |
| Answer» B. False | |
| 3. |
The unit of coefficient of volume change is |
| A. | m2/kN |
| B. | m3/kN |
| C. | m2/N |
| D. | m3/N |
| Answer» B. m3/kN | |
| 4. |
The coefficient of volume change is ______________ |
| A. | reciprocal of compressibility modulus |
| B. | equal to compressibility modulus |
| C. | double compressibility modulus |
| D. | equal to three times the compressibility modulus |
| Answer» B. equal to compressibility modulus | |
| 5. |
From the consolidation test data using the ‘Height of solids’ method, the coefficient of volume change can be calculated by _____________ |
| A. | \(m_v=-\frac{∆H_o}{H_o}\frac{1}{∆σ’}\) |
| B. | \(m_v=\frac{∆H}{H_o} \frac{1}{∆σ’}\) |
| C. | \(m_v=-\frac{∆H}{H_o} \frac{1}{∆σ’}\) |
| D. | \(m_v=-\frac{∆H}{H}\frac{1}{∆σ’}\) |
| Answer» D. \(m_v=-\frac{∆H}{H}\frac{1}{∆σ’}\) | |
| 6. |
From the consolidation test data using the ‘change in void ratio’ method, the coefficient of volume change can be calculated by _____________ |
| A. | \(m_v=-\frac{∆e}{1+e_o} \frac{1}{σ’} \) |
| B. | \(m_v=-\frac{∆e}{1+e_o}\) |
| C. | \(m_v=-\frac{∆e}{1+e_o} \frac{10}{∆σ’}\) |
| D. | \(m_v=-\frac{∆e}{1+e_o} \frac{1}{∆σ’}\) |
| Answer» E. | |
| 7. |
The change in voids ratio of the consolidation test is calculated from the relation of________ |
| A. | \(∆e=\frac{1+e_f}{2} ∆H\) |
| B. | \(∆e=\frac{1+e_f}{H_f} ∆H_f\) |
| C. | \(∆e=\frac{1+e_f}{H}\) |
| D. | \(∆e=\frac{e_f}{H_f} ∆H\) |
| Answer» B. \(∆e=\frac{1+e_f}{H_f} ∆H_f\) | |
| 8. |
From the consolidation test, by the change in voids ratio method, the final void is given by _______ |
| A. | ef=wf G |
| B. | ef=wf AG |
| C. | \(e_f=\frac{w_f}{G}\) |
| D. | \(e_f=\frac{G}{w_f}\) |
| Answer» B. ef=wf AG | |
| 9. |
The height of the specimen at various applied pressures is given by _____________ |
| A. | H=H0*∑∆H |
| B. | H=H0-∑∆H |
| C. | \(H=\frac{H_0}{∑∆H}\) |
| D. | H=H0+∑∆H |
| Answer» E. | |
| 10. |
The voids ratio with respect to height of solids is given by equation______________ |
| A. | \(e=\frac{H}{H_s}\) |
| B. | \(e=\frac{H_s}{H}\) |
| C. | \(e=\frac{H+H_s}{H_s}\) |
| D. | \(e=\frac{H-H_s}{H_s}\) |
| Answer» E. | |
| 11. |
The height Hs of the solids of the specimen with respect to weight of dried specimen is _____________ |
| A. | \(H_s=\frac{W_d}{Gρ_w}\) |
| B. | \(H_s=\frac{W_d}{GAρ_w}\) |
| C. | \(H_s=\frac{W_d}{GA}\) |
| D. | \(H_s=\frac{W_d}{Aρ_w}\) |
| Answer» D. \(H_s=\frac{W_d}{Aρ_w}\) | |
| 12. |
The height HS of the solids of the specimen is calculated from _______________ |
| A. | \(H_s=\frac{M_d}{GA}\) |
| B. | \(H_s=\frac{M_d}{Gρ_w}\) |
| C. | \(H_s=\frac{M_d}{Aρ_w}\) |
| D. | \(H_s=\frac{M_d}{GAρ_w}\) |
| Answer» E. | |
| 13. |
The height of solids method is applicable for ________ |
| A. | only dry specimens |
| B. | only fully saturated specimens |
| C. | both saturated and unsaturated samples |
| D. | only partially saturated specimens |
| Answer» D. only partially saturated specimens | |
| 14. |
The change in voids ratio method is applicable for _________________ |
| A. | only dry specimens |
| B. | only fully saturated specimens |
| C. | only partially saturated specimens |
| D. | for all types of specimens |
| Answer» C. only partially saturated specimens | |
| 15. |
From the consolidation test, the final voids ratio at end of pressure increment can be calculated by ________________ |
| A. | height of solids method only |
| B. | change in voids ratio method only |
| C. | both height of solids method and change in voids ratio method |
| D. | no method are available |
| Answer» D. no method are available | |