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This section includes 14 Mcqs, each offering curated multiple-choice questions to sharpen your Strength Materials knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
A composite bar of two sections of equal length and given diameter is under an axial pull of 15kN. What will be the stresses in the two sections in N/mm2? |
| A. | 190.9 and 84.88 |
| B. | 190.9 and 44.35 |
| C. | 153.45 and 84088 |
| D. | 153045 and 44.35 |
| Answer» B. 190.9 and 44.35 | |
| 2. |
A composite bar of two sections of unequal length and equal diameter is under an axial pull of 10kN. What will be the stresses in the two sections? |
| A. | 2.145 N/mm2 |
| B. | 3.18 N/mm2 |
| C. | 1.245 N/mm2 |
| D. | 2.145 N/mm2 |
| Answer» C. 1.245 N/mm2 | |
| 3. |
A composite bar of two sections of equal length and equal diameter is under an axial pull of 10kN. What will be the stresses in the two sections? |
| A. | 3.18 N/mm2 |
| B. | 2.21 N/mm2 |
| C. | 3.45 N/mm2 |
| D. | 2.14 N/mm2 |
| Answer» B. 2.21 N/mm2 | |
| 4. |
Does the value of stress in each section of a composite bar is constant or not? |
| A. | It changes in a relationship with the other sections as well |
| B. | It changes with the total average length |
| C. | It is constant for every bar |
| D. | It is different in every bar in relation with the load applied and the cross sectional area |
| Answer» E. | |
| 5. |
An axial pull of 20 kN on a bar of two equal lengths of 20cm as shown with their respective dimensions. What will be the total extension of the bar if the young’s modulus = 2×105? |
| A. | 0.200mm |
| B. | 0.345mm |
| C. | 0.509mm |
| D. | 0.486mm |
| Answer» D. 0.486mm | |
| 6. |
An axial pull of 35000 N on a bar consisting of two lengths as shown with their respective dimensions. What will be the total extension of the bar if the young’s modulus = 2.1 x 105? |
| A. | 0.153mm |
| B. | 0.183mm |
| C. | 0.197mm |
| D. | 0.188mm |
| Answer» C. 0.197mm | |
| 7. |
An axial pull of 1kN is acting on a bar of consisting two equal lengths as shown but of dia 10cm and 20cm respectively. What will be the stresses in the two sections respectively in N/mm2? |
| A. | 0.127 and 0.0031 |
| B. | 0.034 and 0.0045 |
| C. | 0.153 and 0.003 |
| D. | 0.124 and 0.124 |
| Answer» B. 0.034 and 0.0045 | |
| 8. |
An axial pull of 35000 N is acting on a bar consisting of two lengths as shown with their respective dimensions. What will be the stresses in the two sections respectively in N/mm2? |
| A. | 111.408 and 49.5146 |
| B. | 111.408 and 17.85 |
| C. | 97.465 and 49.5146 |
| D. | 97.465 and 34.263 |
| Answer» B. 111.408 and 17.85 | |
| 9. |
DOES_THE_VALUE_OF_STRESS_IN_EACH_SECTION_OF_A_COMPOSITE_BAR_IS_CONSTANT_OR_NOT??$ |
| A. | It changes in a relationship with the other sections as well |
| B. | It changes with the total average length |
| C. | It is constant for every bar |
| D. | It is different in every bar in relation with the load applied and the cross sectional area |
| Answer» B. It changes with the total average length | |
| 10. |
153m? |
| A. | 0.183mm |
| B. | 0.197mm |
| C. | 0.188mm |
| Answer» B. 0.197mm | |
| 11. |
127 and 0.0031 |
| A. | 0.034 and 0.0045 |
| B. | 0.153 and 0.003 |
| C. | 0.124 and 0.124 |
| Answer» D. | |
| 12. |
408 and 49.5146 |
| A. | 111.408 and 17.85 |
| B. | 97.465 and 49.5146 |
| C. | 97.465 and 34.263 |
| Answer» B. 97.465 and 49.5146 | |
| 13. |
If a bar of two sections of different diameters of same length are in a line and P load is acting axially on them then what will be the change in length of the bar? |
| A. | PL/E x (1/A<sub>1</sub> + 1/A<sub>2</sub>) |
| B. | P/E x (1/A<sub>1</sub> + 1/A<sub>2</sub>) |
| C. | P/EL x (1/A<sub>1</sub> + 1/A<sub>2</sub>) |
| D. | PE/L x (1/A<sub>1</sub> + 1/A<sub>2</sub>) |
| Answer» B. P/E x (1/A<sub>1</sub> + 1/A<sub>2</sub>) | |
| 14. |
If a bar of two different length are in a line and P load is acting axially on them then what will be the change in length of the bar if the radius of both different lengths is same? |
| A. | P/E x (L<sub>1</sub> + L<sub>2</sub>) |
| B. | PA/E x (L<sub>1</sub> + L<sub>2</sub>) |
| C. | P/EA x (L<sub>1</sub> + L<sub>2</sub>) |
| D. | E/PA x (L<sub>1</sub> + L<sub>2</sub>) |
| Answer» D. E/PA x (L<sub>1</sub> + L<sub>2</sub>) | |