Which of the following formula is incorrect?

Question

TuteeHUB · Accepted Answer

2 tan-1⁡x=tan-1⁡$(\frac{2x}{1-x^2})$

TuteeHUB · Answer

sin-1⁡x+sin-1⁡y=sin-1⁡{$x\sqrt{1-y^2}+y\sqrt{1-x^2}$}

TuteeHUB · Answer

sin-1⁡x-sin-1⁡y=sin-1⁡{$x\sqrt{1+y^2}+y\sqrt{1+x^2}$}

TuteeHUB · Answer

2 tan-1⁡x=tan-1⁡$(\frac{2x}{1-x^2})$

TuteeHUB · Answer

2 cos-1⁡x=cos-1⁡(3x-4x3)

1.	Which of the following formula is incorrect?
A.	sin-1⁡x+sin-1⁡y=sin-1⁡{\(x\sqrt{1-y^2}+y\sqrt{1-x^2}\)}
B.	sin-1⁡x-sin-1⁡y=sin-1⁡{\(x\sqrt{1+y^2}+y\sqrt{1+x^2}\)}
C.	2 tan-1⁡x=tan-1⁡\((\frac{2x}{1-x^2})\)
D.	2 cos-1⁡x=cos-1⁡(3x-4x3)
Answer» C. 2 tan-1⁡x=tan-1⁡\((\frac{2x}{1-x^2})\)

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