MCQOPTIONS
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| 1. |
What is the formula of logarithmic mean temperature in terms of By-pass factor? |
| A. | Tm = td2 – td1 / loge [1/BPF] |
| B. | Tm = td2 – td1 / log10 [BPF] |
| C. | Tm = td2 – td1 / loge [BPF] |
| D. | Tm = td2 – td3 / loge [BPF] |
| Answer» D. Tm = td2 – td3 / loge [BPF] | |