What is the final result obtained by substituting Fc=kB-B/2, T= 1/2B – McqOptions

MCQOPTIONS

1.	What is the final result obtained by substituting Fc=kB-B/2, T= 1/2B and say n = 2m i.e., for even and n=2m-1 for odd in equation x(nT)= \(u_c (nT)cos⁡2πF_c nT-u_s (nT)sin⁡ 2πF_c nT\)?
A.	\((-1)^m u_c (mT_1)-u_s\)
B.	\(u_s (mT_1-\frac{T_1}{2})(-1)^{m+k+1}\)
C.	None
D.	\((-1)^m u_c (mT_1)- u_s (mT_1-\frac{T_1}{2})(-1)^{m+k+1}\)
Answer» E.

Discussion

No Comment Found

Related MCQs

What is the basic relationship between the spectrum o f the real band pass signal x(t) and the spectrum of the equivalent low pass signal xl(t)?
What is the Fourier transform of x(t)?
What is the expression for low pass signal component us(t) that can be expressed in terms of samples of the bandpass signal?
What is the expression for low pass signal component uc(t) that can be expressed in terms of samples of the bandpass signal?
According to the sampling theorem for low pass signals with T1=1/B, then what is the expression for us(t) = ?
According to the sampling theorem for low pass signals with T1=1/B, then what is the expression for uc(t) = ?
What is the new centre frequency for the increased bandwidth signal?
What is the reconstruction formula for the bandpass signal x(t) with samples taken at the rate of 2B samples per second?
Which low pass signal component occurs at the rate of B samples per second with odd numbered samples of x(t)?
What is the final result obtained by substituting Fc=kB-B/2, T= 1/2B and say n = 2m i.e., for even and n=2m-1 for odd in equation x(nT)= \(u_c (nT)cos⁡2πF_c nT-u_s (nT)sin⁡ 2πF_c nT\)?