MCQOPTIONS
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| 1. |
What is the expression for heat transfer coefficient for a horizontally placed condenser? |
| A. | hHOR=0.943\([\frac{K^3 p^2 g h_{fg}}{μx(T_{sat} – T_L)}]^{0.25}\) |
| B. | hHOR=0.743\([\frac{K^3 p^2 g h_{fg}}{μx(T_{sat} – T_L)}]^{0.25}\) |
| C. | hHOR=0.723\([\frac{K^3 p^2 g h_{fg}}{μx(T_{sat} – T_L)}]^{0.25}\) |
| D. | hHOR=0.725\([\frac{K^3 p^2 g h_{fg}}{μx(T_{sat} – T_L)}]^{0.25}\) |
| Answer» E. | |