The stress intensity for a plate is given as K=σ√(πa) tan(πta); where a is crack length equal to 6 mm, t is the thickness of the plate equal to 1 cm, and σ is the nominal stress applied. Determine the maximum allowable stress if KIc=50 MPa m-1/2.

tan(πta); where a is crack length equal to 6 mm, t is the thickness of the plate equal to 1 cm, and σ is the nominal stress applied. Determine the maximum allowable stress if KIc=50 MPa m-1/2.a) 100 MPa

The stress intensity for a plate is given as K=σ√(πa) tan(πta);

1.	The stress intensity for a plate is given as K=σ√(πa) tan(πta); where a is crack length equal to 6 mm, t is the thickness of the plate equal to 1 cm, and σ is the nominal stress applied. Determine the maximum allowable stress if KIc=50 MPa m-1/2.
A.	tan(πta); where a is crack length equal to 6 mm, t is the thickness of the plate equal to 1 cm, and σ is the nominal stress applied. Determine the maximum allowable stress if KIc=50 MPa m-1/2.a) 100 MPa
B.	145 MPa
C.	200 MPa
D.	500 MPa
Answer» C. 200 MPa

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The stress intensity for a plate is given as K=σ√(πa) tan(πta); where a is crack length equal to 6 mm, t is the thickness of the plate equal to 1 cm, and σ is the nominal stress applied. Determine the maximum allowable stress if KIc=50 MPa m-1/2.

The stress intensity for a plate is given as K=σ√(πa) tan(πta); where a is crack length equal to 6 mm, t is the thickness of the plate equal to 1 cm, and σ is the nominal stress applied. Determine the maximum allowable stress if KIc=50 MPa m-1/2.

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