MCQOPTIONS
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| 1. |
The 3 – sigma upper limit for a control chart for average number of nonconformities per unit, is expressed by ___________ |
| A. | UCL=\(\bar{u} + 3\sqrt{\frac{\bar{u}}{n}}\) |
| B. | UCL=\(\bar{u} – 3\sqrt{\frac{\bar{u}}{n}}\) |
| C. | UCL=\(\bar{u} – 2\sqrt{\frac{\bar{u}}{n}}\) |
| D. | UCL=\(\bar{u} – \frac{3}{2} \sqrt{\frac{\bar{u}}{n}}\) |
| Answer» B. UCL=\(\bar{u} – 3\sqrt{\frac{\bar{u}}{n}}\) | |