$\int \frac{(x^2+x+1)dx}{(x+2)(x^2+1)}$ equals ______

Question

TuteeHUB · Accepted Answer

NA

TuteeHUB · Answer

$\frac{3}{5}log|x+2| + \frac{1}{5}log|x^2+1|+\frac{1}{5} tan^{-1}x+5C$

TuteeHUB · Answer

$\frac{3}{5}log|x+2| + \frac{1}{5}log|x^2+1|+\frac{1}{6} tan^{-1}x+C$

TuteeHUB · Answer

$\frac{3}{5}log|x+2| + \frac{1}{6}log|x^2+1|+\frac{1}{6} tan^{-1}x+C$

TuteeHUB · Answer

$\frac{3}{5}log|x+2| + \frac{1}{5}log|x^2+1|+\frac{1}{5} tan^{-1}x+C$

1.	\(\int \frac{(x^2+x+1)dx}{(x+2)(x^2+1)}\) equals ______
A.	\(\frac{3}{5}log\|x+2\| + \frac{1}{5}log\|x^2+1\|+\frac{1}{5} tan^{-1}x+5C\)
B.	\(\frac{3}{5}log\|x+2\| + \frac{1}{5}log\|x^2+1\|+\frac{1}{6} tan^{-1}x+C\)
C.	\(\frac{3}{5}log\|x+2\| + \frac{1}{6}log\|x^2+1\|+\frac{1}{6} tan^{-1}x+C\)
D.	\(\frac{3}{5}log\|x+2\| + \frac{1}{5}log\|x^2+1\|+\frac{1}{5} tan^{-1}x+C\)
Answer» E.

\(\int \frac{(x^2+x+1)dx}{(x+2)(x^2+1)}\) equals ______