If X(k) discrete Fourier transform of x(n), then the inverse discrete Fourier transform of X(k) is?

$\frac{1}{N} \sum_{k=0}^{N-1}X(k)e^{-j2πkn/N}$

$\sum_{k=0}^{N-1}X(k)e^{-j2πkn/N}$

$\sum_{k=0}^{N-1}X(k)e^{j2πkn/N}$

$\frac{1}{N} \sum_{k=0}^{N-1}X(k)e^{j2πkn/N}$

If X(k) discrete Fourier transform of x(n), then the inverse discrete

1.	If X(k) discrete Fourier transform of x(n), then the inverse discrete Fourier transform of X(k) is?
A.	$\frac{1}{N} \sum_{k=0}^{N-1}X(k)e^{-j2πkn/N}$
B.	$\sum_{k=0}^{N-1}X(k)e^{-j2πkn/N}$
C.	$\sum_{k=0}^{N-1}X(k)e^{j2πkn/N}$
D.	$\frac{1}{N} \sum_{k=0}^{N-1}X(k)e^{j2πkn/N}$
Answer» E.

1.	If X(k) discrete Fourier transform of x(n), then the inverse discrete Fourier transform of X(k) is?
A.	\(\frac{1}{N} \sum_{k=0}^{N-1}X(k)e^{-j2πkn/N}\)
B.	\(\sum_{k=0}^{N-1}X(k)e^{-j2πkn/N}\)
C.	\(\sum_{k=0}^{N-1}X(k)e^{j2πkn/N}\)
D.	\(\frac{1}{N} \sum_{k=0}^{N-1}X(k)e^{j2πkn/N}\)
Answer» E.