If foci of a hyperbola are (0, ±5) and length of semi transverse axis is 3 units, then find the equation of hyperbola.

\((\frac{x}{3})^2-(\frac{y}{4})^2\)=1

\((\frac{x}{4})^2-(\frac{y}{3})^2\)=1

\((\frac{x}{3})^2-(\frac{y}{4})^2\)=1

\((\frac{x}{10})^2+(\frac{y}{8})^2\)=1

\((\frac{x}{8})^2-(\frac{y}{6})^2\)=1

If foci of a hyperbola are (0, ±5) and length of semi transverse axi

1.	If foci of a hyperbola are (0, ±5) and length of semi transverse axis is 3 units, then find the equation of hyperbola.
A.	\((\frac{x}{4})^2-(\frac{y}{3})^2\)=1
B.	\((\frac{x}{3})^2-(\frac{y}{4})^2\)=1
C.	\((\frac{x}{10})^2+(\frac{y}{8})^2\)=1
D.	\((\frac{x}{8})^2-(\frac{y}{6})^2\)=1
Answer» B. \((\frac{x}{3})^2-(\frac{y}{4})^2\)=1

A hyperbola in which length of transverse and conjugate axis are equal is called _________ hyperbola.
If foci of a hyperbola are (0, ±5) and length of semi transverse axis is 3 units, then find the equation of hyperbola.
If length of transverse axis is 8 and conjugate axis is 10 and transverse axis is along x-axis then find the equation of hyperbola.
What is equation of latus rectums of hyperbola \((\frac{x}{9})^2-(\frac{y}{16})^2\)=1?
What is length of latus rectum for hyperbola \((\frac{x}{9})^2-(\frac{y}{16})^2\)=1?
What is conjugate axis length for hyperbola \((\frac{x}{9})^2-(\frac{y}{16})^2\)=1?
What is transverse axis length for hyperbola \((\frac{x}{9})^2-(\frac{y}{16})^2\)=1?
What is eccentricity for \((\frac{x}{9})^2-(\frac{y}{16})^2\)=1?
Find the coordinates of foci of hyperbola \((\frac{y}{16})^2-(\frac{x}{9})^2\)=1.
Find the coordinates of foci of hyperbola \((\frac{x}{9})^2-(\frac{y}{16})^2\)=1.