If \[4x+4y-kz=0\] is the equation of the plane through the origin that contains the line \[\frac{x-1}{2}=\frac{y+1}{3}=\frac{z}{4},\]then k = [MP PET 1992]

If \[4x+4y-kz=0\] is the equation of the plane through the origin that

1.	If \[4x+4y-kz=0\] is the equation of the plane through the origin that contains the line \[\frac{x-1}{2}=\frac{y+1}{3}=\frac{z}{4},\]then k = [MP PET 1992]
A.	1
B.	3
C.	5
D.	7
Answer» D. 7

Discussion

No Comment Found

Related MCQs

The equations of the line passing through the point(1,2,-4) and perpendicular to the two lines \[\frac{x-8}{3}=\frac{y+19}{-16}=\frac{z-10}{7}\] and \[\frac{x-15}{3}=\frac{y-29}{8}=\frac{z-5}{-5}\], will be [AI CBSE 1983]
The value of k such that \[\frac{x-4}{1}=\frac{y-2}{1}=\frac{z-k}{2}\] lies in the plane \[2x-4y+z=7\], is [IIT Screening 2003]
The distance of the point of intersection of the line \[\frac{x-3}{1}=\frac{y-4}{2}=\frac{z-5}{2}\]and the plane \[x+y+z=17\] from the point (3, 4, 5) is given by
The distance of the point (1, -2, 3) from the plane \[x-y+z=5\] measured parallel to the line \[\frac{x}{2}=\frac{y}{3}=\frac{z}{-6},\]is [AI CBSE 1984]
If \[4x+4y-kz=0\] is the equation of the plane through the origin that contains the line \[\frac{x-1}{2}=\frac{y+1}{3}=\frac{z}{4},\]then k = [MP PET 1992]
If the lines \[\frac{x-1}{2}=\frac{y+1}{3}=\frac{z-1}{4}\] and \[\frac{x-3}{1}=\frac{y-k}{1}=\frac{z}{1}\] intersect, then k = [IIT Screening 2004]
The straight lines whose direction cosines are given by \[al+bm+cn=0,fmn+gnl+hlm=0\]are perpendicular, if
If three mutually perpendicular lines have direction cosines \[({{l}_{1}},{{m}_{1}},{{n}_{1}}),({{l}_{2}},{{m}_{2}},{{n}_{2}})\]and \[({{l}_{3}},{{m}_{3}},{{n}_{3}})\], then the line having direction cosines \[{{l}_{1}}+{{l}_{2}}+{{l}_{3}}\], \[{{m}_{1}}+\,\,{{m}_{2}}+\,\,{{m}_{3}}\]and \[{{n}_{1}}+{{n}_{2}}+{{n}_{3}}\] make an angle of..... with each other
The radius of the circle in which the sphere \[{{x}^{2}}+{{y}^{2}}+{{z}^{2}}+2x-2y-4z-19=0\] is cut by the plane \[x+2y+2z+7=0\]is [AIEEE 2003]
The shortest distance from the plane \[12x+4y+3z=327\] to the sphere \[{{x}^{2}}+{{y}^{2}}+{{z}^{2}}+\] \[4x-2y-6z=155\] is [AIEEE 2003]

If \[4x+4y-kz=0\] is the equation of the plane through the origin that contains the line \[\frac{x-1}{2}=\frac{y+1}{3}=\frac{z}{4},\]then k = [MP PET 1992]

Discussion

No Comment Found

Related MCQs

Reply to Comment