Find the $L^{-1} (\frac{s+3}{4s^2+9})$.

Question

TuteeHUB · Accepted Answer

NA

TuteeHUB · Answer

$\frac{1}{4} cos⁡(\frac{3t}{2})+\frac{1}{2} cos⁡(\frac{3t}{2})$

TuteeHUB · Answer

$\frac{1}{4} cos⁡(\frac{3t}{4})+\frac{1}{2} sin⁡(\frac{3t}{2})$

TuteeHUB · Answer

$\frac{1}{2} cos⁡(\frac{3t}{2})+\frac{1}{2} sin⁡(\frac{3t}{2})$

TuteeHUB · Answer

$\frac{1}{4} cos⁡(\frac{3t}{2})+\frac{1}{2} sin⁡(\frac{3t}{2})$

Find the \(L^{-1} (\frac{s+3}{4s^2+9})\).