Find the inverse of matrix A=$\begin{bmatrix}5&1&3\4&2&6\5&4&2\end{bmatrix}$

Question

TuteeHUB · Accepted Answer

NA

TuteeHUB · Answer

$\begin{bmatrix}0&-\frac{1}{6}&0\-\frac{11}{30}&\frac{1}{12}&\frac{3}{10}\-\frac{1}{10}&\frac{1}{4}&-\frac{1}{10}\end{bmatrix}$

TuteeHUB · Answer

$\begin{bmatrix}\frac{1}{3}&-\frac{1}{6}&0\-\frac{11}{30}&\frac{1}{12}&\frac{3}{10}\-\frac{1}{10}&\frac{1}{4}&-\frac{1}{10}\end{bmatrix}$

TuteeHUB · Answer

$\begin{bmatrix}\frac{1}{3}&-\frac{1}{6}&0\-\frac{11}{30}&1&\frac{3}{10}\-\frac{1}{10}&\frac{1}{4}&-\frac{1}{10}\end{bmatrix}$

TuteeHUB · Answer

$\begin{bmatrix}\frac{1}{3}&\frac{1}{6}&0\\frac{11}{30}&\frac{1}{12}&\frac{3}{10}\-\frac{1}{10}&\frac{1}{4}&\frac{1}{10}\end{bmatrix}$

1.	Find the inverse of matrix A=\(\begin{bmatrix}5&1&3\\4&2&6\\5&4&2\end{bmatrix}\)
A.	\(\begin{bmatrix}0&-\frac{1}{6}&0\\-\frac{11}{30}&\frac{1}{12}&\frac{3}{10}\\-\frac{1}{10}&\frac{1}{4}&-\frac{1}{10}\end{bmatrix}\)
B.	\(\begin{bmatrix}\frac{1}{3}&-\frac{1}{6}&0\\-\frac{11}{30}&\frac{1}{12}&\frac{3}{10}\\-\frac{1}{10}&\frac{1}{4}&-\frac{1}{10}\end{bmatrix}\)
C.	\(\begin{bmatrix}\frac{1}{3}&-\frac{1}{6}&0\\-\frac{11}{30}&1&\frac{3}{10}\\-\frac{1}{10}&\frac{1}{4}&-\frac{1}{10}\end{bmatrix}\)
D.	\(\begin{bmatrix}\frac{1}{3}&\frac{1}{6}&0\\\frac{11}{30}&\frac{1}{12}&\frac{3}{10}\\-\frac{1}{10}&\frac{1}{4}&\frac{1}{10}\end{bmatrix}\)
Answer» C.

Find the inverse of matrix A=\(\begin{bmatrix}5&1&3\\4&2&6\\5&4&2\end{bmatrix}\)