Find Common Mode Rejection Ration, given gm =16M‚âà√≠¬¨¬©- – McqOptions

MCQOPTIONS

1.	Find Common Mode Rejection Ration, given gm =16M‚âà√≠¬¨¬©-1, RE=25k‚âà√≠¬¨¬©$
A.	58 db
B.	40 db
C.	63 db
D.	89 db
Answer» B. 40 db

Discussion

No Comment Found

Related MCQs

DEFINE_TOTAL_CURRENT_(IQ)_EQUATION_IN_DIFFERENTIAL_AMPLIFIER_WITH_CONSTANT_CURRENT_BIAS_CURRENT?$
When will be the mirror effect valid$
Constant_current_source_in_differential_amplifier_is_also_called_as$
Calculate_the_value_of_reference_current_and_input_resistor_for_current_mirror_with_IC=1.2‚âà√≠¬¨‚à´A_&_VCC=12v._Assume_‚âà√≠‚Äö√¢¬ß=50.$
How to improve CMRR valu?
What is the purpose of diode in differential amplifier with constant current circuit?
To increase the value of CMRR, which circuit is used to replace the emitter resistance Re in differential amplifier?
If the value of Common Mode Rejection Ratio and Common Mode Gain are 40db and -0.12 respectively, then determine the value of differential mode gain
In differential amplifier the input are given as V1=30sin‚Äö√Ñ√∂‚àö√ñ¬¨‚àû‚âà√≠‚Äö√Ñ‚Ä†(50t)+10sin‚Äö√Ñ√∂‚àö√ñ¬¨‚àû‚âà√≠‚Äö√Ñ‚Ä†(25t) , V2=30sin‚Äö√Ñ√∂‚àö√ñ¬¨‚àû‚âà√≠‚Äö√Ñ‚Ä†(50t)-10 sin‚Äö√Ñ√∂‚àö√ñ¬¨‚àû‚âà√≠‚Äö√Ñ‚Ä†(25t), ‚âà√≠‚Äö√¢¬ß0 =200,RE =1k‚âà√≠¬¨¬© and RC = 15k‚âà√≠¬¨¬©. Find the output voltages V01, V02 & gm=4M‚âà√≠¬¨¬©-1$
Find Common Mode Rejection Ration, given gm =16M‚âà√≠¬¨¬©-1, RE=25k‚âà√≠¬¨¬©$