Design equation for varying volume system is ______a) t = $\int_0^{XA} \frac{dXA}{-rA εA} $ b) t = $\int_0^{XA} \frac{dXA}{CA0} $ c) t = $\int_0^{XA} \frac{dXA}{NA0} $ d) t = CA0 \(\int_0^{XA} \frac{dXA}{-rA(1+XA ε

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NA

TuteeHUB · Answer

t = $\int_0^{XA} \frac{dXA}{-rA εA} $

TuteeHUB · Answer

t = $\int_0^{XA} \frac{dXA}{CA0} $

TuteeHUB · Answer

t = $\int_0^{XA} \frac{dXA}{NA0} $

TuteeHUB · Answer

t = CA0 $\int_0^{XA} \frac{dXA}{-rA(1+XA εA)} $

1.	Design equation for varying volume system is ______a) t = \(\int_0^{XA} \frac{dXA}{-rA εA} \) b) t = \(\int_0^{XA} \frac{dXA}{CA0} \) c) t = \(\int_0^{XA} \frac{dXA}{NA0} \) d) t = CA0 \(\int_0^{XA} \frac{dXA}{-rA(1+XA ε
A.	t = \(\int_0^{XA} \frac{dXA}{-rA εA} \)
B.	t = \(\int_0^{XA} \frac{dXA}{CA0} \)
C.	t = \(\int_0^{XA} \frac{dXA}{NA0} \)
D.	t = CA0 \(\int_0^{XA} \frac{dXA}{-rA(1+XA εA)} \)
Answer» E.

Design equation for varying volume system is ______a) t = \(\int_0^{XA} \frac{dXA}{-rA εA} \) b) t = \(\int_0^{XA} \frac{dXA}{CA0} \) c) t = \(\int_0^{XA} \frac{dXA}{NA0} \) d) t = CA0 \(\int_0^{XA} \frac{dXA}{-rA(1+XA ε

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