At the terminal of a 3ϕ, 6.6 kV, 10 MVA alternator, a load R = 200 Ω is connected between two phases, and other phase is kept open. The sequence impedance of the alternator is Z1 = Z2 = j 5Ω and Z0 = j2Ω. What is the current through the load resistance?

At the terminal of a 3ϕ, 6.6 kV, 10 MVA alternator, a load R = 200 Ω

1.	At the terminal of a 3ϕ, 6.6 kV, 10 MVA alternator, a load R = 200 Ω is connected between two phases, and other phase is kept open. The sequence impedance of the alternator is Z1 = Z2 = j 5Ω and Z0 = j2Ω. What is the current through the load resistance?
A.	50 A
B.	60 A
C.	75 A
D.	32 A
Answer» E.

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At the terminal of a 3ϕ, 6.6 kV, 10 MVA alternator, a load R = 200 Ω is connected between two phases, and other phase is kept open. The sequence impedance of the alternator is Z1 = Z2 = j 5Ω and Z0 = j2Ω. What is the current through the load resistance?

At the terminal of a 3ϕ, 6.6 kV, 10 MVA alternator, a load R = 200 Ω is connected between two phases, and other phase is kept open. The sequence impedance of the alternator is Z1 = Z2 = j 5Ω and Z0 = j2Ω. What is the current through the load resistance?

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