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| 1. |
An element of density 8.0 g/cm3 forms an FCC lattice with unit cell edge of 300 pm. Calculate the number of atoms present in 0.5kg of the element. |
| A. | 95 x 10<sup>23</sup> atoms |
| B. | 93.59 x 10<sup>23</sup> atoms |
| C. | 92.59 x 10<sup>23</sup> atoms |
| D. | 91.38 x 10<sup>23</sup> atoms |
| Answer» D. 91.38 x 10<sup>23</sup> atoms | |