MCQOPTIONS
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MCQOPTIONS
This section includes 7 Mcqs, each offering curated multiple-choice questions to sharpen your Linear Integrated Circuit knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
The output voltage of a summing amplifier is equal to (assume sum of input voltage as Vn ) |
| A. | V<sub>n</sub> (non-inverting terminal)+ V<sub>n</sub> (inverting terminal) |
| B. | V<sub>n</sub> (non-inverting terminal)+ (-V<sub>n</sub> (inverting terminal) |
| C. | -V<sub>n</sub> (non-inverting terminal)+ (-V<sub>n</sub> (inverting terminal) |
| D. | -V<sub>n</sub> (non-inverting terminal)+ V<sub>n</sub> (inverting terminal) |
| Answer» C. -V<sub>n</sub> (non-inverting terminal)+ (-V<sub>n</sub> (inverting terminal) | |
| 2. |
How many additional sources are connected to each input terminal to obtain an eight input summing amplifier? |
| A. | Six |
| B. | Three |
| C. | Four |
| D. | Eight |
| Answer» C. Four | |
| 3. |
Calculate the output voltage, when a voltage of 12mv is applied to the non-inverting terminal and 7mv is applied to inverting terminal of a subtractor. |
| A. | 19mv |
| B. | 5mv |
| C. | 1.7mv |
| D. | 8.4mv |
| Answer» C. 1.7mv | |
| 4. |
Find the type of amplifier that cannot be constructed in differential configuration? |
| A. | Summing amplifier |
| B. | Scaling amplifier |
| C. | Averaging amplifier |
| D. | Subtractor |
| Answer» D. Subtractor | |
| 5. |
If the gain of a non-inverting averaging amplifier is one, determine the input voltages if the output voltage, if the output voltage is 3v? |
| A. | V<sub>1</sub> =6v ,V<sub>2</sub>=3v and V<sub>3</sub>=2v |
| B. | V<sub>1</sub> =9v ,V<sub>2</sub>=5v and V<sub>3</sub>=-4v |
| C. | V<sub>1</sub> =8v ,V<sub>2</sub>=-6v and V<sub>3</sub>=1v |
| D. | V<sub>1</sub> =7v ,V<sub>2</sub>=4v and V<sub>3</sub>=-3v |
| Answer» E. | |
| 6. |
Expression for output voltage of non-inverting summing amplifier with five input voltage? |
| A. | V<sub>o</sub> = 5 ( V<sub>a</sub> + V<sub>b</sub>+ V<sub>c</sub>+ V<sub>d</sub>+ V<sub>e</sub>) |
| B. | V<sub>o</sub> = [1+( R<sub>f</sub>/R<sub>1</sub>)] ( V<sub>a</sub> + V<sub>b</sub>+ V<sub>c</sub>+ V<sub>d</sub>+ V<sub>e</sub>) |
| C. | V<sub>o</sub> = V<sub>a</sub> + V<sub>b</sub>+ V<sub>c</sub>+ V<sub>d</sub>+ V<sub>e</sub> |
| D. | V<sub>o</sub> = ( V<sub>a</sub> + V<sub>b</sub>+ V<sub>c</sub>+ V<sub>d</sub>+ V<sub>e</sub>) /5 |
| Answer» D. V<sub>o</sub> = ( V<sub>a</sub> + V<sub>b</sub>+ V<sub>c</sub>+ V<sub>d</sub>+ V<sub>e</sub>) /5 | |
| 7. |
Which type of amplifier has output voltage equal to the average of all input voltages? |
| A. | Inverting averaging amplifier |
| B. | Non-inverting averaging amplifier |
| C. | Non-inverting summing amplifier |
| D. | Inverting scaling amplifier |
| Answer» C. Non-inverting summing amplifier | |