1365 + Mcqs in Simplification Page 23 McqOptions

1101.	43% of 616.6 + 37% of 217 =?
A.	345.428
B.	354.428
C.	344.428
D.	364.428
Answer» B. 354.428

Discussion

1102.	4x2Â +Â kxÂ +Â 5Â is divisible by . The same expression is also divisible by:_x005F_x000D_
A.	4x + 5
B.	4x âˆ’ 1
C.	4x âˆ’ 5
D.	x âˆ’ 5
Answer» B. 4x âˆ’ 1

Discussion

1103.	45Â +Â 47Â =Â ?_x005F_x000D_
A.	44538
B.	48/35
C.	12997
D.	16/35
Answer» C. 12997

Discussion

1104.	4Â +Â (16)Â [-10Â xÂ 25Â -Â 13Â -Â 3Â Ã·Â -5]Â =Â ?_x005F_x000D_
A.	8
B.	9
C.	6
D.	7
Answer» E.

Discussion

1105.	3cosA is equal to
A.	4cos3AÂ +Â 3cosA
B.	4cos3AÂ -Â 3cosA
C.	3cos3AÂ +Â 3cosA
D.	3cos3AÂ -Â 3cosA
Answer» C. 3cos3AÂ +Â 3cosA

Discussion

1106.	{39 âˆ’ (19 âˆ’ 44)} Ã· {âˆ’4 Ã— 3 âˆ’ (âˆ’4)}=_x005F_x000D_ Â _x005F_x000D_
A.	-6
B.	-4
C.	-8
D.	-5
Answer» D. -5

Discussion

1107.	38% of 7500 + Â ?% of 375 = 50% of 6000
A.	50
B.	40
C.	60
D.	45
Answer» C. 60

Discussion

1108.	3.0005 âˆ’ 1.748 = ?_x005F_x000D_
A.	1.2525
B.	1.257
C.	2.8257
D.	1.9257
Answer» B. 1.257

Discussion

1109.	3 + [32 Ã· 8 Ã— 52 Ã· (4 + 9)] =?_x005F_x000D_
A.	19
B.	20
C.	21
D.	18
Answer» B. 20

Discussion

1110.	35+37=?_x005F_x000D_
A.	935
B.	612
C.	1135
D.	635
Answer» D. 635

Discussion

1111.	312Â ofÂ 25+41535-25_x005F_x000D_
A.	44382
B.	44352
C.	44322
D.	44349
Answer» C. 44322

Discussion

1112.	2sin[(C+D)/2].sin[(DÂ-C)/2] is equal to
A.	cosC + cosD
B.	cosC Â- cosD
C.	sinC Â- sinD
D.	sinC + sinD
Answer» C. sinC Â- sinD

Discussion

1113.	2sin[(C+D)/2].cos[(CÂ-D)/2] is equal to
A.	sinC Â-Â sinD
B.	cosC + cosD
C.	cosC -Â cosD
D.	sinC + sinD
Answer» E.

Discussion

1114.	2sinAsinB is equal to
A.	sin(A+B) + sin(AÂ-B)
B.	cos(A-Â'-Â cos(A+B)
C.	sin(A+B) -Â sin(A-ÂB)
D.	cos(A+B) + cos(A-ÂB)
Answer» C. sin(A+B) -Â sin(A-ÂB)

Discussion

1115.	2cos[(C+D)/2]sin[(C-D)/2] is equal to
A.	sinC + sinD
B.	sinC - sinD
C.	cosC - cosD
D.	cosC + cosD
Answer» C. cosC - cosD

Discussion

1116.	252Â Ã·Â [51Â -Â 27Â -Â 9Â -Â 8Â +Â 7Â¯Â ]Â =Â ?_x005F_x000D_
A.	14
B.	9
C.	7
D.	18
Answer» B. 9

Discussion

1117.	25a2Â -Â 9Â Â is factored as_x005F_x000D_
A.	(5a + 3)(5a - 3)
B.	(5a + 1)(5a - 9)
C.	5aÂ -Â 32
D.	(25a + 1)(a - 9)
Answer» B. (5a + 1)(5a - 9)

Discussion

1118.	25 - 1/2{5 + 4 - (3 + 2 - 1 + 3)} = ?
A.	21
B.	23
C.	22
D.	24
Answer» E.

Discussion

1119.	23 x 31 = 713. How much is 0.0713 / 3.1?
A.	0.23
B.	0.0023
C.	2.3
D.	0.023
Answer» E.

Discussion

1120.	23 x 19 = 437. How much is 0.0437 / 1.9 = ?
A.	0.0023
B.	0.23
C.	0.023
D.	2.3
Answer» E.

Discussion

1121.	23-[24-25-(26-27-28Â¯)]=?_x005F_x000D_ Â _x005F_x000D_
A.	-2
B.	-3
C.	-1
D.	1
Answer» D. 1

Discussion

1122.	217 x 217 + 183 x 183 = ?
A.	84521
B.	87487
C.	80578
D.	78458
Answer» D. 78458

Discussion

1123.	{20 âˆ’ (25 âˆ’ 33)} Ã· {âˆ’5 Ã— 4 âˆ’ (âˆ’6)} + 56 Ã· (âˆ’27 + 13) =?_x005F_x000D_
A.	-4
B.	-2
C.	4
D.	-6
Answer» E.

Discussion

1124.	2*[Â0.3(1.3 + 3.7)] of 0.8 = ?
A.	Â1.92
B.	-0.72
C.	2.16
D.
Answer» E.

Discussion

1125.	22Â -Â 33Â +Â 43Â -Â 62Â =Â ?_x005F_x000D_
A.	2
B.	3
C.	4
D.	5
Answer» E.

Discussion

1126.	2 âˆ’ [3 âˆ’ {6 âˆ’ (5 âˆ’ 4 âˆ’ 3 + 10)}]= ?_x005F_x000D_ Â _x005F_x000D_
A.	4
B.	2
C.	1
D.	-3
Answer» E.

Discussion

1127.	199994 x 200006 = ?
A.	39999799964
B.	39999999864
C.	39999999954
D.	39999999964
Answer» E.

Discussion

1128.	1960.196=19.6xthen what will be the value of x?_x005F_x000D_
A.	1.96
B.	10.96
C.	0.0196
D.	0.196
Answer» D. 0.196

Discussion

1129.	19 x 23 = 437. Then 190 x 0.023 = ?
A.	43.7
B.	4.37
C.	0.0437
D.	0.437
Answer» C. 0.0437

Discussion

1130.	[15% of 300% of 560] Ã— 2 Ã· 5 =
A.	100
B.	90
C.	85
D.	105
Answer» B. 90

Discussion

1131.	144 Ã· [40 âˆ’ {37 âˆ’ (25 âˆ’ 112 Ã· 7 Ã— 4)}] =?_x005F_x000D_
A.	4
B.	2
C.	8
D.	6
Answer» E.

Discussion

1132.	1397 x 1397 = ?_x005F_x000D_ Here what replaces '?'
A.	1951609
B.	1821504
C.	2031489
D.	1847879
Answer» B. 1821504

Discussion

1133.	125 - 73 + 48 - 137 + 99 = ?
A.	237
B.	62
C.	-37
D.	52
Answer» C. -37

Discussion

1134.	1.123 + 11.23 + 112.3 = ?_x005F_x000D_
A.	123.453
B.	124.653
C.	125.253
D.	123.953
Answer» C. 125.253

Discussion

1135.	111Ã·[âˆ’52+(âˆ’4)Â ofÂ 33Ã·(âˆ’22Ã·âˆ’2)]_x005F_x000D_ Â _x005F_x000D_
A.	-37
B.	-5
C.	-3
D.	37
Answer» D. 37

Discussion

1136.	105 Ã— 2 Ã· (3 Ã— 5) âˆ’ 6 =?_x005F_x000D_
A.	-70
B.	5
C.	8
D.	35
Answer» D. 35

Discussion

1137.	10+10(9) =
A.	180
B.	110
C.	100
D.	19
Answer» D. 19

Discussion

1138.	1.004 - 0.4 is equal to
A.	0.604
B.	0.006
C.	0.64
D.	1
Answer» B. 0.006

Discussion

1139.	10 dozen apples, 15 dozen mangoes & 20 dozen oranges are kept for sale. 1/2, 1/3rd & 1/4th of each item respectively have been added. What is the total number of fruits kept for sale now?
A.	720
B.	600
C.	580
D.	820
Answer» B. 600

Discussion

1140.	1/(tanA + cotA) is equal to
A.	(cosecA + sinA)(secA - cosA)
B.	âˆš[(cosecA - sinA)(secA - cosA)]
C.	âˆš[(cosecA + sinA)(secA - cosA)]
D.	(cosecA - sinA)(secA - cosA)
Answer» E.

Discussion

1141.	1/(secA + tanA) is equal to
A.	cosecA - cotA
B.	sinA - cosA
C.	secA - tanA
D.	sinA + cosA
Answer» D. sinA + cosA

Discussion

1142.	(1 + sec 20Â° + cot 70Â°)(1 - cosec 20Â° + tan70Â°) is equal to
A.	0
B.	1
C.	2
D.	3
Answer» D. 3

Discussion

1143.	1Â +Â 12Â +Â 14Â +Â 116Â +Â 132Â +Â 164Â is approximately equals to_x005F_x000D_
A.	1.5
B.	2
C.	2.5
D.	3
Answer» C. 2.5

Discussion

1144.	(0.2 x 0.2 x 0.2)(0.06 x 0.06 x 0.06) / (0.12 x 0.12 x 0.12) = ?
A.	0.008
B.	0.001
C.	0.002
D.	0.006
Answer» C. 0.002

Discussion

1145.	0.296 + 2.96 + 29.6 + 296 = ?
A.	327.856
B.	328.756
C.	328.856
D.	327.756
Answer» D. 327.756

Discussion

1146.	0.196 + 1.96 + 19.6 + 196 = ?
A.	217.756
B.	216.856
C.	216.756
D.	217.676
Answer» B. 216.856

Discussion

1147.	0.98940.97âˆ’150=_x005F_x000D_ Â _x005F_x000D_
A.	0.98
B.	1
C.	1.02
D.	1.2
Answer» C. 1.02

Discussion

1148.	What is the value of (sin60Â° - 2/âˆš3) ?
A.	-1/2âˆš3
B.	-0.5
C.	1/âˆš3
D.	(1-2âˆš3)/2
Answer» B. -0.5

Discussion

1149.	0.33Â +Â 0.23Â 0.3Â -Â 0.22Â =Â ?_x005F_x000D_
A.	44232
B.	2
C.	44234
D.	44230
Answer» D. 44230

Discussion

1150.	0
A.	1
B.
C.	416/87
D.	213/4
Answer» D. 213/4

Discussion

Explore topic-wise MCQs in Arithmetic Ability.

43% of 616.6 + 37% of 217 =?

4x2Â +Â kxÂ +Â 5Â is divisible by . The same expression is also divisible by:_x005F_x000D_

45Â +Â 47Â =Â ?_x005F_x000D_

4Â +Â (16)Â [-10Â xÂ 25Â -Â 13Â -Â 3Â Ã·Â -5]Â =Â ?_x005F_x000D_

3cosA is equal to

{39 âˆ’ (19 âˆ’ 44)} Ã· {âˆ’4 Ã— 3 âˆ’ (âˆ’4)}=_x005F_x000D_ Â _x005F_x000D_

38% of 7500 + Â ?% of 375 = 50% of 6000

3.0005 âˆ’ 1.748 = ?_x005F_x000D_

3 + [32 Ã· 8 Ã— 52 Ã· (4 + 9)] =?_x005F_x000D_

35+37=?_x005F_x000D_

312Â ofÂ 25+41535-25_x005F_x000D_

2sin[(C+D)/2].sin[(DÂ­-C)/2] is equal to

2sin[(C+D)/2].cos[(CÂ­-D)/2] is equal to

2sinAsinB is equal to

2cos[(C+D)/2]sin[(C-D)/2] is equal to

252Â Ã·Â [51Â -Â 27Â -Â 9Â -Â 8Â +Â 7Â¯Â ]Â =Â ?_x005F_x000D_

25a2Â -Â 9Â Â is factored as_x005F_x000D_

25 - 1/2{5 + 4 - (3 + 2 - 1 + 3)} = ?

23 x 31 = 713. How much is 0.0713 / 3.1?

23 x 19 = 437. How much is 0.0437 / 1.9 = ?

23-[24-25-(26-27-28Â¯)]=?_x005F_x000D_ Â _x005F_x000D_

217 x 217 + 183 x 183 = ?

{20 âˆ’ (25 âˆ’ 33)} Ã· {âˆ’5 Ã— 4 âˆ’ (âˆ’6)} + 56 Ã· (âˆ’27 + 13) =?_x005F_x000D_

2*[Â­0.3(1.3 + 3.7)] of 0.8 = ?

22Â -Â 33Â +Â 43Â -Â 62Â =Â ?_x005F_x000D_

2 âˆ’ [3 âˆ’ {6 âˆ’ (5 âˆ’ 4 âˆ’ 3 + 10)}]= ?_x005F_x000D_ Â _x005F_x000D_

199994 x 200006 = ?

1960.196=19.6xthen what will be the value of x?_x005F_x000D_

19 x 23 = 437. Then 190 x 0.023 = ?

[15% of 300% of 560] Ã— 2 Ã· 5 =

144 Ã· [40 âˆ’ {37 âˆ’ (25 âˆ’ 112 Ã· 7 Ã— 4)}] =?_x005F_x000D_

1397 x 1397 = ?_x005F_x000D_ Here what replaces '?'

125 - 73 + 48 - 137 + 99 = ?

1.123 + 11.23 + 112.3 = ?_x005F_x000D_

111Ã·[âˆ’52+(âˆ’4)Â ofÂ 33Ã·(âˆ’22Ã·âˆ’2)]_x005F_x000D_ Â _x005F_x000D_

105 Ã— 2 Ã· (3 Ã— 5) âˆ’ 6 =?_x005F_x000D_

10+10(9) =

1.004 - 0.4 is equal to

10 dozen apples, 15 dozen mangoes & 20 dozen oranges are kept for sale. 1/2, 1/3rd & 1/4th of each item respectively have been added. What is the total number of fruits kept for sale now?

1/(tanA + cotA) is equal to

1/(secA + tanA) is equal to

(1 + sec 20Â° + cot 70Â°)(1 - cosec 20Â° + tan70Â°) is equal to

1Â +Â 12Â +Â 14Â +Â 116Â +Â 132Â +Â 164Â is approximately equals to_x005F_x000D_

(0.2 x 0.2 x 0.2)(0.06 x 0.06 x 0.06) / (0.12 x 0.12 x 0.12) = ?

0.296 + 2.96 + 29.6 + 296 = ?

0.196 + 1.96 + 19.6 + 196 = ?

0.98940.97âˆ’150=_x005F_x000D_ Â _x005F_x000D_

What is the value of (sin60Â° - 2/âˆš3) ?

0.33Â +Â 0.23Â 0.3Â -Â 0.22Â =Â ?_x005F_x000D_

0

2sin[(C+D)/2].sin[(DÂ-C)/2] is equal to

2sin[(C+D)/2].cos[(CÂ-D)/2] is equal to

2*[Â0.3(1.3 + 3.7)] of 0.8 = ?