MCQOPTIONS
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This section includes 7 Mcqs, each offering curated multiple-choice questions to sharpen your Network Theory knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
A lattice phase equalizer is a constant equalizer which satisfies the equation? |
| A. | Z<sub>1</sub>Z<sub>2</sub> = R<sub>o</sub> |
| B. | Z<sub>1</sub> + Z<sub>2</sub> = R<sub>o</sub> |
| C. | 1/Z<sub>1</sub>+1/Z<sub>2</sub> = R<sub>o</sub> |
| D. | Z<sub>1</sub>Z<sub>2</sub> = R<sub>o</sub><sup>2</sup> |
| Answer» E. | |
| 2. |
The bridged-T phase equalizer consists of? |
| A. | Only pure inductors |
| B. | Only pure capacitors |
| C. | Only pure resistors |
| D. | Only pure reactance |
| Answer» E. | |
| 3. |
The attenuation is not sharp in the stop band for an m-derived filter. |
| A. | True |
| B. | False |
| Answer» C. | |
| 4. |
The propagation constant of a symmetrical T-section and -section are the same. |
| A. | True |
| B. | False |
| Answer» B. False | |
| 5. |
The value of N in shunt equalizer is? |
| A. | 1+ X<sub>1</sub><sup>2</sup>/R<sub>o</sub><sup>2</sup> |
| B. | X<sub>1</sub><sup>2</sup>/R<sub>o</sub><sup>2</sup> |
| C. | 1+ R<sub>o</sub><sup>2</sup>/X<sub>1</sub><sup>2</sup> |
| D. | R<sub>o</sub><sup>2</sup>/X<sub>1</sub><sup>2</sup> |
| Answer» D. R<sub>o</sub><sup>2</sup>/X<sub>1</sub><sup>2</sup> | |
| 6. |
What is the power at the load of a shunt equalizer? |
| A. | [(V<sub>max</sub><sup>2</sup> X<sub>1</sub><sup>2</sup>)/(R<sub>o</sub>(R<sub>o</sub><sup>2</sup>+X<sub>1</sub><sup>2</sup>))] |
| B. | [(V<sub>max</sub><sup>2</sup> X<sub>1</sub><sup>2</sup>)/(2R<sub>o</sub>(R<sub>o</sub><sup>2</sup>+X<sub>1</sub><sup>2</sup>))] |
| C. | [(V<sub>max</sub><sup>2</sup> X<sub>1</sub><sup>2</sup>)/(3R<sub>o</sub>(R<sub>o</sub><sup>2</sup>+X<sub>1</sub><sup>2</sup>))] |
| D. | [(V<sub>max</sub><sup>2</sup> X<sub>1</sub><sup>2</sup>)/(4R<sub>o</sub>(R<sub>o</sub><sup>2</sup>+X<sub>1</sub><sup>2</sup>))] |
| Answer» E. | |
| 7. |
What is the load current in terms of Vmax in the shunt equalizer? |
| A. | (V<sub>max</sub>jX<sub>1</sub>)/(R<sub>o</sub>(2R<sub>o</sub>+jX<sub>1</sub>)) |
| B. | (V<sub>max</sub>jX<sub>1</sub>)/(2R<sub>o</sub>(2R<sub>o</sub>+jX<sub>1</sub>)) |
| C. | (V<sub>max</sub>jX<sub>1</sub>)/(2R<sub>o</sub>(R<sub>o</sub>+jX<sub>1</sub>)) |
| D. | (V<sub>max</sub>jX<sub>1</sub>)/(R<sub>o</sub>(R<sub>o</sub>+jX<sub>1</sub>)) |
| Answer» D. (V<sub>max</sub>jX<sub>1</sub>)/(R<sub>o</sub>(R<sub>o</sub>+jX<sub>1</sub>)) | |