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This section includes 477 Mcqs, each offering curated multiple-choice questions to sharpen your Computer Science Engineering (CSE) knowledge and support exam preparation. Choose a topic below to get started.
| 351. |
Say s=â€hello†what will be the return value of type(s)? |
| A. | int |
| B. | bool |
| C. | str |
| D. | string |
| Answer» D. string | |
| 352. |
What will be displayed by print(ord(‘b’) – ord(‘a’))? |
| A. | 0 |
| B. | 1 |
| C. | -1 |
| D. | 2 |
| Answer» C. -1 | |
| 353. |
>>>print("A", end = ' ') |
| A. | dcba |
| B. | a, b, c, d |
| C. | d c b a |
| D. | d, c, b, a will be displayed on four lines |
| Answer» D. d, c, b, a will be displayed on four lines | |
| 354. |
+2+3? |
| A. | hello123 |
| B. | hello |
| C. | error |
| D. | hello6 |
| Answer» D. hello6 | |
| 355. |
The format function, when applied on a string returns |
| A. | error |
| B. | int |
| C. | bool |
| D. | str |
| Answer» E. | |
| 356. |
Which of the following statement prints hello\example\test.txt? |
| A. | print(“hello\\example\\test.txtâ€) |
| B. | print(“hello\\example\\test.txtâ€) |
| C. | print(“hello\\â€example\\â€test.txtâ€) |
| D. | print(“helloâ€\\exampleâ€\\test.txtâ€) |
| Answer» C. print(“hello\\â€example\\â€test.txtâ€) | |
| 357. |
>>>print(chr(ord('b')+1)) |
| A. | a |
| B. | b |
| C. | c |
| D. | a |
| Answer» D. a | |
| 358. |
Suppose s is “\t\tWorld\nâ€, what is s.strip()? |
| A. | \\t\\tworld\\n |
| B. | \\t\\tworld\\n |
| C. | \\t\\tworld\\n |
| D. | world |
| Answer» E. | |
| 359. |
>>>chr(ord('A')) |
| A. | a |
| B. | b |
| C. | a |
| D. | error |
| Answer» B. b | |
| 360. |
To concatenate two strings to a third what statements are applicable? |
| A. | s3 = s1 . s2 |
| B. | s3 = s1.add(s2) |
| C. | s3 = s1.    add    (s2) |
| D. | s3 = s1 * s2 |
| Answer» D. s3 = s1 * s2 | |
| 361. |
>>>example[::-1].startswith("d") |
| A. | dlrowolleh |
| B. | true |
| C. | -1 |
| D. | none |
| Answer» C. -1 | |
| 362. |
>>>example.rfind("e") |
| A. | -1 |
| B. | 4 |
| C. | 3 |
| D. | 1 |
| Answer» C. 3 | |
| 363. |
>>>example.find("e") |
| A. | error |
| B. | -1 |
| C. | 1 |
| Answer» D. | |
| 364. |
Given a string example=â€hello†what is the output of example.count(‘l’)? |
| A. | 2 |
| B. | 1 |
| C. | none |
| Answer» B. 1 | |
| 365. |
>>>max("what are you") |
| A. | error |
| B. | u |
| C. | t |
| D. | y |
| Answer» E. | |
| 366. |
>>>print example |
| A. | snow |
| B. | snow world |
| C. | error |
| D. | snos world |
| Answer» D. snos world | |
| 367. |
>>>print(temp.id) |
| A. | 224 |
| B. | error |
| C. | 12 |
| D. | none |
| Answer» D. none | |
| 368. |
>>>print "%d %d" % (obj.o1, obj.o2) |
| A. | none none |
| B. | none 22 |
| C. | 22 none |
| D. | error is generated |
| Answer» E. | |
| 369. |
>>>print("%s" % example[4:7]) |
| A. | wo |
| B. | world |
| C. | sn |
| D. | rl |
| Answer» B. world | |
| 370. |
>>>str1[::-1] |
| A. | dlrowolleh |
| B. | hello |
| C. | world |
| D. | helloworld |
| Answer» B. hello | |
| 371. |
>>>print (r"\nhello") |
| A. | a new line and hello |
| B. | \\nhello |
| C. | the letter r and then hello |
| D. | error |
| Answer» C. the letter r and then hello | |
| 372. |
xA + 0xB + 0xC) |
| A. | 0xa0xb0xc |
| B. | error |
| C. | 0x22 |
| D. | 33 |
| Answer» E. | |
| 373. |
What arithmetic operators cannot be used with strings? |
| A. | + |
| B. | * |
| C. | – |
| D. | all of the mentioned |
| Answer» D. all of the mentioned | |
| 374. |
>>>print('new' 'line') |
| A. | error |
| B. | output equivalent to print ‘new\\nline’ |
| C. | newline |
| D. | new line |
| Answer» D. new line | |
| 375. |
>>>"abcd"[2:] |
| A. | a |
| B. | ab |
| C. | cd |
| D. | dc |
| Answer» D. dc | |
| 376. |
>>> str1[-1:] |
| A. | olleh |
| B. | hello |
| C. | h |
| D. | o |
| Answer» E. | |
| 377. |
>>>"a"+"bc" |
| A. | a |
| B. | bc |
| C. | bca |
| D. | abc |
| Answer» E. | |
| 378. |
] in a: print(a[0]) |
| A. | 0 1 2 3 |
| B. | 0 1 2 2 |
| C. | 3 3 3 3 |
| D. | error |
| Answer» B. 0 1 2 2 | |
| 379. |
0)): print(i) |
| A. | 0.0 1.0 |
| B. | 0 1 |
| C. | error |
| D. | none of the mentioned |
| Answer» C. error | |
| 380. |
0): print(i) |
| A. | 0.0 1.0 |
| B. | 0 1 |
| C. | error |
| D. | none of the mentioned |
| Answer» D. none of the mentioned | |
| 381. |
30) |
| A. | true |
| B. | false |
| C. | error |
| D. | no output |
| Answer» C. error | |
| 382. |
R operator. Hence the output of the code shown above is: 20 10. |
| A. | 1011011 |
| B. | 11010100 |
| C. | 11101011 |
| D. | 10110011 |
| Answer» C. 11101011 | |
| 383. |
): print(i) |
| A. | 0 |
| B. | no output |
| C. | error |
| D. | none of the mentioned |
| Answer» C. error | |
| 384. |
-2)+bin(12^4) |
| A. | 0b10000 |
| B. | 0b10001000 |
| C. | 0b1000b1000 |
| D. | 0b10000b1000 |
| Answer» E. | |
| 385. |
Which of the following expressions can be used to multiply a given number ‘a’ by 4? |
| A. | a<<2 |
| B. | a<<4 |
| C. | a>>2 |
| D. | a>>4 |
| Answer» B. a<<4 | |
| 386. |
^12 |
| A. | 2 |
| B. | 4 |
| C. | 8 |
| D. | 12 |
| Answer» D. 12 | |
| 387. |
Bitwise                    gives 1 if either of the bits is 1 and 0 when both of the bits are 1. |
| A. | or |
| B. | and |
| C. | xor |
| D. | not |
| Answer» D. not | |
| 388. |
00000 is also equal to 10000000. Hence the statement is false. |
| A. | 001101010 |
| B. | 110010101 |
| C. | 001101011 |
| D. | 110010100 |
| Answer» B. 110010101 | |
| 389. |
It is not possible for the two’s complement value to be equal to the original value in any case. |
| A. | true |
| B. | false |
| Answer» C. | |
| 390. |
x75 |
| A. | 115 |
| B. | 116 |
| C. | 117 |
| D. | 118 |
| Answer» D. 118 | |
| 391. |
x8) |
| A. | ‘0bx1000’ |
| B. | 8 |
| C. | 1000 |
| D. | ‘0b1000’ |
| Answer» E. | |
| 392. |
Which of the following represents the bitwise XOR operator? |
| A. | & |
| B. | ^ |
| C. | ! |
| Answer» C. ! | |
| 393. |
Which of the following expressions results in an error? |
| A. | int(1011) |
| B. | int(‘1011’,23) |
| C. | int(1011,2) |
| D. | int(‘1011’) |
| Answer» D. int(‘1011’) | |
| 394. |
1)? |
| A. | 1011 |
| B. | 11 |
| C. | 13 |
| D. | 1101 |
| Answer» B. 11 | |
| 395. |
The expression 2**2**3 is evaluates as: (2**2)**3. |
| A. | true |
| B. | false |
| Answer» C. | |
| 396. |
+2**5//10 |
| A. | 3 |
| B. | 7 |
| C. | 77 |
| Answer» C. 77 | |
| 397. |
//6%3, 24//4//2 |
| A. | (1,3) |
| B. | (0,3) |
| C. | (1,0) |
| D. | (3,1) |
| Answer» B. (0,3) | |
| 398. |
2. Hence the result of this expression is 27.2. |
| A. | 4.7 – 1.5 |
| B. | 7.9 * 6.3 |
| C. | 1.7 % 2 |
| D. | 3.4 + 4.6 |
| Answer» D. 3.4 + 4.6 | |
| 399. |
+int(2.39)%2) |
| A. | 5.0 |
| B. | 5 |
| C. | 4 |
| D. | 4 |
| Answer» D. 4 | |
| 400. |
**(3**2) (2**3)**2 2**3**2 |
| A. | 64, 512, 64 |
| B. | 64, 64, 64 |
| C. | 512, 512, 512 |
| D. | 512, 64, 512 |
| Answer» E. | |