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MCQOPTIONS
This section includes 236 Mcqs, each offering curated multiple-choice questions to sharpen your Electrical Engineering knowledge and support exam preparation. Choose a topic below to get started.
| 101. |
Observe the given figure. The maximum power to the load resistor is when RL =? |
| A. | Ri/2 |
| B. | Ri |
| C. | 4Ri |
| D. | 2Ri |
| Answer» C. 4Ri | |
| 102. |
According to Super position theorem, a Voltage source of 0 V can be replaced by a: |
| A. | 5 V |
| B. | Cannot be replaced |
| C. | Open circuit |
| D. | Short circuit |
| Answer» E. | |
| 103. |
Millman’s theorem yields: |
| A. | Equivalent voltage sources |
| B. | Equivalent voltage or current sources |
| C. | Equivalent resistance |
| D. | Equivalent impedance |
| Answer» C. Equivalent resistance | |
| 104. |
_____________ theorem is applicable to both linear and nonlinear circuits. |
| A. | Norton’s |
| B. | Substitution |
| C. | Tellegen |
| D. | Superposition |
| Answer» D. Superposition | |
| 105. |
Norton's theorem is ________ Thevenin's theorem. |
| A. | the same as |
| B. | converse of |
| C. | none of these |
| D. | cannot say |
| Answer» C. none of these | |
| 106. |
For the network shown, Thevenin's equivalent voltage source and resistance are, respectively : |
| A. | 1 mV and 10 Ω |
| B. | 1 V and 1 KΩ |
| C. | 1 mV and 1 KΩ |
| D. | 1 V and 10 Ω |
| Answer» E. | |
| 107. |
A source of 10 V with an internal resistance of 5 Ω is to be connected through a converter to a load of 20 Ω. For maximum power transfer, what should be the turns ratio of the converter? |
| A. | 1 ∶ 2 |
| B. | 1 ∶ 1 |
| C. | 2 ∶ 1 |
| D. | 1 ∶ 4 |
| Answer» B. 1 ∶ 1 | |
| 108. |
A battery charger can drive current of 5 A into a 1 Ω resistance connected at its output terminals. If it is able to charge an ideal 2 V battery at 7 A rate, then Thevenin’s equivalent will be |
| A. | 7.5 V in series with 0.5 Ω |
| B. | 12.5 V in series with 1.5 Ω |
| C. | 7.5 V in parallel with 0.5 Ω |
| D. | 12.5 V in parallel with 1.5 Ω |
| Answer» C. 7.5 V in parallel with 0.5 Ω | |
| 109. |
In the circuit shown below the maximum power that can be transferred to the load ZL is |
| A. | 250 W |
| B. | 500 W |
| C. | 1000 W |
| D. | 2000 W |
| Answer» C. 1000 W | |
| 110. |
In the circuit shown, what are the values of the internal resistance across the open-circuited (a and b) and of the Thevenin’s voltage between the terminals a and b? |
| A. | 1.43 Ω and 12 V |
| B. | 7 Ω and 20 V |
| C. | 1 Ω and 11 V |
| D. | 8 Ω and 10 V |
| Answer» C. 1 Ω and 11 V | |
| 111. |
A voltage source, connected to a load, has an e.m.f. of 10 V and an impedance of (500 + j100) Ω. The maximum power that can be transferred to the load is |
| A. | 0.2 W |
| B. | 0.1 W |
| C. | 0.05 W |
| D. | 0.01 W |
| Answer» D. 0.01 W | |
| 112. |
Determine the load resistance RL that will result in maximum power delivered to the load for the given circuit. Also, determine the maximum power Pmax delivered to the load resistor. |
| A. | RL = 50 Ω; Pmax = 225 W |
| B. | RL = 35 Ω; Pmax = 200 W |
| C. | RL = 20 Ω; Pmax = 200 W |
| D. | RL = 25 Ω; Pmax = 225 W |
| Answer» E. | |
| 113. |
Norton’s theorem when applied to DC circuit results in: |
| A. | A voltage source alone |
| B. | A voltage source with a resistance in series |
| C. | A current source with resistance in parallel |
| D. | A current source alone |
| Answer» D. A current source alone | |
| 114. |
Norton’s theorem states that a complex network connected to a load can be replaced with an equivalent impedance |
| A. | in series with a current source |
| B. | in parallel with a voltage source |
| C. | in series with a voltage source |
| D. | in parallel with a current source |
| Answer» E. | |
| 115. |
For the given circuit, the maximum power in the load can be: |
| A. | 658 mW |
| B. | 10 mW |
| C. | 893 mW |
| D. | 840 mW |
| Answer» D. 840 mW | |
| 116. |
For the active network shown in figure, the value of V/I is |
| A. | 2 Ω |
| B. | 2.4 Ω |
| C. | 3.6 Ω |
| D. | 10 Ω |
| Answer» D. 10 Ω | |
| 117. |
Observe the given figure. Find Thevenin’s resistance as seen from open-circuited terminals. |
| A. | 8 ohms |
| B. | 16 ohms |
| C. | 4 ohms |
| D. | 32 ohms |
| Answer» E. | |
| 118. |
Determine the value of Thevenin’s equivalent resistance (in Ohms) across terminal A and B for the electrical circuit given below. |
| A. | 1 |
| B. | 2 |
| C. | 6 |
| D. | 8 |
| Answer» C. 6 | |
| 119. |
Maximum power will be delivered from an ac source to a resistive load in a network when the magnitude of the source impedance is equal to |
| A. | Half the load resistance |
| B. | Double the load resistance |
| C. | The load resistance |
| D. | Zero |
| Answer» E. | |
| 120. |
Consider the circuit shown above. The portion of the circuit left to the terminals AB can be replaced by |
| A. | 1 and 2 only |
| B. | 2 and 3 only |
| C. | 1, 2 and 3 only |
| D. | 1, 2, 3 and 4 |
| Answer» E. | |
| 121. |
If Thevenin's voltage is 89.3 volts and Thevenin's resistance is 46.98 ohms then what will be the maximum power delivered to the load present in the network? |
| A. | 100 W |
| B. | 42.43 W |
| C. | 456 W |
| D. | 88.09 W |
| Answer» C. 456 W | |
| 122. |
Find Thevenin's equivalent resistance for the following circuit: |
| A. | 5.67 Ω |
| B. | 6.66 Ω |
| C. | 6 Ω |
| D. | 6.25 Ω |
| Answer» C. 6 Ω | |
| 123. |
As shown in the figure, a 1Ω resistance is connected across a source that has a load line V + I = 100. The current through the resistance is |
| A. | 25 A |
| B. | 50 A |
| C. | 100 A |
| D. | 200 A |
| Answer» C. 100 A | |
| 124. |
Determine Thevenin’s equivalent resistance (in Ohms) and voltage (in V) respectively across terminal ‘a’ and ‘b’ for the given electrical circuit. |
| A. | 12, 40 |
| B. | 20, 80 |
| C. | 10, 30 |
| D. | 10, 50 |
| Answer» D. 10, 50 | |
| 125. |
Determine the value of current (in A) through the load resistance of the given circuit. |
| A. | 0.54 |
| B. | 1 |
| C. | 2 |
| D. | 0.38 |
| Answer» E. | |
| 126. |
An ac source is delivering power to a complex and ZL = 4 + j3. The maximum power is transferred if the source impedance is |
| A. | 4Ω |
| B. | j3 Ω |
| C. | (4 – j3) Ω |
| D. | (4 + j3) Ω |
| Answer» D. (4 + j3) Ω | |
| 127. |
A 20 V battery is connected with a parallel combination of resistance 6 Ω and variable R and this combination is connected with 3 Ω resistor. Now the value of the resistance R in the circuit is varied in such a way that the power dissipated in the 3 Ω resistor is maximum. Under this condition the value of R will be |
| A. | 3 Ω |
| B. | 9 Ω |
| C. | 12 Ω |
| D. | 0 Ω |
| Answer» E. | |
| 128. |
In a parallel circuit having two resistance 4Ω and 6Ω connected across a DC voltage of 12 V, the current through the 4 Ω resistance is: |
| A. | 5 A |
| B. | 2 A |
| C. | 3 A |
| D. | 1 A |
| Answer» D. 1 A | |
| 129. |
Consider following given statements about Tellegen’s theorem and choose which is / are correct.I. It is used in developing the sensitivity coefficients of a network from the concept of adjoint network.II. It is applicable to any lumped network.III. It is applicable to all electrical networks which obey Kirchhoff’s laws. |
| A. | Only I |
| B. | Both I and II |
| C. | All, I, II, III |
| D. | Both II and III |
| Answer» E. | |
| 130. |
Determine Thevenin Equivalent circuit parameters for the given circuit. |
| A. | Vth = 25 V, Rth = 20 Ω |
| B. | Vth = 50 V, Rth = 25 Ω |
| C. | Vth = 50 V, Rth = 20 Ω |
| D. | Vth = 100 V, Rth = 20 Ω |
| Answer» D. Vth = 100 V, Rth = 20 Ω | |
| 131. |
In Norton’s theorem Isc is__________ |
| A. | Sum of two current sources |
| B. | A single current source |
| C. | Infinite current sources |
| D. | 0 |
| Answer» C. Infinite current sources | |
| 132. |
Can we use Norton’s theorem on a circuit containing a BJT? |
| A. | Yes |
| B. | No |
| C. | Depends on the BJT |
| D. | Insufficient data provided |
| Answer» C. Depends on the BJT | |
| 133. |
Norton’s theorem is true for __________ |
| A. | Linear networks |
| B. | Non-Linear networks |
| C. | Both linear networks and nonlinear networks |
| D. | Neither linear networks nor non-linear networks |
| Answer» B. Non-Linear networks | |
| 134. |
If there are 10 nodes in a circuit, how many equations do we get? |
| A. | 10 |
| B. | 9 |
| C. | 8 |
| D. | 7 |
| Answer» C. 8 | |
| 135. |
The maximum power drawn from source depends on __________ |
| A. | Value of source resistance |
| B. | Value of load resistance |
| C. | Both source and load resistance |
| D. | Neither source or load resistance |
| Answer» C. Both source and load resistance | |
| 136. |
Thevenin resistance is found by ________ |
| A. | Shorting all voltage sources |
| B. | Opening all current sources |
| C. | Shorting all voltage sources and opening all current sources |
| D. | Opening all voltage sources and shorting all current sources |
| Answer» D. Opening all voltage sources and shorting all current sources | |
| 137. |
Vth is found across the ____________ terminals of the network. |
| A. | Input |
| B. | Output |
| C. | Neither input nor output |
| D. | Either input or output |
| Answer» C. Neither input nor output | |
| 138. |
The maximum power is delivered to a circuit when source resistance is __________ load resistance. |
| A. | Greater than |
| B. | Equal to |
| C. | Less than |
| D. | Greater than or equal to |
| Answer» C. Less than | |
| 139. |
Thevenin’s theorem is true for __________ |
| A. | Linear networks |
| B. | Non-Linear networks |
| C. | Both linear networks and nonlinear networks |
| D. | Neither linear networks nor non-linear networks |
| Answer» B. Non-Linear networks | |
| 140. |
If source impedance is a complex number Z, then load impedance is equal to _________ |
| A. | Z’ |
| B. | -Z |
| C. | -Z’ |
| D. | Z |
| Answer» B. -Z | |
| 141. |
The Thevenin voltage is the__________ |
| A. | Open circuit voltage |
| B. | Short circuit voltage |
| C. | Open circuit and short circuit voltage |
| D. | Neither open circuit nor short circuit voltage |
| Answer» B. Short circuit voltage | |
| 142. |
Star connection is also known as__________ |
| A. | Y-connection |
| B. | Mesh connection |
| C. | Either Y-connection or mesh connection |
| D. | Neither Y-connection nor mesh connection |
| Answer» B. Mesh connection | |
| 143. |
Delta connection is also known as____________ |
| A. | Y-connection |
| B. | Mesh connection |
| C. | Either Y-connection or mesh connection |
| D. | Neither Y-connection nor mesh connection |
| Answer» C. Either Y-connection or mesh connection | |
| 144. |
If a 1ohm 2ohm and 32/3ohm resistor is connected in star, find the equivalent delta connection. |
| A. | 34 ohm, 18.67 ohm, 3.19 ohm |
| B. | 33 ohm, 18.67 ohm, 3.19 ohm |
| C. | 33 ohm, 19.67 ohm, 3.19 ohm |
| D. | 34 ohm, 19.67 ohm, 3.19 ohm |
| Answer» B. 33 ohm, 18.67 ohm, 3.19 ohm | |
| 145. |
Ra is resistance at A, Rb is resistance at B, Rc is resistance at C in star connection. After transforming to delta, what is resistance between B and C? |
| A. | Rc+Rb+Rc*Rb/Ra |
| B. | Rc+Rb+Ra*Rb/Rc |
| C. | Ra+Rb+Ra*Rc/Rb |
| D. | Rc+Rb+Rc*Ra/Rb |
| Answer» B. Rc+Rb+Ra*Rb/Rc | |
| 146. |
In superposition theorem, when we consider the effect of one voltage source, all the other current sources are ____________ |
| A. | Shorted |
| B. | Opened |
| C. | Removed |
| D. | Undisturbed |
| Answer» C. Removed | |
| 147. |
Which, among the following is the right expression for converting from delta to star? |
| A. | R1=Ra*Rb/(Ra+Rb+Rc), R2=Rb*Rc/(Ra+Rb+Rc), R3=Rc*Ra/(Ra+Rb+Rc) |
| B. | R1=Ra/(Ra+Rb+Rc), R2=Rb/(Ra+Rb+Rc), Rc=/(Ra+Rb+Rc) |
| C. | R1=Ra*Rb*Rc/(Ra+Rb+Rc), R2=Ra*Rb/(Ra+Rb+Rc), R3=Ra/(Ra+Rb+Rc) |
| D. | R1=Ra*Rb*Rc/(Ra+Rb+Rc), R2=Ra*Rb*Rc/(Ra+Rb+Rc), R3=Ra*Rb*Rc/(Ra+Rb+Rc) |
| Answer» B. R1=Ra/(Ra+Rb+Rc), R2=Rb/(Ra+Rb+Rc), Rc=/(Ra+Rb+Rc) | |
| 148. |
Norton resistance is found by? |
| A. | Shorting all voltage sources |
| B. | Opening all current sources |
| C. | Shorting all voltage sources and opening all current sources |
| D. | Opening all voltage sources and shorting all current sources |
| Answer» D. Opening all voltage sources and shorting all current sources | |
| 149. |
Find the equivalent resistance between X and Y. |
| A. | 3.33 ohm |
| B. | 4.34 ohm |
| C. | 5.65 ohm |
| D. | 2.38 ohm |
| Answer» E. | |
| 150. |
Find the equivalent delta circuit. |
| A. | 9.69 ohm, 35.71 ohm, 6.59 ohm |
| B. | 10.69 ohm, 35.71 ohm, 6.59 ohm |
| C. | 9.69 ohm, 34.71 ohm, 6.59 ohm |
| D. | 10.69 ohm, 35.71 ohm, 7.59 ohm |
| Answer» B. 10.69 ohm, 35.71 ohm, 6.59 ohm | |