MCQOPTIONS
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MCQOPTIONS
This section includes 12 Mcqs, each offering curated multiple-choice questions to sharpen your Electromagnetic Theory knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Both the conduction and displacement current densities coexist in which medium? |
| A. | Only conductors in air |
| B. | Only dielectrics in air |
| C. | Conductors placed in any dielectric medium |
| D. | Both the densities can never coexist |
| Answer» D. Both the densities can never coexist | |
| 2. |
At dc field, the displacement current density will be |
| A. | 0 |
| B. | 1 |
| C. | Jc |
| D. | ∞ |
| Answer» B. 1 | |
| 3. |
The total current density is given as 0.5i + j – 1.5k units. Find the curl of the magnetic field intensity. |
| A. | 0.5i – 0.5j + 0.5k |
| B. | 0.5i + j -1.5k |
| C. | i – j + k |
| D. | i + j – k |
| Answer» C. i – j + k | |
| 4. |
Find the equation of displacement current density in frequency domain. |
| A. | Jd = jwεE |
| B. | Jd = jwεH |
| C. | Jd = wεE/j |
| D. | Jd = jεE/w |
| Answer» B. Jd = jwεH | |
| 5. |
An implication of the continuity equation of conductors is given by |
| A. | J = σ E |
| B. | J = E/σ |
| C. | J = σ/E |
| D. | J = jwEσ |
| Answer» B. J = E/σ | |
| 6. |
In the conversion of line integral of H into surface integral, which theorem is used? |
| A. | Green theorem |
| B. | Gauss theorem |
| C. | Stokes theorem |
| D. | It cannot be converted |
| Answer» D. It cannot be converted | |
| 7. |
Calculate the conduction density of a material with resistivity of 0.02 units and electric intensity of 12 units. |
| A. | 300 |
| B. | 600 |
| C. | 50 |
| D. | 120 |
| Answer» C. 50 | |
| 8. |
Find the conduction current density of a material with conductivity 200units and electric field 1.5 units. |
| A. | 150 |
| B. | 30 |
| C. | 400/3 |
| D. | 300 |
| Answer» E. | |
| 9. |
Find the displacement current density of a material with flux density of 5sin t |
| A. | 2.5cos t |
| B. | 2.5sin t |
| C. | 5cos t |
| D. | 5sin t |
| Answer» D. 5sin t | |
| 10. |
In dielectric medium, the Maxwell second equation becomes |
| A. | Curl(H) = Jd |
| B. | Curl(H) = Jc |
| C. | Curl(E) = Jd |
| D. | Curl(E) = Jd |
| Answer» B. Curl(H) = Jc | |
| 11. |
The Maxwell second equation that is valid in any conductor is |
| A. | Curl(H) = Jc |
| B. | Curl(E) = Jc |
| C. | Curl(E) = Jd |
| D. | Curl(H) = Jd |
| Answer» B. Curl(E) = Jc | |
| 12. |
Maxwell second equation is based on which law? |
| A. | Ampere law |
| B. | Faraday law |
| C. | Lenz law |
| D. | Coulomb law |
| Answer» B. Faraday law | |