MCQOPTIONS
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This section includes 14 Mcqs, each offering curated multiple-choice questions to sharpen your Network Theory knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
The angle between resistance and impedance in the circuit shown below. |
| A. | tan-11/ωRC |
| B. | tan-1C/ωR |
| C. | tan-1R/ωC |
| D. | tan-1ωRC |
| Answer» B. tan-1C/ωR | |
| 2. |
The magnitude of the impedance of the circuit shown below is? |
| A. | √(R+1/ωC) |
| B. | √(R-1/ωC) |
| C. | √(R2+(1/ωC)2) |
| D. | √(R2-(1/ωC)2) |
| Answer» D. √(R2-(1/ωC)2) | |
| 3. |
The phase angle between current and voltage in the circuit shown below is? |
| A. | tan-1ωL/R |
| B. | tan-1ωR/ |
| C. | tan-1R/ωL |
| D. | tan-1L/ωR |
| Answer» B. tan-1ωR/ | |
| 4. |
What is the magnitude of the impedance of the following circuit? |
| A. | √(R+ωL) |
| B. | √(R-ωL) |
| C. | √(R2+(ωL)2) |
| D. | √(R2-(ωL)2) |
| Answer» D. √(R2-(ωL)2) | |
| 5. |
The current i(t) in the circuit shown below is? |
| A. | i(t)=(Vm/(R-jωL))etjω |
| B. | i(t)=(Vm(R+jωL)) etjω |
| C. | i(t)=(Vm(R-jωL)) etjω |
| D. | i(t)=(Vm/(R+jωL)) etjω |
| Answer» E. | |
| 6. |
The voltage function v(t) in the circuit shown below is? |
| A. | v(t) = Vm e-tjω |
| B. | v(t) = Vmetjω |
| C. | v(t) = etjω |
| D. | v(t) = e-tjω |
| Answer» C. v(t) = etjω | |
| 7. |
Impedance is a complex quantity having the real part as _______ and the imaginary part as ______ |
| A. | resistance, resistance |
| B. | resistance, reactance |
| C. | reactance, resistance |
| D. | reactance, reactance |
| Answer» C. reactance, resistance | |
| 8. |
THE_MAGNITUDE_OF_THE_IMPEDANCE_OF_THE_CIRCUIT_SHOWN_ABOVE_IS??$ |
| A. | √(R+1/ωC) |
| B. | √(R-1/ωC) |
| C. | √(R<sup>2</sup>+(1/ωC)<sup>2</sup> ) |
| D. | √(R<sup>2</sup>-(1/ωC)<sup>2</sup> ) |
| Answer» D. ‚Äö√Ñ√∂‚àö‚Ć‚àö‚àÇ(R<sup>2</sup>-(1/‚âà√¨‚àö¬¢C)<sup>2</sup> ) | |
| 9. |
The angle between resistance and impedance in the circuit shown above.$ |
| A. | tan<sup>-1</sup>1/ωRC |
| B. | tan<sup>-1</sup>⁡C/ωR |
| C. | tan<sup>-1</sup>⁡R/ωC |
| D. | tan<sup>-1</sup>⁡ωRC |
| Answer» B. tan<sup>-1</sup>‚Äö√Ñ√∂‚àö√ñ¬¨‚àûC/‚âà√¨‚àö¬¢R | |
| 10. |
The phase angle between current and voltage in the circuit shown above is? |
| A. | tan<sup>-1</sup>⁡ωL/R |
| B. | tan<sup>-1</sup>⁡ωR/ |
| C. | tan<sup>-1</sup>⁡R/ωL |
| D. | tan<sup>-1</sup>⁡L/ωR |
| Answer» B. tan<sup>-1</sup>‚Äö√Ñ√∂‚àö√ñ¬¨‚àû‚âà√¨‚àö¬¢R/ | |
| 11. |
The magnitude of the impedance of the circuit shown above. |
| A. | √( R+ωL) |
| B. | √(R-ωL) |
| C. | √(R<sup>2</sup>+(ωL)<sup>2</sup> ) |
| D. | √(R<sup>2</sup>-(ωL)<sup>2</sup> ) |
| Answer» D. ‚Äö√Ñ√∂‚àö‚Ć‚àö‚àÇ(R<sup>2</sup>-(‚âà√¨‚àö¬¢L)<sup>2</sup> ) | |
| 12. |
The impedance of the circuit shown below is? |
| A. | R + jωL |
| B. | R – jωL |
| C. | R + 1/jωL |
| D. | R – 1/jωL |
| Answer» B. R ‚Äö√Ñ√∂‚àö√ë‚àö¬® j‚âà√¨‚àö¬¢L | |
| 13. |
The current i(t) in the circuit shown above is? |
| A. | i(t)=(V<sub>m</sub>/(R-jωL))e<sup>tjω</sup> |
| B. | i(t)=(V<sub>m</sub>(R+jωL)) e<sup>tjω</sup> |
| C. | i(t)=(V<sub>m</sub>(R-jωL)) e<sup>tjω</sup> |
| D. | i(t)=(V<sub>m</sub>/(R+jωL)) e<sup>tjω</sup> |
| Answer» E. | |
| 14. |
Impedance is a complex quantity having the real part as _______ and the imaginary part as ______ |
| A. | resistance, resistance |
| B. | resistance, reactance |
| C. | reactance, resistance |
| D. | reactance, reactance |
| Answer» C. reactance, resistance | |