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This section includes 9 Mcqs, each offering curated multiple-choice questions to sharpen your Fluid Mechanics knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
The dimensions of a rectangular channel is 3m×2m and the bed slope of the channel is 1 in 1000, calculate the rate of change of depth if the rate of change of specific energy is 2×10-5m. Given: n = 0.010 |
| A. | 1.43×10-5m |
| B. | 2.43×10-5m |
| C. | 3.43×10-5m |
| D. | 4.43×10-5m |
| Answer» D. 4.43×10-5m | |
| 2. |
Calculate the slope of the energy line if the bed slope of the channel is 4.81×10-5 if the depths of the channel are 2.7m and 4.7m and velocities are 1 m/s and 0.5m/s respectively. |
| A. | 2.0E-5 |
| B. | 0.00003 |
| C. | 0.00004 |
| D. | 0.00005 |
| Answer» E. | |
| 3. |
If the depths in a channel are 2m and 4m and the velocities are 0.5 m/s and 0.3m/s, calculate the difference between specific energies. |
| A. | 2m |
| B. | 3m |
| C. | 4m |
| D. | 5m |
| Answer» B. 3m | |
| 4. |
Calculate the bed slope of the channel if the slope of the energy line 0.00024 and the length of the back water curve is 104166.67m. Given:E1-E2=3m. |
| A. | 2.28×10-5 |
| B. | 3.28×10-5 |
| C. | 4.28×10-5 |
| D. | 5.28×10-5 |
| Answer» E. | |
| 5. |
If the difference between specific energies is 2m calculate the rate of change of specific energies if the length of the back water curve is 26314m. |
| A. | 6.6×10-5m |
| B. | 7.6×10-5m |
| C. | 8.6×10-5m |
| D. | 9.6×10-5m |
| Answer» C. 8.6×10-5m | |
| 6. |
Determine the length of the back water curve if E1=2.8m and E2=5.6m. Given:S0=0.00009 Sf= 0.00004. |
| A. | 26000m |
| B. | 36000m |
| C. | 46000m |
| D. | 56000m |
| Answer» E. | |
| 7. |
Estimate the slope of energy line in a GVF having length of the back water curve 30000m and head loss of 1m. |
| A. | 1.33×10-5 |
| B. | 2.33×10-5 |
| C. | 3.33×10-5 |
| D. | 4.33×10-5 |
| Answer» D. 4.33×10-5 | |
| 8. |
Calculate the head loss if the length of the back water curve is 25000m and Sf=0.00006. |
| A. | 1m |
| B. | 1.5m |
| C. | 2.0m |
| D. | 2.5m |
| Answer» C. 2.0m | |
| 9. |
What is the expression for head loss in case of a GVF? |
| A. | hf = L⁄2 Sf |
| B. | hf = LSf |
| C. | hf = 2LSf |
| D. | hf = 3LSf |
| Answer» C. hf = 2LSf | |