MCQOPTIONS
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MCQOPTIONS
This section includes 9 Mcqs, each offering curated multiple-choice questions to sharpen your Fluid Mechanics knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
CALCULATE_THE_SLOPE_OF_THE_ENERGY_LINE_IF_THE_BED_SLOPE_OF_THE_CHANNEL_IS_4.81‚ÄÖ√†√∂‚Àւ•10-5_IF_THE_DEPTHS_OF_THE_CHANNEL_ARE_2.7M_AND_4.7M_AND_VELOCITIES_ARE_1_M/S_AND_0.5M/S_RESPECTIVELY.?$# |
| A. | 0.00002 |
| B. | 0.00003 |
| C. | 0.00004 |
| D. | 0.00005 |
| Answer» E. | |
| 2. |
The_dimensions_of_a_rectangular_channel_is_3m√ó2m_and_the_bed_slope_of_the_channel_is_1_in_1000,_calculate_the_rate_of_change_of_depth_if_the_rate_of_change_of_specific_energy_is_2√ó10-5m._Given:_n_=_0.010$# |
| A. | 1.43√ó10<sup>-5</sup>m |
| B. | 2.43√ó10<sup>-5</sup>m |
| C. | 3.43√ó10<sup>-5</sup>m |
| D. | 4.43√ó10<sup>-5</sup>m |
| Answer» D. 4.43‚Äö√†√∂‚àö‚â•10<sup>-5</sup>m | |
| 3. |
If the depths in a channel are 2m and 4m and the velocities are 0.5 m/s and 0.3m/s, calculate the difference between specific energies? |
| A. | 2m |
| B. | 3m |
| C. | 4m |
| D. | 5m |
| Answer» B. 3m | |
| 4. |
Calculate the bed slope of the channel if the slope of the energy line 0.00024 and the length of the back water curve is 104166.67m. Given:E1-E2=3m. |
| A. | 2.28√ó10<sup>-5</sup> |
| B. | 3.28√ó10<sup>-5</sup> |
| C. | 4.28√ó10<sup>-5</sup> |
| D. | 5.28√ó10<sup>-5</sup> |
| Answer» E. | |
| 5. |
If the difference between specific energies is 2m calculate the rate of change of specific energies if the length of the back water curve is 26314m. |
| A. | 6.6√ó10<sup>-5</sup>m |
| B. | 7.6√ó10<sup>-5</sup>m |
| C. | 8.6√ó10<sup>-5</sup>m |
| D. | 9.6√ó10<sup>-5</sup>m |
| Answer» C. 8.6‚Äö√†√∂‚àö‚â•10<sup>-5</sup>m | |
| 6. |
Determine the length of the back water curve if E1=2.8m and E2=5.6m. Given:S0=0.00009 Sf= 0.00004. |
| A. | 26000m |
| B. | 36000m |
| C. | 46000m |
| D. | 56000m |
| Answer» E. | |
| 7. |
Estimate the slope of energy line in a GVF having length of the back water curve 30000m and head loss of 1m. |
| A. | 1.33√ó10<sup>-5</sup> |
| B. | 2.33√ó10<sup>-5</sup> |
| C. | 3.33√ó10<sup>-5</sup> |
| D. | 4.33√ó10<sup>-5</sup> |
| Answer» D. 4.33‚Äö√†√∂‚àö‚â•10<sup>-5</sup> | |
| 8. |
Calculate the head loss if the length of the back water curve is 25000m and Sf=0.00006. |
| A. | 1m |
| B. | 1.5m |
| C. | 2.0m |
| D. | 2.5m |
| Answer» C. 2.0m | |
| 9. |
What is the expression for head loss in case of a GVF? |
| A. | h<sub>f</sub> = <sup>L</sup>‚ÅÑ<sub>2</sub> S<sub>f</sub> |
| B. | h<sub>f</sub> = LS<sub>f</sub> |
| C. | h<sub>f</sub> = 2LS<sub>f</sub> |
| D. | h<sub>f</sub> = 3LS<sub>f</sub> |
| Answer» C. h<sub>f</sub> = 2LS<sub>f</sub> | |