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This section includes 9 Mcqs, each offering curated multiple-choice questions to sharpen your Mechanical Metallurgy knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
The notch sensitivity factor ________ with an increase in the tensile strength of the material. |
| A. | increases |
| B. | decreases |
| C. | remains the same |
| D. | no relationship |
| Answer» B. decreases | |
| 2. |
A material has notch sensitivity factor equal to one (q=1), the relation between the Kf and Kt for this material will be __________ |
| A. | Kf>Kt |
| B. | Kf<Kt |
| C. | Kf=Kt |
| D. | no relation between them |
| Answer» D. no relation between them | |
| 3. |
The material does not experience any reduction in the fatigue strength from the notch. The value of notch sensitivity factor (q) for this material will be equal to ___________ |
| A. | q=0 |
| B. | q=infinite |
| C. | q=1 |
| D. | q=0.5 |
| Answer» B. q=infinite | |
| 4. |
The material does not experience any reduction in the fatigue strength from the notch. The value of fatigue notch factor (Kf) for this material will be equal to ________ |
| A. | Kf=0 |
| B. | Kf=1 |
| C. | Kf=0.5 |
| D. | Kf=infinite |
| Answer» C. Kf=0.5 | |
| 5. |
The relationship between the Kf and Kt is defined as ____________ (where q is notch sensitivity factor). |
| A. | Kf=q+Kt |
| B. | q=(Kf-1)/(Kt-1) |
| C. | q=(Kf)/(Kt-1) |
| D. | q=(Kf-1)/(Kt) |
| Answer» C. q=(Kf)/(Kt-1) | |
| 6. |
A very sharp notch having high Kt has more effect on the fatigue strength than it would be expected from the value of Kt. |
| A. | True |
| B. | False |
| Answer» C. | |
| 7. |
The fatigue strength reduction factor is not affected by ____________ |
| A. | the severity of the notch |
| B. | type of notch |
| C. | type loading |
| D. | critical resolved shear stress |
| Answer» E. | |
| 8. |
The stress concentration factor and fatigue strength reduction factor are the same quantity. |
| A. | True |
| B. | False |
| Answer» C. | |
| 9. |
Find the crack growth per cycle for a steel plate where the crack growth equation is given by:-> da/dN = A(ΔK)pThe value of p=3, A= 6.9*10-18, and stress intensity factor variation is 1 kPa m1/2. |
| A. | 6.9 m/cycle |
| B. | 6.9 mm/cycle |
| C. | 6.9 nm/cycle |
| D. | 13.3 m/cycle |
| Answer» D. 13.3 m/cycle | |