MCQOPTIONS
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This section includes 7 Mcqs, each offering curated multiple-choice questions to sharpen your Power Electronics knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
THE_REACTOR_IN_CIRCULATING_CURRENT_TYPE_DUAL_CONVERTERS?$ |
| A. | increases losses |
| B. | reduces power factor |
| C. | increase the weight of the circuit |
| D. | all of the above |
| Answer» E. | |
| 2. |
If_V1_and_V2_are_the_instantaneous_voltages_of_the_two_converter_circuits_in_the_dual_convert,_then_the_output_voltage_is$ |
| A. | V1 + V2 |
| B. | (V1 + V2)/2 |
| C. | V1 – V2 |
| D. | 2(V1 + V2) |
| Answer» C. V1 ‚Äö√Ñ√∂‚àö√ë‚àö¬® V2 | |
| 3. |
Circulating current flow? |
| A. | from load to converters |
| B. | from one converter to another converter |
| C. | in the whole circuit |
| D. | none of the mentioned |
| Answer» C. in the whole circuit | |
| 4. |
In case of circulating current type dual converters, the reactor is inserted between |
| A. | supply and converter |
| B. | across the load |
| C. | between the converters |
| D. | no reactor is used in case of circulating type dual converter |
| Answer» D. no reactor is used in case of circulating type dual converter | |
| 5. |
In case of three-phase dual converter, one of the converter circuits is fired at an angle of 60°. For both the converter circuits to have equal average output voltage, what is the value of the firing angle for the other converter circuit?$ |
| A. | 60° |
| B. | 120° |
| C. | 100° |
| D. | Insufficient data |
| Answer» C. 100¬¨¬®‚Äö√†√ª | |
| 6. |
What causes circulating current in dual converters? |
| A. | Temperature issues |
| B. | Inductance in load circuit |
| C. | Out of phase voltages from both the converters |
| D. | none of the mentioned |
| Answer» D. none of the mentioned | |
| 7. |
In circulating current mode dual converters, the circulating current is avoided by |
| A. | connecting a series reactor |
| B. | maintaining α1 + α2 = 180° |
| C. | operating only one converter |
| D. | adding an extra SCR |
| Answer» B. maintaining ‚âà√≠¬¨¬±1 + ‚âà√≠¬¨¬±2 = 180¬¨¬®‚Äö√†√ª | |