Explore topic-wise MCQs in Aerodynamics.

This section includes 8 Mcqs, each offering curated multiple-choice questions to sharpen your Aerodynamics knowledge and support exam preparation. Choose a topic below to get started.

1.

Where is methods of characteristics used?

A. Designing supersonic nozzle
B. Designing fuselage’s bulkhead
C. Computing optimum wing camber
D. Designing diamond airfoil for supersonic flow
Answer» B. Designing fuselage’s bulkhead
Discussion
2.

If the flow conditions at point 1 near the nozzle wall is given, then what is the flow conditions at point 2 on the wall?

A. ν2 = θ2 + θ1 – ν3
B. ν2 = θ2 – θ1 + ν3
C. ν2 = θ2 – θ1
D. ν2 = θ2 + θ1
Answer» C. ν2 = θ2 – θ1
Discussion
3.

If we know the value of θ1,ν1 at point 1 and θ2,ν2 in a flow, then what is the flow field condition at an internal point 3 lying at the intersection of characteristic lines passing from points 1 and 2?

A. θ3 = \(\frac {(K_- )_1 + (K_+ )_2}{2}\)
B. θ3 = \(\frac {(K_- )_1 + (K_+ )_3}{2}\)
C. θ3 = \(\frac {(K_+ )_1 + (K_+ )_2 + (K_+ )_3}{2}\)
D. θ3 = \(\frac {(K_- )_1 + (K_- )_2 + (K_- )_3}{2}\)
Answer» B. θ3 = \(\frac {(K_- )_1 + (K_+ )_3}{2}\)
Discussion
4.

K+ and K– constant along the characteristic lines related velocity to J+ and J– constants.

A. True
B. False
Answer» C.
Discussion
5.

Which of these is not an application of a hodograph?

A. Solution for method of characteristics
B. Obtaining motion of celestial objects
C. Swinging Artwood’s machine
D. Determining temperature
Answer» E.
Discussion
6.

K+ and K– constant along the characteristic lines are analogous to the Reimann constants.

A. True
B. False
Answer» B. False
Discussion
7.

Which of these represents K+ constant along the C+ characteristic line?

A. θ + ν(M) = const
B. θ – ν(M) = const
C. θ + 2ν(M) = const
D. θ – 2ν(M) = const
Answer» B. θ – ν(M) = const
Discussion
8.

Which of these represent compatibility equation along C+ characteristic line?

A. dθ = tan⁡(θ – μ)
B. dθ = \(\sqrt {M^2 + 1} \frac {dV}{V}\)
C. dθ = \(\sqrt {M^2 – 1} \frac {dV}{V}\)
D. dθ = tan⁡(θ – μ)\(\frac {dV}{V}\)
Answer» D. dθ = tan⁡(θ – μ)\(\frac {dV}{V}\)
Discussion