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This section includes 19 Mcqs, each offering curated multiple-choice questions to sharpen your Digital Communications knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
The performance of non binary concatenated code depends on |
| A. | Bit errors |
| B. | Symbols errors |
| C. | Bit & Symbols errors |
| D. | None of the mentioned |
| Answer» C. Bit & Symbols errors | |
| 2. |
A concatenated code has |
| A. | Low error rate |
| B. | High complexity |
| C. | Low error rate & High complexity |
| D. | None of the mentioned |
| Answer» B. High complexity | |
| 3. |
A concatenated code uses |
| A. | One level of coding |
| B. | Two levels of coding |
| C. | Three levels of coding |
| D. | None of the mentioned |
| Answer» C. Three levels of coding | |
| 4. |
The minimum end to end delay in block interleaving is |
| A. | 2MN+2M+2 |
| B. | 2MN-2M+2 |
| C. | 2MN-2M-2 |
| D. | 2MN+2M-2 |
| Answer» C. 2MN-2M-2 | |
| 5. |
Separating the symbols makes the channel memory-less. |
| A. | True |
| B. | False |
| Answer» B. False | |
| 6. |
THE_MINIMUM_END_TO_END_DELAY_IN_BLOCK_INTERLEAVING_IS?$ |
| A. | 2MN+2M+2 |
| B. | 2MN-2M+2 |
| C. | 2MN-2M-2 |
| D. | 2MN+2M-2 |
| Answer» C. 2MN-2M-2 | |
| 7. |
A concatenated code has$ |
| A. | Low error rate |
| B. | High complexity |
| C. | Low error rate & High complexity |
| D. | None of the mentioned |
| Answer» B. High complexity | |
| 8. |
A_concatenated_code_uses$ |
| A. | One level of coding |
| B. | Two levels of coding |
| C. | Three levels of coding |
| D. | None of the mentioned |
| Answer» C. Three levels of coding | |
| 9. |
Turbo code is a |
| A. | Serial concatenation code |
| B. | Parallel concatenation code |
| C. | Block code |
| D. | None of the mentioned |
| Answer» C. Block code | |
| 10. |
Concatenated code is an example of |
| A. | Error detecting code |
| B. | Error correcting code |
| C. | Error detecting & correcting code |
| D. | None of the mentioned |
| Answer» C. Error detecting & correcting code | |
| 11. |
The_performance_of_non_binary_concatenated_code_depends_on |
| A. | Bit errors |
| B. | Symbols errors |
| C. | Bit & Symbols errors |
| D. | None of the mentioned |
| Answer» C. Bit & Symbols errors | |
| 12. |
Separating the symbols makes the channel memory-less? |
| A. | True |
| B. | False |
| Answer» B. False | |
| 13. |
The channel that exhibits multi-path fading |
| A. | Has memory |
| B. | Exhibits mutually dependent signal transmission impairments |
| C. | Received signal will be distorted |
| D. | All of the mentioned |
| Answer» E. | |
| 14. |
In interpolation |
| A. | New samples are added |
| B. | Unreliable samples are removed |
| C. | New samples are added & Unreliable samples are removed |
| D. | None of the mentioned |
| Answer» D. None of the mentioned | |
| 15. |
The ______ the error correcting capability used, the _____ will be the erasure correcting capability. |
| A. | Larger, smaller |
| B. | Smaller, larger |
| C. | Smaller, smaller |
| D. | Larger, larger |
| Answer» B. Smaller, larger | |
| 16. |
Decoding step consists of |
| A. | De-interleaving |
| B. | Decoding |
| C. | De-interleaving & Decoding |
| D. | None of the mentioned |
| Answer» D. None of the mentioned | |
| 17. |
The CIRC error control scheme includes |
| A. | Correction |
| B. | Concealment |
| C. | Correction & Concealment |
| D. | None of the mentioned |
| Answer» D. None of the mentioned | |
| 18. |
Sources of channel errors are |
| A. | Finger prints |
| B. | Air bubbles |
| C. | Unwanted particles |
| D. | All of the mentioned |
| Answer» E. | |
| 19. |
Compact disc is used for |
| A. | Digital storage |
| B. | Reproduction of audio signals |
| C. | Digital storage & Reproduction of audio signals |
| D. | None of the mentioned |
| Answer» D. None of the mentioned | |