MCQOPTIONS
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MCQOPTIONS
This section includes 13 Mcqs, each offering curated multiple-choice questions to sharpen your Electrical Engineering knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
What happens to the potential difference between the plates of a capacitor as the thickness of the dielectric slab increases? |
| A. | Increases |
| B. | Decreases |
| C. | Remains the same |
| D. | Becomes zero |
| Answer» C. Remains the same | |
| 2. |
A dielectric is basically a ________ |
| A. | Capacitor |
| B. | Conductor |
| C. | Insulator |
| D. | Semiconductor |
| Answer» D. Semiconductor | |
| 3. |
Calculate the capacitance if the dielectric constant=4, area of cross section= 10m2 and the distance of separation between the plates is 5m. |
| A. | 7.08*10-11F |
| B. | 7.08*1011F |
| C. | 7.08*10-12F |
| D. | 7.08*10-10F |
| Answer» B. 7.08*1011F | |
| 4. |
WHAT_HAPPENS_TO_THE_POTENTIAL_DIFFERENCE_BETWEEN_THE_PLATES_OF_A_CAPACITOR_AS_THE_THICKNESS_OF_THE_DIELECTRIC_SLAB_INCREASES??$ |
| A. | Increases |
| B. | Decreases |
| C. | Remains the same |
| D. | Becomes zero |
| Answer» C. Remains the same | |
| 5. |
A_DIELECTRIC_IS_BASICALLY_A_________?$ |
| A. | Capacitor |
| B. | Conductor |
| C. | Insulator |
| D. | Semiconductor |
| Answer» D. Semiconductor | |
| 6. |
Calculate the capacitance if the dielectric constant=4, area of cross section= 10m2 and the distance of separation between the plates is 5m? |
| A. | 7.08*10<sup>-11</sup>F |
| B. | 7.08*10<sup>11</sup>F |
| C. | 7.08*10<sup>-12</sup>F |
| D. | 7.08*10<sup>-10</sup>F |
| Answer» B. 7.08*10<sup>11</sup>F | |
| 7. |
If the potential difference across the plates of a capacitor is 10V and a dielectric having thickness 2m is introduced between the plates, calculate the potential difference after introducing the dielectric. The electric field strength is 2V/m. |
| A. | 4V |
| B. | 6V |
| C. | 8V |
| D. | 10V |
| Answer» C. 8V | |
| 8. |
What happens to the potential drop between the two plates of a capacitor when a dielectric is introduced between the plates? |
| A. | Increases |
| B. | Decreases |
| C. | Remains the same |
| D. | Becomes zero |
| Answer» C. Remains the same | |
| 9. |
Calculate the relative permittivity of the second dielectric if the relative permittivity of the first is 4. The electric field strength of the first dielectric is 8V/m and that of the second is 2V/m. |
| A. | 32 |
| B. | 4 |
| C. | 16 |
| D. | 8 |
| Answer» D. 8 | |
| 10. |
What happens to the capacitance when a dielectric is introduced between its plates? |
| A. | Increases |
| B. | Decreases |
| C. | Remains the same |
| D. | Becomes zero |
| Answer» B. Decreases | |
| 11. |
The electric fields of dielectrics having the same cross sectional area in series are related to their relative permittivities in which way? |
| A. | Directly proportional |
| B. | Inversely proportional |
| C. | Equal |
| D. | Not related |
| Answer» C. Equal | |
| 12. |
The electric field strength is 10N/C and the thickness of the dielectric is 3m. Calculate the potential drop in the dielectric. |
| A. | 10V |
| B. | 20V |
| C. | 30V |
| D. | 40V |
| Answer» D. 40V | |
| 13. |
Potential drop in a dielectric is equal to _______ |
| A. | Electric field strength*thickness |
| B. | Electric field strength*area of a cross section |
| C. | Electric field strength |
| D. | Zero |
| Answer» B. Electric field strength*area of a cross section | |