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This section includes 40 Mcqs, each offering curated multiple-choice questions to sharpen your Electrical Engineering knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Find branch current . |
| A. | 5.4 mA |
| B. | –5.4 mA |
| C. | 113.0 mA |
| D. | 119.6 mA |
| Answer» D. 119.6 mA | |
| 2. |
Find the node voltage . |
| A. | 6 V |
| B. | 12 V |
| C. | 4.25 V |
| D. | 3 V |
| Answer» D. 3 V | |
| 3. |
4 + 4 = 2 6 + 7 = 4 |
| A. | 0.5 A |
| B. | 50 mA |
| C. | –0.5 A |
| D. | –50 mA |
| Answer» D. –50 mA | |
| 4. |
Using the mesh current method, find the branch current, , in the above figure. |
| A. | 115 mA |
| B. | 12.5 mA |
| C. | 12.5 A |
| D. | 135 mA |
| Answer» B. 12.5 mA | |
| 5. |
What is the current through ? |
| A. | 177 mA |
| B. | 250 mA |
| C. | 500 mA |
| D. | 125 mA |
| Answer» B. 250 mA | |
| 6. |
What is the voltage drop across ? |
| A. | 3.5 V |
| B. | 4.18 V |
| C. | 1.5 V |
| D. | 145 mV |
| Answer» C. 1.5 V | |
| 7. |
What is the voltage drop across R3? |
| A. | 112 mV |
| B. | 11.25 V |
| C. | 180 mV |
| D. | 1.80 V |
| Answer» D. 1.80 V | |
| 8. |
What is the voltage drop across R2? |
| A. | 3.5 V |
| B. | 4.18 V |
| C. | 1.5 V |
| D. | 145 mV |
| Answer» C. 1.5 V | |
| 9. |
Third-order determinants are evaluated by the expansion method or by the cofactor method. |
| A. | rue |
| B. | alse |
| Answer» B. alse | |
| 10. |
Find the node voltage VA. |
| A. | 18 mV |
| B. | .18 V |
| C. | .56 V |
| D. | 56 mV |
| Answer» C. .56 V | |
| 11. |
Second-order determinants are evaluated by subtracting the signed cross-products. |
| A. | rue |
| B. | alse |
| Answer» C. | |
| 12. |
What is the current through R2? |
| A. | .19 A |
| B. | 19 mA |
| C. | .73 A |
| D. | 73 mA |
| Answer» E. | |
| 13. |
The mesh method can be applied to circuits with any number of loops. |
| A. | rue |
| B. | alse |
| Answer» B. alse | |
| 14. |
When assigning branch currents, you need not be concerned with the direction you choose. |
| A. | rue |
| B. | alse |
| Answer» B. alse | |
| 15. |
Using the mesh current method, find the branch current, IR1, in the above figure. |
| A. | 15 mA |
| B. | 2.5 mA |
| C. | 2.5 A |
| D. | 35 mA |
| Answer» B. 2.5 mA | |
| 16. |
The mesh current method is based on Kirchhoff's current law. |
| A. | rue |
| B. | alse |
| Answer» C. | |
| 17. |
What is the voltage drop across R1? |
| A. | 50 mV |
| B. | .82 V |
| C. | .18 V |
| D. | 18 mV |
| Answer» C. .18 V | |
| 18. |
In assigning the direction of branch currents. |
| A. | he directions are critical |
| B. | he directions are not critical |
| C. | hey must point into a node |
| D. | hey must point out of a node |
| Answer» C. hey must point into a node | |
| 19. |
Find I2.4I1 4I2 = 2 6I1 7I2 = 4 |
| A. | 0.0416666666666667 |
| B. | –1 A |
| C. | 100 mA |
| D. | –100 mA |
| Answer» B. –1 A | |
| 20. |
Referring to Problem 10, find branch current IR3. |
| A. | –67.8 mA |
| B. | 67.8 mA |
| C. | –5.4 mA |
| D. | 5.4 mA |
| Answer» D. 5.4 mA | |
| 21. |
The expansion method for evaluating determinants is%! |
| A. | Better than any other method |
| B. | Good for only one determinant |
| C. | More flexible than the cofactor method |
| D. | Good for second- and third-order determinants |
| Answer» E. | |
| 22. |
Third-order determinants are evaluated by the expansion method or by the cofactor method.%! |
| A. | True |
| B. | False |
| Answer» B. False | |
| 23. |
Generally, the mesh current method results in fewer equations than the node voltage method.%! |
| A. | True |
| B. | False |
| Answer» C. | |
| 24. |
When assigning branch currents, you need not be concerned with the direction you choose.%! |
| A. | True |
| B. | False |
| Answer» B. False | |
| 25. |
Using the mesh current method, find the branch current, IR1, in the above figure.%! |
| A. | 115 mA |
| B. | 12.5 mA |
| C. | 12.5 A |
| D. | 135 mA |
| Answer» B. 12.5 mA | |
| 26. |
The node voltage method is based on Kirchhoff's voltage law.%! |
| A. | True |
| B. | False |
| Answer» C. | |
| 27. |
The mesh current method is based on Kirchhoff's current law.%! |
| A. | True |
| B. | False |
| Answer» C. | |
| 28. |
The branch current method is based on Kirchhoff's voltage law and Kirchhoff's current law.%! |
| A. | True |
| B. | False |
| Answer» B. False | |
| 29. |
Find the node voltage VA.%! |
| A. | 518 mV |
| B. | 5.18 V |
| C. | 9.56 V |
| D. | 956 mV |
| Answer» C. 9.56 V | |
| 30. |
Second-order determinants are evaluated by subtracting the signed cross-products.%! |
| A. | True |
| B. | False |
| Answer» C. | |
| 31. |
What is the current through R2?%! |
| A. | 3.19 A |
| B. | 319 mA |
| C. | 1.73 A |
| D. | 173 mA |
| Answer» E. | |
| 32. |
A loop current is an actual current in a branch.%! |
| A. | True |
| B. | False |
| Answer» C. | |
| 33. |
The mesh method can be applied to circuits with any number of loops.%! |
| A. | True |
| B. | False |
| Answer» B. False | |
| 34. |
What is the voltage drop across R1?%! |
| A. | 850 mV |
| B. | 7.82 V |
| C. | 9.18 V |
| D. | 918 mV |
| Answer» C. 9.18 V | |
| 35. |
*/*_What is the voltage drop across R1?? |
| A. | 850 mV |
| B. | 7.82 V |
| C. | 9.18 V |
| D. | 918 mV |
| Answer» C. 9.18 V | |
| 36. |
*/*_The first row of a certain determinant has the numbers 3 and 5. The second row has the numbers 7 and 2. The value of this determinant is? |
| A. | 31 |
| B. | -31 |
| C. | 39 |
| D. | -29 |
| Answer» E. | |
| 37. |
_ The first row of a certain determinant has the numbers 3 and 5. The second row has the numbers 7 and 2. The value of this determinant is$? |
| A. | 31 |
| B. | -31 |
| C. | 39 |
| D. | -29 |
| Answer» E. | |
| 38. |
_In assigning the direction of branch currents.$? |
| A. | The directions are critical |
| B. | The directions are not critical |
| C. | They must point into a node |
| D. | They must point out of a node |
| Answer» C. They must point into a node | |
| 39. |
The branch current method uses. |
| A. | Kirchhoff's voltage and current laws |
| B. | Thevenin's theorem and Ohm's law |
| C. | Kirchhoff's current law and Ohm's law |
| D. | The superposition theorem and Thevenin's theorem |
| Answer» B. Thevenin's theorem and Ohm's law | |
| 40. |
Find branch current IR2. |
| A. | 5.4 mA |
| B. | -5.4 mA |
| C. | 113.0 mA |
| D. | 119.6 mA |
| Answer» D. 119.6 mA | |