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This section includes 7 Mcqs, each offering curated multiple-choice questions to sharpen your Surveying knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
If L represents the staff reading and 'x' as the angle of inclination, error due to non-verticallity of the staff will be: |
| A. | L(sin x - 1) |
| B. | L(tan x - 1) |
| C. | L(sec x - 1) |
| D. | L(cosec x - 1) |
| Answer» D. L(cosec x - 1) | |
| 2. |
Error of measurement = |
| A. | Precision - True value |
| B. | Measured value - Precision |
| C. | True value - Measured value |
| D. | None of the above |
| Answer» E. | |
| 3. |
Hypotenusal allowance is given by the expression (adopting standard conventions) |
| A. | (1 – secθ) × measured distance |
| B. | (1- cosθ) × measured distance |
| C. | (secθ - 1) × measured distance |
| D. | (cosθ -1) × measured distance |
| Answer» D. (cosθ -1) × measured distance | |
| 4. |
A steel tape weighing 6 N is suspended between two supports and has three spans. If the pull on the tape is 100 N and each span is of 10 m length, then the sag correction (in m) in the tape will be |
| A. | 0.0045 |
| B. | 0.0135 |
| C. | 0.45 |
| D. | 1.35 |
| E. | 0.009 |
| Answer» B. 0.0135 | |
| 5. |
A 100 m tape is suspended between the ends under a pull of 200 N. If the weight of the tape is 30 N, the correct distance between the tape ends will be nearly |
| A. | 100.5 m |
| B. | 100.3 m |
| C. | 100.1 m |
| D. | 99.9 m |
| Answer» E. | |
| 6. |
In a survey work, three independent angles X, Y and Z were observed with weights WX, WY, WZ, respectively. The weight of the sum of angles X, Y and Z is given by: |
| A. | \(\frac{1}{{\left( {\frac{1}{{{W_X}}} + \frac{1}{{{W_Y}}} + \frac{1}{{{W_Z}}}} \right)}}\) |
| B. | \(\left( {\frac{1}{{{W_X}}} + \frac{1}{{{W_Y}}} + \frac{1}{{{W_Z}}}} \right)\) |
| C. | \({W_X} + {W_Y} + {W_Z}\) |
| D. | \(W_X^2 + W_Y^2 + W_Z^2\) |
| Answer» B. \(\left( {\frac{1}{{{W_X}}} + \frac{1}{{{W_Y}}} + \frac{1}{{{W_Z}}}} \right)\) | |
| 7. |
If the difference in the reduced levels of the end points is H, slope correction for a slope distance 'I' will be |
| A. | H / I |
| B. | H / 2I |
| C. | H2 / I |
| D. | H2 / 2I |
| Answer» E. | |