1.

Which of one of the following is correct?

A. \(\begin{array}{*{20}{c}} {{\rm{lim}}}\\ {x \to 0} \end{array}\;\left( {\frac{{\sin 4x}}{{\sin 2x}}} \right) = 1\;and\;\begin{array}{*{20}{c}} {{\rm{lim}}}\\ {x \to 0} \end{array}\;\left( {\frac{{\tan \;x}}{x}} \right) = 1\)
B. \(\begin{array}{*{20}{c}} {{\rm{lim}}}\\ {x \to 0} \end{array}\;\left( {\frac{{\sin 4x}}{{\sin 2x}}} \right) = \infty \;and\;\begin{array}{*{20}{c}} {{\rm{lim}}}\\ {x \to 0} \end{array}\;\left( {\frac{{\tan \;x}}{x}} \right) = 1\)
C. \(\begin{array}{*{20}{c}} {{\rm{lim}}}\\ {x \to 0} \end{array}\;\left( {\frac{{\sin 4x}}{{\sin 2x}}} \right) = 2\;and\;\begin{array}{*{20}{c}} {{\rm{lim}}}\\ {x \to 0} \end{array}\;\left( {\frac{{\tan \;x}}{x}} \right) = \infty \)
D. \(\begin{array}{*{20}{c}} {{\rm{lim}}}\\ {x \to 0} \end{array}\;\left( {\frac{{\sin 4x}}{{\sin 2x}}} \right) = 2\;and\;\begin{array}{*{20}{c}} {{\rm{lim}}}\\ {x \to 0} \end{array}\;\left( {\frac{{\tan \;x}}{x}} \right) = 1\)
Answer» E.


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