What will be the output of the program?
#include
int fun(int **ptr);

int main()
{
int i=10;
const int *ptr = &i;
fun(&ptr);
return 0;
}
int fun(int **ptr)
{
int j = 223;
int *temp = &j;
printf("Before changing ptr = %5x
", *ptr);
const *ptr = temp;
printf("After changing ptr = %5x
", *ptr);
return 0;
}

Question

What will be the output of the program?
#include
int fun(int **ptr);

int main()
{
    int i=10;
    const int *ptr = &i;
    fun(&ptr);
    return 0;
}
int fun(int **ptr)
{
    int j = 223;
    int *temp = &j;
    printf("Before changing ptr = %5x
", *ptr);
    const *ptr = temp;
    printf("After changing ptr = %5x
", *ptr);
    return 0;
}

TuteeHUB · Accepted Answer

Garbage value

TuteeHUB · Answer

Address of iAddress of j

TuteeHUB · Answer

10223

TuteeHUB · Answer

Error: cannot convert parameter 1 from 'const int **' to 'int **'

1.	What will be the output of the program? #include int fun(int *ptr); int main() { int i=10; const int ptr = &i; fun(&ptr); return 0; } int fun(int *ptr) { int j = 223; int temp = &j; printf("Before changing ptr = %5x\n", ptr); const ptr = temp; printf("After changing ptr = %5x\n", *ptr); return 0; }
A.	Address of iAddress of j
B.	10223
C.	Error: cannot convert parameter 1 from 'const int ' to 'int '
D.	Garbage value
Answer» D. Garbage value

Discussion

No Comment Found

Related MCQs

Reply to Comment